Chapter 2: Problem 34
For the following exercises, given each set of information, find a linear equation satisfying the conditions, if possible. Passes through \((-1,4)\) and \((5,2)\)
Short Answer
Expert verified
The linear equation is \(y = -\frac{1}{3}x + \frac{11}{3}\).
Step by step solution
01
Identify Given Points
The problem provides two points through which the linear equation must pass: \((-1, 4)\) and \((5, 2)\). These points are in the format \((x_1, y_1)\) and \((x_2, y_2)\), respectively.
02
Calculate the Slope
The slope \(m\) of a line passing through two points \((x_1, y_1)\) and \((x_2, y_2)\) is calculated using the formula \(m = \frac{y_2 - y_1}{x_2 - x_1}\). Substituting in our points, we have:\[m = \frac{2 - 4}{5 - (-1)} = \frac{-2}{6} = -\frac{1}{3}.\]
03
Use Point-Slope Form
Now that we have the slope, we can use the point-slope form of a linear equation: \(y - y_1 = m(x - x_1)\). Using the point \((-1, 4)\), the equation becomes:\[y - 4 = -\frac{1}{3}(x + 1).\]
04
Simplify to Slope-Intercept Form
Simplify the equation from the point-slope form to the slope-intercept form \(y = mx + b\):1. Expand the right-hand side: \[y - 4 = -\frac{1}{3}x - \frac{1}{3}.\]2. Add 4 to both sides: \[y = -\frac{1}{3}x - \frac{1}{3} + 4.\]3. Combine like terms: \[y = -\frac{1}{3}x + \frac{11}{3}.\]
05
Verify the Equation
Ensure the equation \(y = -\frac{1}{3}x + \frac{11}{3}\) satisfies both points. Substitute \((-1, 4)\):For \(x = -1\):\[y = -\frac{1}{3}(-1) + \frac{11}{3} = \frac{1}{3} + \frac{11}{3} = \frac{12}{3} = 4.\]Substitute \((5, 2)\):For \(x = 5\):\[y = -\frac{1}{3}(5) + \frac{11}{3} = -\frac{5}{3} + \frac{11}{3} = \frac{6}{3} = 2.\]Both points satisfy the equation.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Point-Slope Form
A critical tool in linear algebra is the point-slope form of a linear equation. The point-slope form is particularly useful when you know a point on the line and the slope of the line. This formula is expressed as:\[ y - y_1 = m(x - x_1) \]where:
By using the point-slope form, one can also assess how changes in slope or point affect the equation of a line.
- \((x_1, y_1)\) represents a known point on the line.
- \(m\) is the slope of the line.
By using the point-slope form, one can also assess how changes in slope or point affect the equation of a line.
Slope-Intercept Form
The slope-intercept form is one of the most common ways to express the equation of a line. This form is very intuitive and is given by:\[ y = mx + b \]Where:
This form is exceptionally handy for graphing, as knowing \(m\) and \(b\) allows you to plot the line with ease by simply starting at the y-intercept and using the slope to determine the direction and steepness of the line.
- \(m\) is the slope of the line, providing insight into how steep the line is. It shows how much \(y\) changes for a unit change in \(x\).
- \(b\) is the y-intercept, which is the value where the line crosses the y-axis.
This form is exceptionally handy for graphing, as knowing \(m\) and \(b\) allows you to plot the line with ease by simply starting at the y-intercept and using the slope to determine the direction and steepness of the line.
Slope Calculation
Finding the slope of a line is fundamental in understanding the direction and steepness of the line in a cartesian plane. The slope, often denoted as \(m\), is calculated using the formula:\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]Here's how to understand this equation:
- \((x_1, y_1)\) and \((x_2, y_2)\) are two points on the line.
- The numerator \((y_2 - y_1)\) represents the vertical change, or how much \(y\) changes between the two points.
- The denominator \((x_2 - x_1)\) represents the horizontal change, or how much \(x\) changes between the two points.