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Chapter 3: Q26. (page 127)

Solve the equation. Check your solution.42=18t+4(t+5)

Short Answer

Expert verified

The solution for the equation 42=18t+4(t+5)ist=1 .

Step by step solution

01

– Separate the variable and constants

Write the original equation and separate the variable and constants.

42=18t+4(t+5)42=18t+4t+20[distributiveproperty]42=22t+20[combineliketerms]

02

– Solve for t

42鈭�20=22t+20鈭�20[subtractfrom20toeachside]22=22t[divideeachsideby22]t=1

Therefore, the solution of the equation ist=1 .

03

– Check the solution 

To check the solution, write the original equation and substitute the value oft.

42=18t+4(t+5)

Now, substitute t=1and check the result.

42=18脳1+4(1+5)42=18+4(6)42=18+2442=42

As the left-hand side is equal to right hand side, this signifies that the solution is correct.

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