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Imagine you have a bag containing 5 red, 3 blue, and 2 orange chips. (a) Suppose you draw a chip and it is blue. If drawing without replacement, what is the probability the next is also blue? (b) Suppose you draw a chip and it is orange, and then you draw a second chip without replacement. What is the probability this second chip is blue? (c) If drawing without replacement, what is the probability of drawing two blue chips in a row? (d) When drawing without replacement, are the draws independent? Explain.

Short Answer

Expert verified
(a) \( \frac{2}{9} \); (b) \( \frac{1}{3} \); (c) \( \frac{1}{15} \); (d) No, they are not independent.

Step by step solution

01

Understand the Total Chips

First, we need to understand the composition of the total chips in the bag. There are 5 red, 3 blue, and 2 orange chips, summing up to a total of 10 chips.
02

Part (a) Calculate Probability

To find the probability of drawing a second blue chip after one blue has already been drawn, first note that removing one blue chip leaves 9 chips in total and 2 remaining blue chips. The probability is thus \( \frac{2}{9} \).
03

Part (b) Calculate Probability

Since the first chip drawn is orange, there are 9 chips left: 5 red, 3 blue, and 1 orange. Hence, the probability of drawing a blue chip next is \( \frac{3}{9} \) or \( \frac{1}{3} \).
04

Part (c) Calculate Probability

The probability of drawing two blue chips in a row can be calculated by first getting a blue chip \( \frac{3}{10} \), and then another blue chip \( \frac{2}{9} \). Thus, the probability is \( \frac{3}{10} \times \frac{2}{9} = \frac{6}{90} = \frac{1}{15} \).
05

Part (d) Check Independence

Drawing without replacement means the total number of chips decreases, affecting the probabilities of subsequent draws. Therefore, the events are not independent, since the outcome of the first draw affects the probability of the second draw.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conditional Probability
Conditional probability is a fundamental concept when dealing with situations where the outcome of an event impacts the probability of another. It's the probability of an event happening given that another event has already occurred.
For example, in step 2 of the solution, once a blue chip is drawn, the total number of chips and the count of blue chips change.
This alters the probability of drawing another blue chip, making it conditional on the first draw.
The formula for conditional probability is:
\( P(A|B) = \frac{P(A \cap B)}{P(B)} \)
where \( P(A|B) \) is the probability of event A occurring given that B has occurred, \( P(A \cap B) \) is the probability of both A and B occurring, and \( P(B) \) is the probability of B occurring.
This principle demonstrates how probabilities can evolve based on prior events, which is essential in calculating probabilities without replacement.
Dependent Events
In probability, events that are dependent have outcomes that affect each other. This is especially pertinent in scenarios like drawing chips without replacement from a bag.
When you draw a chip and do not replace it, the composition of the remaining chips is altered.
Therefore, the probability outcomes change based on previous draws. The scenario in parts (a), (b), and (c) of the exercise illustrates dependent events.
Let's look at part (c) as a detailed example:
  • Initially, you have a certain probability of picking a blue chip from a total of 10 chips.
  • Once a blue chip is drawn, the count of blue chips, as well as the total, decreases, impacting what remains in the bag. Thus, they become dependent events.
  • This dependency showcases how the outcome of the first event is crucial in determining the scenario for the next event.
Overall, understanding dependent events is critical, as it aligns with real-world situations where events impact each other, not isolated outcomes.
Combinatorics
Combinatorics is the branch of mathematics dealing with combinations and permutations, essential in counting and arranging possibilities.
In the context of probability without replacement, combinatorics helps calculate how likely certain draws are, based on the different potential arrangements of the remaining items.
For this exercise, understanding the initial setup and how the remaining items alter matters a lot.
Take a moment to consider different possible sequences you could draw from this bag of chips.
By considering all possible orders and how previous choices influence available options, combinatorics merges with probability to provide a full picture of likely outcomes.
Probability Calculation Steps
To solve problems like this one effectively, follow a structured approach with precise calculation steps.
Let's break down the steps used in the original solution:
  • Recognize the total number of items initially available (in this case, 10 chips).

  • Consider what happens to the total with each draw, especially since items are not replaced.

  • For part (a), compute the probability after one blue chip is drawn, leaving a new total.
  • For part (b), process the probability, recognizing the first chip is orange, which impacts the next draw outcomes.
  • For part (c), multiply the probability of the first blue by the adjusted probability for a second blue chip. This cascading effect of prior actions highlights understanding sequence.
  • In part (d), identify changes in the probability through each action showing dependence.
Calculate methodically and remember how each situation adjusts for the real-life aspect of the lack of replacement.

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