Chapter 7: Problem 38
Graph equation. \(r=3 \sin \theta\)
Short Answer
Expert verified
The graph of \(r=3 \sin \theta\) is a circle centered at \((0, \frac{3}{2})\) with a diameter of 3.
Step by step solution
01
Understand the Equation Type
The equation given is in polar coordinates, which are represented in the form of \( r = f(\theta) \). In this case, \(r = 3 \sin \theta\). This describes a curve where the radius \(r\) changes depending on the angle \(\theta\).
02
Recall the Shape for Sine-based Polar Equations
For equations of the form \(r = a \sin \theta\), the graph is typically a circle. Specifically, when \(a\) is positive, the circle is symmetric about the vertical axis (the y-axis in Cartesian coordinates). Here, \(a\ = 3\). This indicates the presence of a circle.
03
Determine the Circle's Characteristics
Given \(r = 3 \sin \theta\), identify the maximum value of \(\sin \theta\), which is \(1\). Thus, the maximum radius \(r\) is 3. The minimum when \(\sin \theta = 0\) is \(r = 0\). This confirms that the circle's diameter is 3 and it is centered at \((0, \frac{3}{2})\) in Cartesian coordinates.
04
Sketch the Graph
Draw a circle centered at \((0, \frac{3}{2})\) on the polar plane. Since the function involves \(\sin\), the circle is oriented vertically. The radius being \(3/2\) means the circle will stretch from the pole (origin) to a full extent vertically along the initial line (y-axis). Its diameter is vertically positioned from \(\theta = \frac{\pi}{2}\) to \(-\frac{\pi}{2}\).
05
Verify Symmetry and Features
Double-check the shape: It should be circular, symmetric about the vertical axis. This confirms our derivation: The circle's radius extends up to 3 along the vertical axis, and passes through the origin with its bottom-most point at \((0, 0)\) when \(\theta = 0\ or \theta = \pi\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sine Function
The sine function, represented as \( \sin \theta \), is a fundamental trigonometric function that oscillates between -1 and 1. In the context of polar coordinates, it plays a critical role in determining the radius \( r \) based on the angle \( \theta \). This is evident in the polar equation \( r = 3 \sin \theta \). Here, the sine function modifies the radius as \( \theta \) changes:
- When \( \sin \theta = 1 \), the radius \( r \) is at its maximum of 3.
- When \( \sin \theta = 0 \), the radius \( r \) is zero.
Circle Graphing
In polar coordinates, graphing a circle is more straightforward if you know the equation's form. A sine-based polar equation like \( r = 3 \sin \theta \) typically results in a circular graph. To graph a circle from this equation:
- Identify that the function involves a sine term, indicating a circular shape oriented in a specific direction.
- Recognize that the maximum value of the equation determines the circle's diameter. Here, \( a = 3 \) means the diameter is 3.
Symmetry in Polar Graphs
Symmetry is an essential aspect when analyzing and graphing polar equations. The given equation, \( r = 3 \sin \theta \), shows a specific symmetry, allowing for easier graph interpretation.
- Because the equation involves \( \sin \theta \) and the coefficient 3 is positive, the symmetry is about the vertical axis or y-axis.
- This line of symmetry simplifies the process of determining how \( r \) varies since you know the graph should mirror itself across this axis.