91Ó°ÊÓ

A computer generates an integer from 1 to 10.

Probability:

$\text{P}=\frac{\text{favorable} \text{outcomes}}{\text{total} \text{outcomes}}$

To calculate the probability of getting even number, there are 10 total outcomes. It is needed to calculate favourable outcomes.

$\begin{array}{l}\text{´Ú²¹±¹´Ç³Ü°ù²¹²ú±ô±ð o³Ü³Ù³¦´Ç³¾±ð²õ}=\left\{2,4,6,8,10\right\}\\ =5\end{array}$

Therefore, the probability of getting even number is obtained as,

$\begin{array}{c}\text{P}\left(\text{´Ç´Ú g±ð³Ù³Ù¾±²Ô²µ±ð±¹±ð²Ô²Ô³Ü³¾²ú±ð°ù}\right)=\frac{\text{´Ú²¹±¹´Ç°ù²¹²ú±ô±ð â¶Ä„o³Ü³Ù³¦´Ç³¾±ð}}{\text{³Ù´Ç³Ù²¹±ô â¶Ä„o³Ü³Ù³¦´Ç³¾±ð}}\\ \text{P}\left(\text{´Ç´Ú g±ð³Ù³Ù¾±²Ô²µ±ð±¹±ð²Ô²Ô³Ü³¾²ú±ð°ù}\right)=\frac{5}{10}\\ =\frac{1}{2}\end{array}$

Therefore, the probability of getting even number is $\frac{1}{2}$.

Multiply $\frac{1}{2}$ by 100% to convert the fraction form in percent.

$\begin{array}{c}\text{P}\left(\text{´Ç´Ú g±ð³Ù³Ù¾±²Ô²µ±ð±¹±ð²Ô²Ô³Ü³¾²ú±ð°ù}\right)=\frac{1}{2}×100\%\\ \text{P}\left(\text{´Ç´Ú g±ð³Ù³Ù¾±²Ô²µ±ð±¹±ð²Ô²Ô³Ü³¾²ú±ð°ù}\right)=50\%\end{array}$

The probability of getting even number is 50%.