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Solve using the square root method. $$(x-3)^{2}=36$$

Short Answer

Expert verified
The solutions are \(x = 9\) and \(x = -3\).

Step by step solution

01

Apply the Square Root Property

The square root method implies taking the square root of both sides of the equation. Start with \((x-3)^2 = 36\). When you take the square root of \((x-3)^2\), you get \(x-3\). The square root of 36 is \(6\), but remember, it can be either positive or negative, so we have two cases to consider: \(x-3=6\) and \(x-3=-6\).
02

Solve for x in the First Case

For the first case, solve \(x-3=6\). Add 3 to both sides to isolate \(x\): \(x = 6 + 3\). This simplifies to \(x = 9\).
03

Solve for x in the Second Case

For the second case, solve \(x-3=-6\). Add 3 to both sides to isolate \(x\): \(x = -6 + 3\). This simplifies to \(x = -3\).
04

Interpret the Solutions

The solutions to the equation \((x-3)^2 = 36\) are \(x = 9\) and \(x = -3\). This means there are two possible values for \(x\) that satisfy the equation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solving Quadratic Equations
Quadratic equations often take the form \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are constants. Solving these equations can be achieved through several methods, including factoring, the quadratic formula, completing the square, and the square root method.

When using methods like factoring or the quadratic formula, more computation and steps are involved. However, for special cases such as \((x-a)^2 = k\), like the example \((x-3)^2 = 36\), the square root method is particularly efficient. This is because we can directly apply the square root to both sides to simplify the equation more quickly.
  • Factoring involves rewriting the quadratic as a product of binomials.
  • The quadratic formula solves for \(x\) using \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\).
  • Completing the square involves rearranging and adjusting the equation into a perfect square trinomial.
  • Square root method is most useful when dealing with perfect square forms.
These strategies help in finding solutions to quadratic equations efficiently based on the form of the equation.
Square Root Property
The square root property is pivotal in solving equations that are already in a perfect square form, such as \((x-a)^2 = k\). When you have an equation in this form, you can directly apply the square root to both sides of the equation.

By doing this, you simplify the equation significantly. So, for \((x-3)^2 = 36\), taking the square root gives \(x-3 = \pm 6\). The square root property acknowledges that a number's square root can be either positive or negative.
  • Always consider both positive and negative roots, unless other aspects of the problem specify otherwise.
  • This property directly yields linear equations from what were quadratic expressions.
  • Simplifies the process by reducing the problem to a simpler equation.
The square root property cuts down the usually lengthy process of solving quadratics by focusing on a direct and quick approach.
Isolation of Variables
Isolation of variables is a technique used to solve an equation by getting the unknown variable by itself on one side of the equation. In our context, usually after applying the square root property, we use isolation of variables to determine specific solutions for \(x\).

For instance, when solving \(x-3 = 6\) and \(x-3 = -6\), you add 3 to each side to get \(x\) alone. This gives you \(x = 9\) and \(x = -3\).
  • This technique ensures clarity and simplicity as you continue to isolate \(x\) throughout the equation steps.
  • Makes solutions straightforward by iteratively applying operations that simplify the expression.
  • When dealing with equations, always perform the same operation on both sides to maintain equality.
Isolation of variables is a fundamental tool that, when combined with the square root property, efficiently solves equations like \((x-3)^2 = 36\).

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