Chapter 9: Problem 46
The initial point for each vector is the origin, and \(\theta\) denotes the angle (measured counterclockwise) from the x-axis to the vector. In each case, compute the horizontal and vertical components of the given vector. (Round your answers to two decimal places.) The magnitude of \(\mathbf{F}\) is \(6.34 \mathrm{N},\) and \(\theta=175^{\circ}\)
Short Answer
Step by step solution
Understand the Vector Components
Calculate Horizontal Component
Calculate Vertical Component
Compile the Results
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Magnitude of a Vector
For the given problem, the magnitude of vector \( \mathbf{F} \) is \( 6.34 \) Newtons (N). Understanding the magnitude is crucial because when decomposing a vector into its components, this length directly influences the sizes of its horizontal and vertical components.
To sum it up:
- Magnitude is the length of the vector.
- It's the same as the length of an arrow representing the vector.
- Affects both the horizontal and vertical components.
Trigonometric Functions
To break down a vector, the cosine function helps find the horizontal component, while sine helps with the vertical. Here’s how it works:
- **Cosine** - If \( \theta \) represents the angle of the vector from the positive x-axis, then the horizontal component, \( F_x \), is given by \( F \cdot \cos(\theta) \).
- **Sine** - Similarly, the vertical component, \( F_y \), is represented by \( F \cdot \sin(\theta) \).
Angle Conversion
\( \text{Radians} = \text{Degrees} \times \frac{\pi}{180} \)
This conversion is crucial because many calculators and mathematical libraries operate with trigonometric functions using radian values. In our problem:
- The angle given was \( 175^{\circ} \).
- Converted to radians as \( 175 \times \frac{\pi}{180} \).
Component Form of a Vector
For vector \( \mathbf{F} \):
- The horizontal component \( F_x \) is found using cosine: \( F \cdot \cos(\theta) \). In the example, we calculated this as approximately \( -6.32 \) N, highlighting that even vectors directed nearly backward have substantial force.
- The vertical component \( F_y \) uses sine: \( F \cdot \sin(\theta) \), giving us \( 0.55 \) N here, representing a small upward force.