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Determine the domain and the range of each function. $$g(x)=\frac{4 x-20}{3 x-18}$$

Short Answer

Expert verified
Domain: \((-\infty, 6) \cup (6, \infty)\); Range: \((-\infty, \frac{4}{3}) \cup (\frac{4}{3}, \infty)\).

Step by step solution

01

Identify the Function Type

The given function is \( g(x) = \frac{4x - 20}{3x - 18} \). This is a rational function where the numerator is a linear expression \( 4x - 20 \) and the denominator is another linear expression \( 3x - 18 \).
02

Determine Domain Restrictions

The domain of a rational function is all real numbers except where the denominator equals zero. To find these restrictions, set the denominator equal to zero and solve for \( x \):\[3x - 18 = 0\]Solve for \( x \):\[3x = 18 \x = 6\]Thus, \( x eq 6 \). Therefore, the domain is all real numbers except \( x = 6 \), written in interval notation as \((-\infty, 6) \cup (6, \infty)\).
03

Determine the Range

The range of a rational function is determined by finding the horizontal asymptote, which affects the range. The horizontal asymptote for a rational function of form \( \frac{ax + b}{cx + d} \) with \( a \) and \( c \) being the coefficients of the highest degree term in the numerator and denominator, respectively, is found by dividing these coefficients: \[y = \frac{4}{3}\]Thus, \( y = \frac{4}{3} \) is a horizontal asymptote. The function approaches but never reaches this value, so the range is all real numbers except \( y = \frac{4}{3} \) and is written as \((-\infty, \frac{4}{3}) \cup (\frac{4}{3}, \infty)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Domain of a Function
The domain of a function defines all the possible input values (or x-values) for which the function is valid. For rational functions, which are expressed in the form \(f(x) = \frac{p(x)}{q(x)}\), where both \(p(x)\) and \(q(x)\) are polynomials, the domain excludes any x-values that make the denominator zero. This is because division by zero is undefined in mathematics.

To find the domain of the function \(g(x) = \frac{4x - 20}{3x - 18}\), we focus on the denominator \(3x - 18\). Set the denominator equal to zero and solve for \(x\):

  • \(3x - 18 = 0\)
  • Solve for \(x\): \(3x = 18\)
  • \(x = 6\)
Thus, \(x = 6\) is not part of the domain, as it would cause division by zero.
The domain of \(g(x)\) is written in interval notation as \((-fty, 6) \cup (6, \infty)\), meaning all real numbers except \(x = 6\).
Range of a Function
The range of a function is the set of all possible output values (or y-values). For rational functions, the range is often influenced by any horizontal asymptotes that the function may have.

In the given function \(g(x) = \frac{4x - 20}{3x - 18}\), the range can be determined by considering its behavior as \(x\) becomes very large or very small. Plus, it’s essential to identify any horizontal asymptotes because they indicate values that \(y\) will approach but never actually reach.

With a rational function of the form \(\frac{ax + b}{cx + d}\), the horizontal asymptote can be found by the leading coefficients of the numerator and the denominator.

  • The horizontal asymptote is \( y = \frac{a}{c} \) or \( y = \frac{4}{3} \)
This asymptote tells us that as \(x\) approaches infinity or negative infinity, the value of the function approaches \(\frac{4}{3}\).
Therefore, the range of \(g(x)\) is \((-fty, \frac{4}{3}) \cup (\frac{4}{3}, fty)\), which means all real numbers except \(y = \frac{4}{3}\).
Horizontal Asymptote
A horizontal asymptote in a function is a horizontal line that the graph of the function approaches as \(x\) goes to positive or negative infinity. For rational functions like \(g(x) = \frac{4x - 20}{3x - 18}\), horizontal asymptotes are determined by comparing the degrees of the polynomials in the numerator and the denominator.

If both polynomials are of the same degree, the horizontal asymptote can be found by dividing the leading coefficients:

  • For \(g(x)\), both the numerator \(4x - 20\) and the denominator \(3x - 18\) have degree 1 (due to the \(x\) term).
  • The horizontal asymptote is given by \( y = \frac{4}{3} \).
This means that no matter how large or small \(x\) becomes, the function will get closer and closer to this y-value, but it won't actually equal \(\frac{4}{3}\).
Understanding horizontal asymptotes is crucial in graphing rational functions because they help describe the behavior of the function at extreme values of \(x\).
For \(g(x)\), the horizontal asymptote \( y = \frac{4}{3} \) guides the range, suggesting that the function's output values will never be \(\frac{4}{3}\).

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Most popular questions from this chapter

Let \(f(x)=2 x+3 .\) Find values for \(a\) and \(b\) such that the equation \(f(a x+b)=x\) is true for all values of \(x\) Hint: Use the fact that if two polynomials (in the variable \(x\) ) are equal for all values of \(x\), then the corresponding coefficients are equal.

Let \(T(x)=2 x^{2}-3 x .\) Find (and simplify) each expression. (a) \(T(x+h)\) (b) \(T(x-h)\) (c) \(T(x+h)-T(x-h)\)

In this exercise you'll investigate the inverse of a composite function. In parts (b) and (c), which involve graphing, be sure to use the same size unit and scale on both axes so that symmetry about the line \(y=x\) can be checked visually. (a) Let \(f(x)=2 x+1\) and \(g(x)=\frac{1}{4} x-3 .\) Compute each of the following: (i) \(f(g(x))\) \(g^{-1}(x)\) (ii) \(g(f(x))\) (v) \(f^{-1}\left(g^{-1}(x)\right)\) (iii) \(f^{-1}(x)\) (vi) \(g^{-1}\left(f^{-1}(x)\right)\) (b) On the same set of axes, graph the two answers that you obtained in (i) and (v) of part (a). Note that the graphs are not symmetric about \(y=x .\) The conclusion here is that the inverse function for \(f(g(x))\) is not \(f^{-1}\left(g^{-1}(x)\right)\) (c) On the same set of axes, graph the two answers that you obtained in (i) and (vi) of part (a); also put the line\(y=x\) into the picture. Note that the two graphs are symmetric about the line \(y=x .\) The conclusion here is that the inverse function for \(f(g(x))\) is \(g^{-1}\left(f^{-1}(x)\right)\) In fact, it can be shown that this result is true in general. For reference, then, we summarize this fact about the inverse of a composite function in the box that follows.

Let \(g(x)=2 x+1 .\) Find \(f(x),\) given that \((g \circ f)(x)=10 x-7\).

Let \(f(x)=\sqrt{x} .\) Find a number \(b\) so that the average rate of change of \(f\) on the interval \([1, b]\) is \(1 / 7\)

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