/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 30 Let \(z=a+b i\) and \(w=c+d i\) ... [FREE SOLUTION] | 91Ó°ÊÓ

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Let \(z=a+b i\) and \(w=c+d i\) be arbitrary complex numbers. Associate \(z\) and \(w\) with the matrices $$ Z=\left[\begin{array}{rr} a & b \\ -b & a \end{array}\right] \text { and } W=\left[\begin{array}{rr} c & d \\ -d & c \end{array}\right] $$ Show that complex number addition, subtraction and multiplication are mirrored by the associated matrix arithmetic. That is, show that \(Z+W, Z-W\) and \(Z W\) produce matrices which can be associated with the complex numbers \(z+w, z-w\) and \(z w,\) respectively.

Short Answer

Expert verified
Matrix addition, subtraction, and multiplication correspond to complex number operations.

Step by step solution

01

Matrix Association of Addition

The complex number addition \( z + w \) is given by \((a + bi) + (c + di) = (a+c) + (b+d)i \). The matrix representation of this number is:\\[ Z + W = \begin{bmatrix} a & b \ -b & a \end{bmatrix} + \begin{bmatrix} c & d \ -d & c \end{bmatrix} \]\Adding the matrices component-wise, we get:\\[ Z + W = \begin{bmatrix} a+c & b+d \ -(b+d) & a+c \end{bmatrix} \]\This matrix represents the complex number \((a+c) + (b+d)i\) which corresponds to \(z+w\).
02

Matrix Association of Subtraction

The complex number subtraction \( z - w \) is given by \((a + bi) - (c + di) = (a-c) + (b-d)i \). Its matrix representation is:\\[ Z - W = \begin{bmatrix} a & b \ -b & a \end{bmatrix} - \begin{bmatrix} c & d \ -d & c \end{bmatrix} \]\Performing matrix subtraction component-wise results in:\\[ Z - W = \begin{bmatrix} a-c & b-d \ -(b-d) & a-c \end{bmatrix} \]\This matrix corresponds to the complex number \((a-c) + (b-d)i\), which matches \(z-w\).
03

Matrix Association of Multiplication

For multiplication, the complex number \( z \cdot w \) is \((a+bi)(c+di) = (ac-bd) + (ad+bc)i \). The matrix product is:\\[ZW = \begin{bmatrix} a & b \ -b & a \end{bmatrix} \times \begin{bmatrix} c & d \ -d & c \end{bmatrix} = \begin{bmatrix} ac-bd & ad+bc \ -(ad+bc) & ac-bd \end{bmatrix}\]\This resulting matrix represents the complex number \((ac-bd) + (ad+bc)i\), which corresponds to the multiplication \(z \cdot w\).
04

Conclusion

By showing the results of matrix operations \(Z+W\), \(Z-W\), and \(ZW\) are representable as complex numbers \(z+w\), \(z-w\), and \(z\cdot w\) respectively, we have established that the operations on these matrices reflect the operations on their associated complex numbers.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Matrix Representation
When dealing with complex numbers, associating them with matrices can provide a more visual and structured approach, especially for operations like addition, subtraction, and multiplication. If we have complex numbers expressed as \( z = a + bi \) and \( w = c + di \), they can be translated into matrices:
- For \( z \), the matrix is \( Z = \begin{bmatrix} a & b \ -b & a \end{bmatrix} \). - Similarly, for \( w \), it becomes \( W = \begin{bmatrix} c & d \ -d & c \end{bmatrix} \).
These matrices help in straightforward visualization of how complex number operations work. The entries in these matrices are chosen so that the addition, subtraction, and multiplication reflect operations on the original complex numbers. This matrix representation maintains the properties needed to correctly perform and simplify these operations, as matrix arithmetic parallels the properties of complex numbers.
Complex Addition
Complex addition involves combining the real parts and the imaginary parts of two complex numbers. For example, if you have \( z = a + bi \) and \( w = c + di \), then the addition \( z + w \) results in \( (a+c) + (b+d)i \).
Translated to matrices, this operation is also straightforward. Using our given matrices \( Z \) and \( W \):
- Compute the sum by adding corresponding elements: \[ Z + W = \begin{bmatrix} a & b \ -b & a \end{bmatrix} + \begin{bmatrix} c & d \ -d & c \end{bmatrix} = \begin{bmatrix} a+c & b+d \ -(b+d) & a+c \end{bmatrix} \]
This matrix representation directly corresponds to the complex number \((a+c) + (b+d)i\), ensuring the parallelism between matrix and complex arithmetic.
Complex Subtraction
In complex subtraction, we simply subtract the corresponding real and imaginary parts of the numbers involved. For complexity numbers \( z = a + bi \) and \( w = c + di \), the subtraction \( z - w \) yields \( (a-c) + (b-d)i \).
Matrix subtraction follows a similar rule, making use of the matrix representations \( Z \) and \( W \):
- Perform element-wise subtraction: \[ Z - W = \begin{bmatrix} a & b \ -b & a \end{bmatrix} - \begin{bmatrix} c & d \ -d & c \end{bmatrix} = \begin{bmatrix} a-c & b-d \ -(b-d) & a-c \end{bmatrix} \]
This mirrors the complex number \((a-c) + (b-d)i\), matching precisely the approach used for complex numbers.
Complex Multiplication
Complex multiplication can be a bit more intricate, involving the distribution of terms and combining them according to imaginary unit rules. For two complex numbers \( z = a + bi \) and \( w = c + di \), the multiplication \( z \cdot w \) results in \( (ac-bd) + (ad+bc)i \).
In matrix form, the operation involves multiplying the matrices \( Z \) and \( W \):
- Apply matrix multiplication rules: \[ ZW = \begin{bmatrix} a & b \ -b & a \end{bmatrix} \times \begin{bmatrix} c & d \ -d & c \end{bmatrix} = \begin{bmatrix} ac-bd & ad+bc \ -(ad+bc) & ac-bd \end{bmatrix} \]
The resulting matrix encodes the same complex number result \((ac-bd) + (ad+bc)i\), validating the consistency and unity between matrix and complex number multiplications. This approach underscores the concept of seamlessly integrating matrix operations with complex arithmetic.

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Most popular questions from this chapter

In Exercises \(23-29,\) consider the following scenario. In the small village of Pedimaxus in the country of Sasquatchia, all 150 residents get one of the two local newspapers. Market research has shown that in any given week, \(90 \%\) of those who subscribe to the Pedimaxus Tribune want to keep getting it, but \(10 \%\) want to switch to the Sasquatchia Picayune. Of those who receive the Picayune, \(80 \%\) want to continue with it and \(20 \%\) want switch to the Tribune. We can express this situation using matrices. Specifically, let \(X\) be the 'state matrix' given by $$ X=\left[\begin{array}{l} T \\ P \end{array}\right] $$ where \(T\) is the number of people who get the Tribune and \(P\) is the number of people who get the Picayune in a given week. Let \(Q\) be the 'transition matrix' given by $$ Q=\left[\begin{array}{ll} 0.90 & 0.20 \\ 0.10 & 0.80 \end{array}\right] $$ such that \(Q X\) will be the state matrix for the next week. Let's assume that when Pedimaxus was founded, all 150 residents got the Tribune. (Let's call this Week \(0 .)\) This would mean $$ X=\left[\begin{array}{r} 150 \\ 0 \end{array}\right] $$ Since \(10 \%\) of that 150 want to switch to the Picayune, we should have that for Week 1, 135 people get the Tribune and 15 people get the Picayune. Show that \(Q X\) in this situation is indeed $$ Q X=\left[\begin{array}{r} 135 \\ 15 \end{array}\right] $$

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