Chapter 2: Problem 62
You are given a line and a point which is not on that line. Find the line parallel to the given line which passes through the given point. \(y=\frac{4-x}{3}, P(1,-1)\)
Short Answer
Expert verified
The equation of the parallel line is \(y = -\frac{1}{3}x - \frac{2}{3}\).
Step by step solution
01
Identify the Slope of the Given Line
Start by rewriting the equation of the given line in slope-intercept form, which is \(y=mx+b\). The given line is \(y=\frac{4-x}{3}\). Rewrite it by separating the terms: \(y = -\frac{1}{3}x + \frac{4}{3}\). From this, you can identify that the slope \(m\) of the line is \(-\frac{1}{3}\).
02
Use the Same Slope for the Parallel Line
Since parallel lines have the same slope, the line parallel to the given line will also have a slope \(-\frac{1}{3}\). Therefore, the equation of the parallel line will have the form \(y = -\frac{1}{3}x + b\), where \(b\) is the y-intercept to be determined.
03
Substitute the Point into the Line Equation
Substitute the given point \(P(1, -1)\) into the equation to find \(b\). Replace \(x\) with 1 and \(y\) with -1 in \(y = -\frac{1}{3}x + b\). Thus, \(-1 = -\frac{1}{3} \times 1 + b\).
04
Solve for the Y-intercept \(b\)
Solve the equation from the previous step: \(-1 = -\frac{1}{3} + b\). Add \(\frac{1}{3}\) to both sides to isolate \(b\): \(-1 + \frac{1}{3} = b\). Convert \(-1\) to \(-\frac{3}{3}\) to facilitate the addition: \(-\frac{3}{3} + \frac{1}{3} = b\), which simplifies to \(-\frac{2}{3} = b\).
05
Write the Equation of the Parallel Line
Now that we have both the slope and the y-intercept, we can write the equation of the line parallel to the given line that passes through \(P(1, -1)\): \(y = -\frac{1}{3}x - \frac{2}{3}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Slope-Intercept Form
The Slope-Intercept Form is a widely used equation format for straight lines and is written as \(y = mx + b\). This formula is extremely helpful because it immediately gives us two key pieces of information:
- Slope (\(m\)): This tells us the angle or steepness of the line
- Y-intercept (\(b\)): This is where the line crosses the y-axis
Slope of a Line
The slope of a line is a measure of its steepness and is often represented by the letter \(m\). The slope indicates the degree to which the line inclines or declines.
- If the slope is positive, the line rises as it moves from left to right.
- If the slope is negative, the line falls as it moves from left to right.
- If the slope is zero, the line is horizontal.
- If the slope is undefined, the line is vertical.
Y-intercept
The y-intercept of a line is the point where the line crosses the y-axis. It is embodied by the term \(b\) in the slope-intercept equation \(y = mx + b\). This is a very useful piece of information because it defines a starting point for our line, or where it "begins" on the graph.In the example, the y-intercept of the original line \(y = -\frac{1}{3}x + \frac{4}{3}\) is \(\frac{4}{3}\). This tells us that the line crosses the y-axis at a vertical position of \(\frac{4}{3}\). Understanding the y-intercept helps in constructing and visualizing the complete line when combined with the slope.
Equation of a Line
The equation of a line succinctly describes its direction and position on the coordinate plane. There are several ways to represent this, but the Slope-Intercept Form \(y = mx + b\) is often the most convenient.Having both the slope and y-intercept enables us to write this equation simply. For instance, to find a line parallel to another, we adhere to the rule that parallel lines share the same slope. So if we know a parallel line's slope, we need only one point that the new line passes through to find \(b\), our y-intercept.In our problem, after calculating the correct y-intercept using the point \(P(1, -1)\), we arrive at the final equation \(y = -\frac{1}{3}x - \frac{2}{3}\). This line runs parallel to our original line and passes through a specific point, demonstrating how equations can be manipulated to achieve desired line attributes.