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Let \(f(x)=2 x^{2}\) (a) Find \(\frac{f(x)-f(3)}{x-3}\) (b) Find \(\frac{f(x)-f(a)}{x-a}\)

Short Answer

Expert verified
(a) \(2x + 6\); (b) \(2x + 2a\).

Step by step solution

01

Find f(3)

Given the function \(f(x) = 2x^2\), substitute \(x=3\) into the function to find \(f(3)\). \[ f(3) = 2(3)^2 = 2 \times 9 = 18 \]
02

Substitute into Expression for (a)

Use the result from Step 1 to substitute into \(\frac{f(x)-f(3)}{x-3}\). \[ \frac{f(x)-f(3)}{x-3} = \frac{2x^2 - 18}{x-3} \]
03

Simplify Expression for (a)

Factor the numerator, \(2x^2 - 18\), as \(2(x^2 - 9)\). Further factor it as a difference of squares: \[ 2(x^2 - 9) = 2(x-3)(x+3) \] Substitute into the fraction: \[ \frac{2(x-3)(x+3)}{x-3} \]Cancel \((x-3)\) to get \[ 2(x+3) \]
04

Simplify for part (a) result

Expand and simplify the expression. \[ 2(x+3) = 2x + 6 \] Thus, the result for part (a) is \(2x + 6\).
05

Find f(a) for part (b)

Substitute \(x=a\) into \(f(x)\) to get \(f(a)\). \[ f(a) = 2a^2 \]
06

Substitute into Expression for (b)

Substitute \(f(a)\) obtained from Step 5 into the expression \(\frac{f(x)-f(a)}{x-a}\). \[ \frac{f(x)-f(a)}{x-a} = \frac{2x^2 - 2a^2}{x-a} \]
07

Simplify Expression for (b)

Factor the numerator, \(2x^2 - 2a^2\), as \(2(x^2 - a^2)\). Further factor it as a difference of squares: \[ 2(x^2 - a^2) = 2(x-a)(x+a) \] Substitute into the fraction: \[ \frac{2(x-a)(x+a)}{x-a} \]Cancel \((x-a)\) to get \[ 2(x+a) \]
08

Simplify for part (b) result

Expand and simplify the expression. \[ 2(x+a) = 2x + 2a \] Thus, the result for part (b) is \(2x + 2a\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Function Evaluation
In mathematics, function evaluation refers to the process of determining the output of a function for a particular input. Think of it like a machine where you put something in, and something else comes out based on a specific rule.
For example, if we have a function denoted by \( f(x) = 2x^2 \), it means for any value of \( x \), you need to square it first and then multiply the result by 2.

Here's a simple process you can follow when evaluating functions:
  • Identify the function rule: this is the equation that defines the function, such as \( f(x) = 2x^2 \).
  • Substitute the given value of \( x \) into the function. For instance, if \( x = 3 \), you would calculate \( f(3) = 2(3)^2 \).
  • Perform the arithmetic to find the result. In our case, this leads to \( 2 \times 9 = 18 \).
Evaluating functions is a fundamental skill essential for understanding more complex mathematical concepts. It allows you to understand how different inputs affect the outcome of a function.
Through function evaluation, we make mathematical predictions and solve various practical problems.
Simplifying Expressions
Simplifying expressions is an important mathematical skill that involves reducing expressions to their simplest form. This often means combining like terms or factoring. When expressions are simpler, they are easier to work with and understand.
To simplify an expression, follow these steps:
  • Identify like terms: These are the terms with the same variables and powers. For instance, in an expression \(3x + 2x \), both terms are alike because they involve \(x\).
  • Combine like terms: Add or subtract the coefficients of the like terms. For example, \(3x + 2x = 5x\).
  • Factor common terms if possible: Factoring involves rewriting an expression as a product of its factors. For instance, \(2x^2 - 18 \) can be factored as \(2(x^2 - 9)\).
In the exercise provided, simplifying involves not only combining terms but also canceling out terms in a fraction. To simplify \( \frac{2(x-3)(x+3)}{x-3} \), we cancel \( (x-3) \), leaving us with \( 2(x+3) \). Simplification like this is crucial for solving more complex equations efficiently.
Factoring Polynomials
Factoring polynomials is a process used to express a polynomial as the product of simpler polynomials. This is a key concept because it often helps simplify problems and solve equations.
When working on factoring, you'll frequently encounter the difference of squares, especially with quadratic polynomials like \(x^2 - a^2\).
Let's dive into the process of factoring:
  • Identify and factor out the greatest common factor (GCF). For example, in \(2x^2 - 18\), the GCF is 2, so we factor it out: \(2(x^2 - 9)\).
  • Recognize common patterns such as the difference of squares, \(x^2 - a^2 = (x-a)(x+a)\). This makes the factorization simpler.
  • Once factored, these polynomials can be simplified in various expressions, making the overall problem easier to work with.
Correctly factoring a polynomial enables us to simplify expressions like \( \frac{2(x^2 - a^2)}{x-a} \) into \( 2(x+a) \), after canceling common terms. It is a powerful tool in the mathematical toolkit which lays the groundwork for solving higher degree equations.

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Most popular questions from this chapter

In this exercise you will show that if a linear function has an inverse, then the inverse function is also linear. Let \(f(x)=m x+b,\) where \(m\) and \(b\) are constants, with \(m \neq 0\) (a) Show \(f^{-1}\) exists. Hint: Show \(f\) is one-to-one. (b) Find a formula for \(f^{-1}(x)\) (c) Explain why \(f^{-1}\) is linear. In particular, what are the slope and \(y\) -intercept of the graph of \(y=f^{-1}(x) ?\) (d) What happens when \(m=0 ?\)

Use this definition: A prime number is a positive whole number with no factors other than itself and \(1 .\) For example, \(2,13,\) and 37 are primes, but 24 and 39 are not. \(B y\) convention 1 is not considered prime, so the list of the first few primes is as follows: \(2,3,5,7,11,13,17,19,23,29, \ldots\) Let \(f\) be the function that assigns to each natural number \(x\) the number of primes that are less than or equal to \(x .\) For example, \(f(12)=5\) because, as you can easily check, five primes are less than or equal to \(12 .\) Similarly, \(f(3)=2\) because two primes are less than or equal to \(3 .\) Find \(f(8)\) \(f(10),\) and \(f(50)\)

(a) Find the difference quotient \(\frac{f(x)-f(a)}{x-a}\) for each function, as in Example 4. (b) Find the difference quotient \(\frac{f(x+h)-f(x)}{h}\) for each function, as in Example \(5 .\) $$f(x)=1-x^{3}$$

Let \(f(x)=\sqrt{x^{3}+2 x+17}\) and \(g(x)=x+6\) (a) What is the relationship between the graphs of the two functions \(f\) and \(f \circ g ?\) (As in Exercise 21 , the idea here is to answer without looking at the graphs.) (b) Use a graphing utility to check your answer in part (a).

Let \(f(x)=(3 x-4) /(x-3)\). (a) Compute \((f \circ f)(x)\) (b) Find \(f[f(113 / 355)] .\) (Try not to do it the hard way.)

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