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Lost baggage. Occasionally an airline will lose a bag. Suppose a small airline has found it can reasonably model the number of bags lost each weekday using a Poisson model with a mean of 2.2 bags. (a) What is the probability that the airline will lose no bags next Monday? (b) What is the probability that the airline will lose \(0,1,\) or 2 bags on next Monday? (c) Suppose the airline expands over the course of the next 3 years, doubling the number of flights it makes, and the CEO asks you if it's reasonable for them to continue using the Poisson model with a mean of 2.2. What is an appropriate recommendation? Explain.

Short Answer

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(a) 0.1108. (b) 0.6228. (c) Reassess and adjust the Poisson model.

Step by step solution

01

Understanding the Poisson Distribution

The Poisson distribution is used to model the number of times an event happens in a fixed interval of time or space. Given that the mean number of events (bags lost) is \(\lambda = 2.2\), we can use this to find the probabilities for the number of events (bags lost) on a particular day.
02

Calculate Probability of Losing No Bags (a)

The probability of losing no bags can be calculated using the Poisson probability formula: \( P(X = x) = \frac{e^{-\lambda} \cdot \lambda^x}{x!} \), where \(\lambda = 2.2\) and \(x = 0\). Plug these values into the formula: \[ P(X = 0) = \frac{e^{-2.2} \cdot 2.2^0}{0!} = e^{-2.2} \approx 0.1108 \]
03

Calculate Probability of Losing 0, 1, or 2 Bags (b)

To find this probability, we need to calculate \( P(X = 0) + P(X = 1) + P(X = 2) \). These are given by:- \( P(X=0) = e^{-2.2} \)- \( P(X=1) = \frac{e^{-2.2} \cdot 2.2^1}{1!} \approx 0.2438 \)- \( P(X=2) = \frac{e^{-2.2} \cdot 2.2^2}{2!} \approx 0.2682 \)Adding them gives: \[ P(X = 0 \text{ or } 1 \text{ or } 2) = 0.1108 + 0.2438 + 0.2682 = 0.6228 \]
04

Consideration of Doubling Flights (c)

If the airline doubles the number of flights, the mean number of lost bags \(\lambda\) would likely increase since more flights usually mean more opportunities for bags to be lost. This requires recalibration of the Poisson model. Keeping \(\lambda = 2.2\) is unsuitable if the actual average changes significantly. Therefore, the recommendation is to reassess and possibly adjust \(\lambda\) based on new data.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculations
Probability calculations are essential in understanding and predicting the likelihood of various outcomes in uncertain situations. For our airline example, the Poisson distribution provides a powerful tool for these calculations. The formula for the Poisson distribution is: - \[ P(X = x) = \frac{e^{-\lambda} \cdot \lambda^x}{x!} \] It calculates the probability of observing exactly \(x\) events—such as losing \(x\) bags. First, we use it to find the probability of losing no bags by setting \(x = 0\) in the formula. This calculation shows the possibility of the airline having a perfect day with no lost bags. When trying to determine the likelihood of losing \(0, 1,\) or \(2\) bags, we must perform the calculation for each potential number of lost bags separately. Then, we sum these probabilities to understand the total probability of falling within that range. This accumulation helps in understanding how probable these different scenarios are on a typical weekday for this airline. Working out these probabilities can show airline managers just how often they can expect a certain number of bags to be lost, which is critical for planning and improving customer service.
Mean Parameter
The mean parameter, often denoted by \(\lambda\) in the Poisson distribution, is central to properly modeling and predicting events in a temporal or spatial setting. In our scenario, the mean \(\lambda = 2.2\) represents the average number of bags lost by the airline each weekday.
  • The mean value is essentially the expected frequency of the event—that is, how often this event is likely to occur.
  • In the context of lost baggage, \(\lambda\) of \(2.2\) means, on average, 2.2 bags are misplaced daily.
Because the Poisson distribution evaluates events across an interval, maintaining an accurate mean is crucial to predictions. If factors change, such as an increase in the number of flights, this mean parameter can shift, necessitating a recalibration of the entire model. Selecting an appropriate \(\lambda\) helps the business understand its regular operations and the impact of any process changes or external factors. Regularly reassessing this parameter ensures the model reflects current conditions and helps in making informed operational decisions.
Model Reassessment
Model reassessment becomes necessary when the conditions or underlying factors of a model change considerably. Our airline example highlights how the assumption of a constant mean \(\lambda = 2.2\) might not hold true if the airline expands. Doubling the flights could lead to more lost luggage, hence affecting the mean. Here’s why model reassessment is crucial:
  • If the mean \(\lambda\) changes, the current predictions and planning would no longer be accurate.
  • Regular data collection allows the model to stay relevant and reliable.
Reassessing the Poisson model involves examining new data to check if the occurrence of lost baggage has indeed changed and adjusting \(\lambda\) accordingly. This recalibration process ensures future predictions remain valid and decisions are based on factual and updated information. Making these changes helps the airline in delivering accurate performance insights and adapting its operations to better manage and, potentially, reduce lost baggage incidents.
Events in Fixed Interval
Events in a fixed interval refer to occurrences that are measured over a specific and consistent time frame or space—such as our daily count of lost baggage by the airline. The Poisson distribution is particularly adept at predicting the number of such events because it assumes these events happen independently within the same interval. Understanding fixed intervals helps businesses organize and interpret data consistently. Here are some key points:
  • These intervals allow for effective tracking and comparison of events over time.
  • Fixed intervals provide consistency in forecasting, making it easier to monitor trends or detect anomalies.
In this scenario, examining events over a weekday interval keeps operations and goals clearly defined. The reliability of predictions over standard periods helps with managing resources and responding to potential issues promptly. By consistently measuring events in a fixed interval, like weekdays, airlines can not only monitor performance but also implement targeted improvements based on observed patterns, leading to better customer satisfaction and operational efficiency.

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