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. If you flip a fair coin 10 times, what is the probability of (a) getting all tails? (b) getting all heads? (c) getting at least one tails?

Short Answer

Expert verified
(a) \( \frac{1}{1024} \), (b) \( \frac{1}{1024} \), (c) \( \frac{1023}{1024} \).

Step by step solution

01

Understanding the Problem

We are asked to find probabilities related to flipping a fair coin 10 times. Specifically: (a) getting all tails, (b) getting all heads, and (c) getting at least one tail.
02

Calculate Probability of All Tails

When flipping a fair coin, each flip has two possible outcomes: heads (H) or tails (T), both with a probability of \( \frac{1}{2} \). The probability of getting all tails in 10 flips is \( \left( \frac{1}{2} \right)^{10} = \frac{1}{1024} \).
03

Calculate Probability of All Heads

Similar to the probability of all tails, the probability of getting all heads in 10 flips is \( \left( \frac{1}{2} \right)^{10} = \frac{1}{1024} \).
04

Calculate Probability of At Least One Tail

To find the probability of at least one tail, we use the complement rule: subtract the probability of all heads from 1. This gives \( 1 - \frac{1}{1024} = \frac{1023}{1024} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coin Flip
Flipping a coin is one of the simplest forms of probability experiments. A single coin flip has two potential outcomes: heads or tails. When we say a "fair coin," we mean each outcome is equally probable. This makes the probability for a head \( \frac{1}{2} \) and for a tail \( \frac{1}{2} \)as well. Because the coin is not biased, these outcomes are what we expect.
Each flip is independent, meaning the outcome of one flip does not affect the next. For instance, flipping heads does not make tails more or less likely on the next flip. This independence is crucial in calculating probabilities over multiple flips.
When flipping a coin multiple times, the situation becomes slightly more complex. With ten flips, the probability of a specific sequence, like all tails, is calculated by taking the probability of a tail in one flip and raising it to the power of the number of flips, \( \left( \frac{1}{2} \right)^{10} \). Simply put, the more you flip, the less likely any specific sequence will occur.
Complement Rule
The complement rule is a nifty tool in probability that helps when calculating probabilities more indirectly. The idea is to consider the entire sample space—everything that could happen—and then find what you don’t want.
For example, consider wanting at least one tail in ten coin flips. Instead of calculating every possible way to include a tail, it's simpler to calculate the probability of the outcome you don’t want—all heads—and subtract it from 1, the total probability space.
Here's how it works in this exercise:
  • First, find the probability of all heads, which is \( \frac{1}{1024} \).
  • Next, use the complement rule. The probability of getting at least one tail is \(1 - \frac{1}{1024}\).
  • This calculation gives \( \frac{1023}{1024} \).
The complement rule makes complex probability calculations more manageable, especially when dealing with scenarios like "at least one" or "none of."
Independent Events
Coins flips are a classic example of independent events in probability. Independence means that the outcome of one event does not influence the outcome of another.
Each flip of the coin is not affected by previous flips; a head or tail is equally likely no matter what sequence has occurred beforehand. This property simplifies the calculation of probabilities over a series of flips.
For ten flips, each flip is considered independent. This allows us to express the probability of multiple independent events occurring together as the product of their individual probabilities. If you're calculating the chance of all heads or all tails, you multiply the independent probability of a head (or tail) \( \left( \frac{1}{2} \right)^{10} \).
Understanding independence is important in many probability problems, as it helps clarify whether or not outcomes are influenced by past events, and guides the correct calculation methods.

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Most popular questions from this chapter

The relative frequency table below displays the distribution of annual total personal income (in 2009 inflation-adjusted dollars) for a representative sample of 96,420,486 Americans. These data come from the American Community Survey for 2005-2009. This sample is comprised of \(59 \%\) males and \(41 \%\) females. \({ }^{63}\) (a) Describe the distribution of total personal income. (b) What is the probability that a randomly chosen US resident makes less than $$\$ 50,000$$ per year? (c) What is the probability that a randomly chosen US resident makes less than $$\$ 50,000$$ per year and is female? Note any assumptions you make. (d) The same data source indicates that \(71.8 \%\) of females make less than $$\$ 50,000$$ per year. Use this value to determine whether or not the assumption you made in part (c) is valid. $$\begin{array}{lr}\hline \text { Income } & \text { Total } \\ \hline \$ 1 \text { to } \$ 9,999 \text { or loss } & 2.2 \% \\ \$ 10,000 \text { to } \$ 14,999 & 4.7 \% \\ \$ 15,000 \text { to } \$ 24,999 & 15.8 \% \\ \$ 25,000 \text { to } \$ 34,999 & 18.3 \% \\ \$ 35,000 \text { to } \$ 49,999 & 21.2 \% \\ \$ 50,000 \text { to } \$ 64,999 & 13.9 \% \\ \$ 65,000 \text { to } \$ 74,999 & 5.8 \% \\ \$ 75,000 \text { to } \$ 99,999 & 8.4 \% \\ \$ 100,000 \text { or more } & 9.7 \% \\ \hline\end{array}$$

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