Chapter 9: Problem 32
Assume that the vectors \(\mathbf{a}, \mathbf{b}, \mathbf{c},\) and \(\mathbf{d}\) are defined as follows: $$\mathbf{a}=\langle 2,3\rangle \quad \mathbf{b}=\langle 5,4\rangle \quad \mathbf{c}=\langle 6,-1\rangle \quad \mathbf{d}=\langle-2,0\rangle$$ Compute each of the indicated quantities. $$|\mathbf{a}+\mathbf{b}|^{2}+|\mathbf{a}-\mathbf{b}|^{2}-2|\mathbf{a}|^{2}-2|\mathbf{b}|^{2}$$
Short Answer
Step by step solution
Compute \( \mathbf{a} + \mathbf{b} \)
Compute \( \mathbf{a} - \mathbf{b} \)
Compute \(|\mathbf{a} + \mathbf{b}|^{2} \)
Compute \(|\mathbf{a} - \mathbf{b}|^{2} \)
Compute \( 2|\mathbf{a}|^2 \)
Compute \( 2|\mathbf{b}|^2 \)
Combine All Results
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Addition
- First component: \( 2 + 5 = 7 \)
- Second component: \( 3 + 4 = 7 \)
Vector Magnitude
- Calculate: \( \sqrt{7^2 + 7^2} = \sqrt{49 + 49} = \sqrt{98} \)
- The squared magnitude is \( 98 \)
Vector Subtraction
- First component: \( 2 - 5 = -3 \)
- Second component: \( 3 - 4 = -1 \)
Pythagorean Theorem
- \( (-3)^2 + (-1)^2 = 9 + 1 = 10 \)
- \( \sqrt{10} \) gives the length of the vector \( \mathbf{a} - \mathbf{b} \)