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For each pair of matrices \(A\) and \(B\) find the following, if defined \- \(3 A\) \- \(-B\) \- \(A^{2}\) \- \(A-2 B\) \- \(A B\) \- \(B A\) $$ A=\left[\begin{array}{l} 7 \\ 8 \\ 9 \end{array}\right], B=\left[\begin{array}{lll} 1 & 2 & 3 \end{array}\right] $$

Short Answer

Expert verified
\(3A = \begin{bmatrix} 21 \\ 24 \\ 27 \end{bmatrix}, -B = \begin{bmatrix} -1 & -2 & -3 \end{bmatrix}, A^2\) undefined, \(A - 2B\) undefined, \(AB = \begin{bmatrix} 7 & 14 & 21 \\ 8 & 16 & 24 \\ 9 & 18 & 27 \end{bmatrix}, BA = [50]\).

Step by step solution

01

Check Dimensions

First, observe the matrices and their dimensions. Matrix \( A \) is a column vector with dimensions \( 3 \times 1 \), and Matrix \( B \) is a row vector with dimensions \( 1 \times 3 \). This information helps determine which operations are defined.
02

Compute Scalar Multiplication \(3A\)

Multiply each element of matrix \( A \) by 3. \[3 A = 3 \begin{bmatrix} 7 \ 8 \ 9 \end{bmatrix} = \begin{bmatrix} 21 \ 24 \ 27 \end{bmatrix}\]
03

Compute Scalar Multiplication \(-B\)

Multiply each element of matrix \( B \) by -1. \[-B = -1 \begin{bmatrix} 1 & 2 & 3 \end{bmatrix} = \begin{bmatrix} -1 & -2 & -3 \end{bmatrix}\]
04

Attempt to Square Matrix \(A\) as \(A^2\)

Matrix \( A \) is \( 3 \times 1 \), making \( A^2 \) undefined since squaring requires that the number of columns in \( A \) equals the number of rows, which is not the case here.
05

Attempt Matrix Subtraction \(A - 2B\)

Compute \( 2B \) first and then attempt \( A - 2B \). \[ 2B = 2 \begin{bmatrix} 1 & 2 & 3 \end{bmatrix} = \begin{bmatrix} 2 & 4 & 6 \end{bmatrix} \] Matrix \( A \) and \( 2B \) have different dimensions (\( 3 \times 1 \) and \( 1 \times 3 \)), so the subtraction is undefined.
06

Attempt Matrix Multiplication \(AB\)

Multiply matrices \( A \) and \( B \):\[AB = \begin{bmatrix} 7 \ 8 \ 9 \end{bmatrix} \begin{bmatrix} 1 & 2 & 3 \end{bmatrix} = \begin{bmatrix} 7 & 14 & 21 \ 8 & 16 & 24 \ 9 & 18 & 27 \end{bmatrix}\] The result is a \( 3 \times 3 \) matrix.
07

Compute Matrix Multiplication \(BA\)

Multiply matrices \( B \) and \( A \):\[BA = \begin{bmatrix} 1 & 2 & 3 \end{bmatrix} \begin{bmatrix} 7 \ 8 \ 9 \end{bmatrix} = \begin{bmatrix} 1 \times 7 + 2 \times 8 + 3 \times 9 \end{bmatrix} = \begin{bmatrix} 50 \end{bmatrix}\] The result is a \( 1 \times 1 \) matrix.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Matrix Dimensions
Understanding matrix dimensions is crucial when working with matrix operations. The dimensions of a matrix are given as rows x columns. In the original exercise, Matrix \( A \) is a column vector with dimensions \( 3 \times 1 \), meaning it has 3 rows and 1 column. Conversely, Matrix \( B \) is a row vector with dimensions \( 1 \times 3 \), having 1 row and 3 columns.

Knowing the dimensions of matrices allows you to determine the feasibility of matrix operations, such as multiplication and addition. For instance:
  • Matrix multiplication \( AB \) is possible if the number of columns in \( A \) matches the number of rows in \( B \).
  • Matrix addition or subtraction requires both matrices to have the same dimensions.

Clearly defining dimensions is the first step before performing operations to ensure all calculations are valid and correctly implementable.
Matrix Scalar Multiplication
Matrix scalar multiplication involves multiplying every element of a matrix by a scalar (a single number). It is a straightforward operation and is always defined, regardless of the matrix dimensions.

In the given exercise, two scalar multiplications are performed:
  • For \( 3A \), each entry of Matrix \( A \) is multiplied by 3: \[3A = 3 \begin{bmatrix} 7 \ 8 \ 9 \end{bmatrix} = \begin{bmatrix} 21 \ 24 \ 27 \end{bmatrix}\]
  • For \(-B\), each entry of Matrix \( B \) is multiplied by -1: \[-B = -1 \begin{bmatrix} 1 & 2 & 3 \end{bmatrix} = \begin{bmatrix} -1 & -2 & -3 \end{bmatrix}\]

This operation effectively scales the matrix by the given amount, affecting all elements in unison.
Matrix Multiplication
Matrix multiplication involves multiplying two matrices to produce a new matrix. It is not as straightforward as scalar multiplication because it requires specific conditions relating to the matrix dimensions.

Matrix multiplication \( AB \) is only valid when the number of columns in the first matrix \( A \) equals the number of rows in the second matrix \( B \).
In our example:
  • Matrix \( A \) is \( 3 \times 1 \) and Matrix \( B \) is \( 1 \times 3 \). Here, multiplication \( AB \) results in a new \( 3 \times 3 \) matrix because the inner dimensions (1 and 1) match. \[AB = \begin{bmatrix} 7 \ 8 \ 9 \end{bmatrix} \begin{bmatrix} 1 & 2 & 3 \end{bmatrix} = \begin{bmatrix} 7 & 14 & 21 \ 8 & 16 & 24 \ 9 & 18 & 27 \end{bmatrix}\]
  • However, when attempting \( A^2 \), it is undefined because \( A \) is a column vector and doesn't have a second dimension equal to its own row count.
The key here is ensuring that the provided matrix dimensions enable valid multiplication.
Matrix Addition and Subtraction
Matrix addition and subtraction involve element-wise operations, meaning you add or subtract corresponding elements from two matrices. However, these operations require the matrices to have identical dimensions.

In the exercise, the operation \( A - 2B \) was attempted. First, \( 2B \) is calculated:
  • \[2B = 2 \begin{bmatrix} 1 & 2 & 3 \end{bmatrix} = \begin{bmatrix} 2 & 4 & 6 \end{bmatrix}\]
However, subtraction involving \( A \) and \( 2B \) is undefined because their dimensions differ - \( A \) is \( 3 \times 1 \) and \( 2B \) is \( 1 \times 3 \).
Always check matrix dimensions before attempting addition or subtraction to confirm the operation is valid.
Vector Operations
Vectors are a type of matrix with either only one row or one column. In this exercise, we worked with one column vector (\( A \)) and one row vector (\( B \)). Vector operations are subject to matrix operation rules.

Since vectors can be considered as simplified matrices, we apply matrix rules similarly. Here:
  • Multiplying a vector by a scalar changes each component of the vector proportionally, just as \( 3A \) did.
  • Adding or subtracting vectors is only possible when both vectors have the same dimensions.
When multiplying a row vector by a column vector (or vice versa), as seen in \( BA \), the result is a single number or a \( 1 \times 1 \) matrix, often called the dot product:\[BA = \begin{bmatrix} 1 & 2 & 3 \end{bmatrix} \begin{bmatrix} 7 \ 8 \ 9 \end{bmatrix} = \begin{bmatrix} 50 \end{bmatrix}\] This simple product involves matching dimensions as with any other matrix multiplication.

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Most popular questions from this chapter

Consider the following definitions. A square matrix is said to be an upper triangular matrix if all of its entries below the main diagonal are zero and it is said to be a lower triangular matrix if all of its entries above the main diagonal are zero. For example,$$ E=\left[\begin{array}{rrr} 1 & 2 & 3 \\\ 0 & 4 & -9 \\ 0 & 0 & -5 \end{array}\right] $$ from Exercises 8 - 21 above is an upper triangular matrix whereas $$ F=\left[\begin{array}{ll} 1 & 0 \\\ 3 & 0 \end{array}\right] $$ is a lower triangular matrix. (Zeros are allowed on the main diagonal.) Discuss the following questions with your classmates. Is the product of two \(n \times n\) lower triangular matrices always lower triangular?

Compute the determinant of the given matrix. (Some of these matrices appeared in Exercises \(1-8\) in Section 8.4.) \(F=\left[\begin{array}{rrr}4 & 6 & -3 \\ 3 & 4 & -3 \\ 1 & 2 & 6\end{array}\right]\)

Consider the following scenario. In the small village of Pedimaxus in the country of Sasquatchia, all 150 residents get one of the two local newspapers. Market research has shown that in any given week, \(90 \%\) of those who subscribe to the Pedimaxus Tribune want to keep getting it, but \(10 \%\) want to switch to the Sasquatchia Picayune. Of those who receive the Picayune, \(80 \%\) want to continue with it and \(20 \%\) want switch to the Tribune. We can express this situation using matrices. Specifically, let \(X\) be the 'state matrix' given by $$ X=\left[\begin{array}{l} T \\ P \end{array}\right] $$ where \(T\) is the number of people who get the Tribune and \(P\) is the number of people who get the Picayune in a given week. Let \(Q\) be the 'transition matrix' given by $$ Q=\left[\begin{array}{ll} 0.90 & 0.20 \\ 0.10 & 0.80 \end{array}\right] $$ such that \(Q X\) will be the state matrix for the next week. If the conditions do not change from week to week, then \(Q\) remains the same and we have what's known as a Stochastic Process \({ }^{10}\) because Week \(n\) 's numbers are found by computing \(Q^{n} X .\) Choose a few values of \(n\) and, with the help of your classmates and calculator, find out how many people get each paper for that week. You should start to see a pattern as \(n \rightarrow \infty\).

Let \(z=a+b i\) and \(w=c+d i\) be arbitrary complex numbers. Associate \(z\) and \(w\) with the matrices $$ Z=\left[\begin{array}{rr} a & b \\ -b & a \end{array}\right] \text { and } W=\left[\begin{array}{rr} c & d \\ -d & c \end{array}\right] $$ Show that complex number addition, subtraction and multiplication are mirrored by the associated matrix arithmetic. That is, show that \(Z+W, Z-W\) and \(Z W\) produce matrices which can be associated with the complex numbers \(z+w, z-w\) and \(z w,\) respectively.

Use the matrices \(A=\left[\begin{array}{ll}1 & 2 \\ 3 & 4\end{array}\right] \quad B=\left[\begin{array}{rr}0 & -3 \\ -5 & 2\end{array}\right] \quad C=\left[\begin{array}{rrr}10 & -\frac{11}{2} & 0 \\ \frac{3}{5} & 5 & 9\end{array}\right]\) \(D=\left[\begin{array}{rr}7 & -13 \\ -\frac{4}{3} & 0 \\\ 6 & 8\end{array}\right] \quad E=\left[\begin{array}{rrr}1 & 2 & 3 \\ 0 & 4 & -9 \\ 0 & 0 & -5\end{array}\right]\) to compute the following or state that the indicated operation is undefined. $$ A^{2}-B^{2} $$

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