Chapter 1: Problem 33
Assume that \(|x|<\frac{1}{2}\) and determine by Taylor's Theorem the best upper bound. a. \(\left|\cos x-\left(1-x^{2} / 2\right)\right|\) b. \(\left|\sin x-x\left(1-x^{2} / 6\right)\right|\)
Short Answer
Expert verified
a. \( \leq \frac{1}{48}\); b. \( \leq \frac{1}{384}\).
Step by step solution
01
Understanding the Problem
Taylor's Theorem provides a way to approximate functions with polynomials. We want to find an upper bound for the error term when these approximations are used for \( \cos x \) and \( \sin x \). The error for approximations made by a \( n \)-degree Taylor polynomial is given by the remainder term \( R_n(x) \).
02
Finding the Taylor Remainder Term for \( \cos x \)
The approximation given is \( 1 - x^2/2 \), which is a 2nd-degree polynomial. The true Taylor series for \( \cos x \) starts as \( 1 - x^2/2 + x^4/24 - x^6/720 + \ldots \). The remainder term \( R_2(x) \) for \( \cos x \) is given by \( \frac{f^{(3)}(c)}{3!}x^3 \) for some \( c \) between 0 and \( x \). Since \( f^{(3)}(x) = -\sin x \), and \( |\sin x| \leq 1 \), the maximum absolute value of \( f^{(3)}(x) \) is 1.
03
Deriving the Error Bound for \( \cos x \approx 1 - x^2/2 \)
By using the remainder estimate, we have \( |R_2(x)| = \left|\frac{-\sin(c)}{3!} x^3\right| \leq \frac{1}{6}|x|^3 \). Since \(|x| < \frac{1}{2}\), the worst-case scenario for the error bound is \( \frac{1}{6}\left(\frac{1}{2}\right)^3 = \frac{1}{48} \). Thus, \( \left|\cos x - \left(1 - \frac{x^2}{2}\right)\right| \leq \frac{1}{48} \).
04
Finding the Taylor Remainder Term for \( \sin x \)
The approximation given is \( x - x^3/6 \), which is a 3rd-degree polynomial. The true Taylor series for \( \sin x \) is \( x - x^3/6 + x^5/120 - \ldots \). The remainder term \( R_3(x) \) is \( \frac{f^{(4)}(c)}{4!} x^4 \) where \( f^{(4)}(x) = \cos x \), and \( |\cos x| \leq 1 \).
05
Deriving the Error Bound for \( \sin x \approx x - x^3/6 \)
The error bound is \( |R_3(x)| = \left|\frac{\cos(c)}{4!} x^4\right| \leq \frac{1}{24}|x|^4 \). Given \( |x| < \frac{1}{2} \), the maximum error is \( \frac{1}{24}\left(\frac{1}{2}\right)^4 = \frac{1}{384} \). Thus, \( \left|\sin x - \left(x - \frac{x^3}{6}\right)\right| \leq \frac{1}{384} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Taylor Series
The Taylor Series is a powerful tool used to approximate functions with polynomials. This series expands a function into an infinite sum of terms calculated from the function's derivatives at a single point. It provides an approximation that becomes more accurate as more terms are included.
For a function \( f(x) \) that is infinitely differentiable at a point \( a \), the Taylor series is expressed as:
For a function \( f(x) \) that is infinitely differentiable at a point \( a \), the Taylor series is expressed as:
- \( f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \frac{f^{(3)}(a)}{3!}(x-a)^3 + \ldots \)
Error Bound
The notion of the Error Bound is crucial when working with Taylor series approximations. It provides a quantifiable measure of how accurate the polynomial approximation is compared to the original function.
For an \( n \)-degree Taylor polynomial, the error or remainder term \( R_n(x) \) represents the difference between the true function value and the polynomial approximation. The error bound helps us understand how large this remainder can be, ensuring we know the worst-case scenario in terms of deviation from the true function.
In our problem, for \( \cos x \) approximated by \( 1 - \frac{x^2}{2} \), the error bound was estimated to be \( \frac{1}{48} \), while for \( \sin x \) approximated by \( x - \frac{x^3}{6} \), it was \( \frac{1}{384} \). These calculations assure us within a specific bound how closely our polynomial matches the actual function for a given \( x \).
For an \( n \)-degree Taylor polynomial, the error or remainder term \( R_n(x) \) represents the difference between the true function value and the polynomial approximation. The error bound helps us understand how large this remainder can be, ensuring we know the worst-case scenario in terms of deviation from the true function.
In our problem, for \( \cos x \) approximated by \( 1 - \frac{x^2}{2} \), the error bound was estimated to be \( \frac{1}{48} \), while for \( \sin x \) approximated by \( x - \frac{x^3}{6} \), it was \( \frac{1}{384} \). These calculations assure us within a specific bound how closely our polynomial matches the actual function for a given \( x \).
Cosine Approximation
Approximating the cosine function with a Taylor series allows us to simplify its computation to a polynomial. The basic approximation used is \( \cos x \approx 1 - \frac{x^2}{2} \). This is a 2nd-degree polynomial derived from the Taylor series expansion of \( \cos x \).
Further approximations can be made by adding more terms, which increases accuracy. The truncated series \( 1 - \frac{x^2}{2} \) is often sufficient for small values of \( x \), especially since you're given \( |x| < \frac{1}{2} \), which ensures that terms beyond the second have a limited impact.
In calculating the error, our task is to find how far off this approximation might be from the actual \( \cos x \). By checking the remainder term or error, we find it's bounded by \( \frac{1}{48} \) in this specific exercise scenario.
Further approximations can be made by adding more terms, which increases accuracy. The truncated series \( 1 - \frac{x^2}{2} \) is often sufficient for small values of \( x \), especially since you're given \( |x| < \frac{1}{2} \), which ensures that terms beyond the second have a limited impact.
In calculating the error, our task is to find how far off this approximation might be from the actual \( \cos x \). By checking the remainder term or error, we find it's bounded by \( \frac{1}{48} \) in this specific exercise scenario.
Sine Approximation
When approximating the sine function, a similar process is followed using its Taylor series expansion. For \( \sin x \), an effective polynomial approximation is \( x - \frac{x^3}{6} \), which is a 3rd-degree polynomial.
This polynomial provides a simple way to compute the sine of small angles when high precision isn't necessary. Again, due to \( |x| < \frac{1}{2} \), the approximation is quite good, as higher order terms (like \( x^5 \) and beyond) are small.
Checking the error bound allows us to conclude that the maximum deviation from the true sine function will not exceed \( \frac{1}{384} \). Understanding this builds confidence in using polynomial approximations in practical applications where exact calculations are cumbersome or unnecessary.
This polynomial provides a simple way to compute the sine of small angles when high precision isn't necessary. Again, due to \( |x| < \frac{1}{2} \), the approximation is quite good, as higher order terms (like \( x^5 \) and beyond) are small.
Checking the error bound allows us to conclude that the maximum deviation from the true sine function will not exceed \( \frac{1}{384} \). Understanding this builds confidence in using polynomial approximations in practical applications where exact calculations are cumbersome or unnecessary.