/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 Plot the graph of the given equa... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Plot the graph of the given equation. $$\frac{x^{2}}{4}+\frac{y^{2}}{9}=1$$

Short Answer

Expert verified
The graph is an ellipse centered at the origin with vertices at \((0, 3)\), \((0, -3)\), \((2, 0)\), and \((-2, 0)\).

Step by step solution

01

Identify the Equation Type

The equation \(\frac{x^2}{4} + \frac{y^2}{9} = 1\) is in the standard form of the equation of an ellipse, \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\). We recognize this because it involves squared terms of \(x\) and \(y\) being equal to 1.
02

Determine the Ellipse Parameters

For the given equation \(\frac{x^2}{4} + \frac{y^2}{9} = 1\), identify \(a^2 = 4\) and \(b^2 = 9\). Thus, \(a = 2\) and \(b = 3\). Since \(b > a\), the ellipse is vertical, with the longer axis (major axis) being along the y-axis.
03

Locate the Center

The ellipse equation is centered at the origin (0,0) because the equation does not have terms involving \(x-h\) or \(y-k\). Therefore, the center is \((0,0)\).
04

Find the Vertices

Since it is a vertical ellipse, the vertices are given by the points \((0, \pm b)\) and \((\pm a, 0)\). Substituting the values of \(a\) and \(b\), the vertices are \((0, 3)\), \((0, -3)\), \((2, 0)\), and \((-2, 0)\).
05

Plot the Ellipse

Plot the points obtained from the vertices on a coordinate plane and sketch the ellipse shape, keeping in mind that the curve passes through these points, with the ends extending along the x-axis to \(\pm 2\) and along the y-axis to \(\pm 3\). The ellipse is symmetrical about both the x-axis and y-axis.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conic Sections
Conic sections are fundamental shapes that emerge from the intersection of a plane with a cone. These shapes are highly significant in mathematics and include ellipses, circles, parabolas, and hyperbolas.
Each type of conic section features distinct properties and equations. These sections form the basis for understanding complex geometric figures and real-life structures.
In terms of equations:
  • A circle is a special type of ellipse where the two axes are equal.
  • An ellipse has an equation of the form \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\).
  • A parabola is represented by an equation such as \(y^2 = 4ax\).
  • A hyperbola could be written as \(\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\).
Understanding conic sections allows mathematicians to explore a range of phenomena, from planetary orbits (ellipses) to satellite dishes (parabolas) and more.
Graphing Ellipses
When graphing ellipses, it is essential to recognize their symmetry and shape. The equation \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\) guides us in plotting the curve correctly. Each ellipse consists of two axes: the major axis and the minor axis.
The major axis is the longer one, and it can be either vertical or horizontal, while the minor axis is perpendicular to it.
For graphing an ellipse, you should:
  • Identify the center, which in the standard form \(\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1\) is at \(h, k\).
  • Determine whether it is wider or taller by comparing \(a\) and \(b\).
  • Plot the vertices, which define the ends of both axes.
  • Sketch the curve ensuring it is smooth and symmetrical about both axes.
In \(\frac{x^2}{4} + \frac{y^2}{9} = 1\), the vertical major axis indicates that the ellipse is stretched taller than it is wide.
Standard Form of an Ellipse
The standard form for the equation of an ellipse is a simple way to describe its shape and features precisely. The general standard form is \(\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1\). In this formula:
  • h and \(k\) are coordinates of the center.
  • \(a^2\) and \(b^2\) are the squares of the semi-major and semi-minor axes lengths.
  • The ellipse is horizontal if \(a > b\) and vertical if \(b > a\).
This form provides a straightforward method to derive the ellipse's features and enables easy graphing and analysis.
In the original equation \(\frac{x^2}{4} + \frac{y^2}{9} = 1\), \(a^2 = 4\) and \(b^2 = 9\), meaning that the ellipse is centered at \(0,0\) with the center of the ellipse at the origin.
Vertices of an Ellipse
The vertices of an ellipse are crucial points that describe its extremities and help to define its principal axes. For an ellipse centered at \(h, k\), its vertices are given by two sets of coordinates:
  • \((h \pm a, k)\) parallel to the x-axis if it is a horizontal ellipse
  • \((h, k \pm b)\) parallel to the y-axis if it is a vertical ellipse
Vertices indicate the farthest points of the ellipse along its major axis.
In the exercise \(\frac{x^2}{4} + \frac{y^2}{9} = 1\), the vertices are \(0, \pm 3\) and \(\pm 2, 0\), suggesting that the ellipse is taller with its major axis aligned with the y-axis.
Understanding vertices helps in accurately sketching the ellipse and comprehending its dimensions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Determine whether each statement is true or false. If a line has slope equal to zero, describe a line that is perpendicular to it.

Refer to the following: Einstein's special theory of relativity states that time is relative: Time speeds up or slows down, depending on how fast one object is moving with respect to another. For example, a space probe traveling at a velocity \(v\) near the speed of light \(c\) will have "clocked" a time \(t\) hours, but for a stationary observer on Earth that corresponds to a time \(t_{0} .\) The formula governing this relativity is given by $$ t=t_{0} \sqrt{1-\frac{v^{2}}{c^{2}}} $$ If the time elapsed on a space probe mission is 5 years but the time elapsed on Earth during that mission is 30 years, how fast is the space probe traveling? Give your answer relative to the speed of light.

The average temperature for Boston in January 2005 was 43 "F. In 2007 the average January temperature was \(44.5^{\circ} \mathrm{F}\). What is the rate of change of the temperature per year? If this trend continues, what is the expected average temperature in January \(2010 ?\)

The value of a Daewoo car is given by \(y=11,100-1850 x, x \geq 0,\) where \(y\) is the value of the car and \(x\) is the age of the car in years. Find the \(x\) -intercept and \(y\) -intercept and interpret the meaning of each.

Explain the mistake that is made. Given the slope, classify the line as rising, falling, horizontal, or vertical. a. \(m=0\) b. \(m\) undefined c. \(m=2\) d. \(m=-1\) Solution: a. vertical line b. horizontal line c. rising d. falling These are incorrect. What mistakes were made?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.