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Pre-algebra

Ron Larson, Laurie Boswell, Timothy D. Kanold, Lee Stiff

$Math Studyset 91影视 Explanations$ Math

Common Core Edition 路 183 pages

ISBN: 9780547587776

Chapter 9: Q. 52 (page 480)

Solve the equation. Round to the nearest tenth if necessary.
$200 = 16 t^{2}$

Short Answer

Expert verified

The solution of the is $t = 3.5$ .

Step by step solution

01

Step 1. Given Information.

The given equation is

$16 t^{2} = 200$

02

Step 2. Calculation.

The solution of the given equation will be

$\begin{matrix} 16 t^{2} = 200 \\ t^{2} = \frac{200}{16} \\ t^{2} = 12.5 \\ t = {(12.5)}^{\frac{1}{2}} \end{matrix}$

On further simplification,

$\begin{matrix} t = 3.5355 \\ t 鈮� 3.5 \end{matrix}$

03

Step 3. Conclusion.

The solution is $t = 3.5$ .

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Most popular questions from this chapter

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