/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q.4 Find the value of x. Then classi... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the value of x. Then classify the triangle by its angle measures.

Short Answer

Expert verified

The value of x isx=65°, and the triangle is a scalene right-angled triangle.

Step by step solution

01

Step 1. Given Information.

One angle of the triangle is25°.

Second angle is given asx°.

Third angle is given asx+25°.

02

Step 2. Formula.

Sum of all angles of a triangle is180°.

03

Step 3. Calculation.

The sum of all the angles of a triangle is180°.

This gives us,

x+x+25+∘25=∘180°

Add both x and both numbers together.

2x+50=∘180°

Subtract 50 from both the sides.

2x+50-∘50=∘180-∘50°

This gives us,

2x=130°

Now, divide both sides by 2.

2x°2=130°2

This will give us the value of x.

x=65°

Second side of the angle of the triangle is given as x°which is65°.

Third side of the angle of the triangle is given asx+25°.

Now add 65°to it.

This gives us the value as,

65+∘25=∘90°

04

Step 4. Conclusion.

The value of x isx=65°.

Since one angle of the triangle is 90°and the other two angles are 25°and 65°respectively.

Hence, it is a scalene right-angled triangle.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.