Chapter 7: Problem 38
Find all \(n\) th roots of \(z\). Write the answers in polar form, and plot the roots in the complex plane. $$4 \sqrt{2}+4 \sqrt{2} i, n=3$$
Short Answer
Expert verified
The 3rd roots are \(2 \text{cis} \frac{\pi}{12}\), \(2 \text{cis} \frac{3\pi}{4}\), and \(2 \text{cis} \frac{17\pi}{12}\).
Step by step solution
01
Convert to Polar Form
The complex number given is \(4\sqrt{2} + 4\sqrt{2} i\). First, find the modulus \(r\) of the complex number:\[ r = \sqrt{(4\sqrt{2})^2 + (4\sqrt{2})^2} = \sqrt{32 + 32} = \sqrt{64} = 8\]Next, determine the argument \(\theta\) using \( \tan \theta = \frac{\text{Imaginary part}}{\text{Real part}} = 1 \):\[\theta = \frac{\pi}{4} + 2k\pi \quad \text{for some integer } k\]Thus, the polar form is \(8 \text{cis} \frac{\pi}{4}\).
02
Apply De Moivre's Theorem
Use De Moivre's Theorem to find the 3rd roots of the complex number in polar form \( r \text{cis} \theta \). For this, the 3 roots are given by:\[z_k = \sqrt[3]{r} \text{cis} \left(\frac{\theta + 2k\pi}{3}\right)\]where \( k = 0, 1, 2 \).
03
Calculate the Modulus of the Roots
Calculate \(\sqrt[3]{r}\):\[\sqrt[3]{8} = 2\]So each root will have the modulus 2.
04
Find the Angles for Each Root
Substitute \(\theta = \frac{\pi}{4}\) and \( r = 8 \):- For \(k=0\):\[\theta_0 = \frac{\pi}{12}\]- For \(k=1\):\[\theta_1 = \frac{\pi}{12} + \frac{2\pi}{3} = \frac{9\pi}{12} = \frac{3\pi}{4}\] - For \(k=2\):\[\theta_2 = \frac{\pi}{12} + \frac{4\pi}{3} = \frac{17\pi}{12}\]
05
Write the Roots in Polar Form
Using the moduli and angles calculated, write the roots as:\[z_0 = 2 \text{cis} \frac{\pi}{12}\]\[z_1 = 2 \text{cis} \frac{3\pi}{4}\]\[z_2 = 2 \text{cis} \frac{17\pi}{12}\]
06
Plot the Roots on the Complex Plane
To plot these on the complex plane, each root can be represented as a point at - a distance of 2 units from the origin- forming angles \(\frac{\pi}{12}\), \(\frac{3\pi}{4}\), and \(\frac{17\pi}{12}\) with the positive real axis.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
De Moivre's Theorem
De Moivre's Theorem is a powerful tool in the field of complex numbers. It helps us find the powers and roots of complex numbers when they're expressed in polar form. The theorem is given by:
Polar Form of Complex Numbers
The polar form provides an alternative way to represent complex numbers, complementing the more familiar rectangular form \( a + bi \). In polar form, a complex number is expressed as:
- \( z = r(\cos \theta + i \sin \theta) \)
- Alternatively written as \( z = r \text{cis} \theta \)
- The modulus \( r \) represents the distance from the origin to the point \( (a, b) \) in the complex plane.
- The argument \( \theta \) is determined using inverse trigonometric functions, like \( \tan^{-1}(b/a) \).
Complex Plane
The complex plane is a two-dimensional plane used to visualize complex numbers. Think of it as an extension of the conventional XY-plane, but designed for complex numbers. It's constructed by:
- Representing the real part along the horizontal axis (real axis).
- Placing the imaginary part along the vertical axis (imaginary axis).
- Distance from the origin is the modulus \( r = \sqrt{a^2 + b^2} \).
- Angle from the positive real axis is the argument \( \theta \).