/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 6 Answer True or False. You do not... [FREE SOLUTION] | 91Ó°ÊÓ

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Answer True or False. You do not need a calculator for these exercises. Rather, use the fact that e is approximately 2.7 $$e^{3}<27$$

Short Answer

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Step by step solution

01

Understanding the Question

We need to determine if the expression \(e^3 < 27\) is true or false given that \(e\) is approximately \(2.7\).
02

Estimate \(e^3\) Using Approximation

Given \(e \approx 2.7\), we approximate \(e^3\) by raising \(2.7\) to the power of 3: \[2.7^3 = 2.7 \times 2.7 \times 2.7\]
03

Calculate \(2.7^2\)

First, calculate \(2.7^2 = 2.7 \times 2.7 = 7.29\).
04

Calculate \(2.7^3\)

Next, multiply by 2.7 again to find \(2.7^3\):\[7.29 \times 2.7 \approx 19.713\]
05

Compare \(2.7^3\) to 27

We have \(2.7^3 \approx 19.713\). Since \(19.713 < 27\), the statement \(e^3 < 27\) is true.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Natural exponential function
The natural exponential function is a mathematical function denoted by the symbol \( e\). It is one of the most important functions in mathematics and plays a critical role in calculus and complex analysis. The constant \( e\) is an irrational number approximately equal to 2.71828 and serves as the base of natural logarithms.
This function is usually written as \( e^x\), where \( x\) is any real number. It is unique because its derivative is itself, which means the rate of change of the function is equal to the function's value at any point.
  • \( e^0 = 1\)
  • \( e^1 = e \approx 2.718\)
  • The function grows faster than any linear and polynomial function.
Understanding the natural exponential function is crucial as it appears in various mathematical and real-world scenarios, such as calculating compound interest and modeling population growth.
Approximation
In mathematics, approximation is a method used to find estimated values that are close to the exact values of a number, function, or curve. It is particularly useful when working with irrational numbers like \( e\), where precise calculations may be impractical or unnecessary.
When solving problems involving \( e\), it is common to approximate it as 2.7 for convenience. This helps to quickly verify inequalities or relationships without needing exact values.
  • Approximation makes calculations more manageable.
  • It is especially beneficial in situations where only a rough estimate is required.
  • This method simplifies complex arithmetic operations.
For example, in calculating \( e^3\), using the approximate value \( e \approx 2.7\) can easily show how expressions like \( e^3 < 27\) hold true without detailed mathematical computation.
Inequalities
Inequalities are mathematical expressions that state the relative size or order of two values. They are used to compare numbers or algebraic expressions and are commonly found in various problem-solving scenarios.
The inequality \(e^3 < 27\) is an example where you determine if one quantity is less than another.
  • <= represents "less than or equal to"
  • >= represents "greater than or equal to"
  • < represents "less than" and \(>\) represents "greater than"
In the exercise above, we used an approximate value and simple multiplication to check if \( e^3\) is indeed less than 27. This comparison allows us to confirm the inequality statement as true. Dealing with inequalities often involves approximation techniques to simplify and solve them without exhaustive calculations.

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Most popular questions from this chapter

In 1969 the United States National Academy of Sciences issued a report entitled 91Ó°ÊÓ and Man. One conclusion in the report is that a world population of 10 billion "is close to (if not above) the maximum that an intensively managed world might hope to support with some degree of comfort and individual choice." (The figure "10 billion" is sometimes referred to as the carrying capacity of the Earth.) (a) When the report was issued in \(1969,\) the world population was about 3.6 billion, with a relative growth rate of \(2 \%\) per year. Assuming continued exponential growth at this rate, estimate the year in which the Earth's carrying capacity of 10 billion might be reached. (b) Repeat the calculations in part (a) using the following more recent data: In 2000 the world population was about 6.0 billion, with a relative growth rate of \(1.4 \%\) per year. How does your answer compare with that in part (a)?

Use the half-life information to complete each table. (The formula \(\mathcal{N}=\mathcal{N}_{0} e^{k t}\) is not required.) (a) Uranium-228: half-life \(=550\) seconds$$\begin{array}{llllll}t \text { (seconds) } & 0 & 550 & 1100 & 1650 & 2200 \\\\\mathcal{N} \text { (grams) } & 8 & & & \\\\\hline\end{array}$$ (b) Uranium-238: half-life \(=4.9 \times 10^{9}\) years$$\begin{array}{lcccccc}\hline \multirow{2}{*}\begin{array}{l}\text { t (years) } \\\\\mathcal{N} \text { (grams) }\end{array} & \multicolumn{2}{c}0 \\\& \multicolumn{2}{c}10 & 5 & 2.5 & 1.25 & 0.625 \\\\\hline\end{array}$$

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Use the following information on \(p H\) Chemists define pH by the formula pH \(=-\log _{10}\left[\mathrm{H}^{+}\right],\) where [H \(^{+}\) ] is the hydrogen ion concentration measured in moles per liter. For example, if \(\left[\mathrm{H}^{+}\right]=10^{-5},\) then \(p H=5 .\) Solutions with \(a\) pH of 7 are said to be neutral; a p \(H\) below 7 indicates an acid: and a pH above 7 indicates a base. (A calculator is helpful for Exercises 49 and 50.1 A chemist adds some acid to a solution changing the \(\mathrm{pH}\) from 6 to \(4 .\) By what factor does the hydrogen ion concentration change? Note: Lower pH corresponds to higher hydrogen ion concentration.

Solve the inequalities. Where appropriate, give an exact answer as well as a decimal approximation. $$3\left(2-0.6^{x}\right) \leq 1$$

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