Chapter 1: Problem 26
When the sequence \(x_{n}=(1+1 / n)^{n}\) is computed, it appears to be monotone increasing. Prove that this is so. Hints: First, if \(\ln f(x)\) is increasing, then so is \(f(x) .\) Second, if \(f^{\prime}(x)>0\), then \(f\) is increasing. Finally, \(\ln x\) is defined to be \(\int_{1}^{x} t^{-1} d t\).
Short Answer
Expert verified
The sequence \( x_n = (1 + 1/n)^n \) is monotone increasing.
Step by step solution
01
Define the Sequence
The sequence in question is \( x_n = \left(1 + \frac{1}{n}\right)^n \). Our goal is to show this sequence is monotone increasing.
02
Apply the Logarithm Hints
According to the hint, if \( \ln f(x) \) is increasing for a function, then \( f(x) \) is also increasing. Let's consider the function \( f(n) = \left(1 + \frac{1}{n}\right)^n \) and therefore look at \( \ln f(n) = \ln \left(1 + \frac{1}{n}\right)^n = n \ln \left(1 + \frac{1}{n}\right) \).
03
Differentiate the Logarithm
To show \( n \ln \left(1 + \frac{1}{n}\right) \) is increasing, we need to check if its derivative with respect to \( n \), denoted here by \( g(n) = n \ln \left(1 + \frac{1}{n}\right) \), is positive. The derivative \( g'(n) \) is calculated using the product and chain rules:
04
Simplify the Derivative
Calculate the derivative: \[g'(n) = \ln\left(1 + \frac{1}{n}\right) + n \cdot \frac{d}{dn}\ln\left(1 + \frac{1}{n}\right)\]Recall that \( \frac{d}{dn}\ln\left(1 + \frac{1}{n}\right) = -\frac{1}{n(n+1)} \). Apply the derivative:
05
Detailed Derivative Calculation
Compute:\[g'(n) = \ln\left(1 + \frac{1}{n}\right) - \frac{1}{n+1}\]
06
Evaluate and Conclude
We need \( g'(n) > 0 \) for the sequence to be increasing. Notice that:\[\ln\left(1 + \frac{1}{n}\right) \approx \frac{1}{n} - \frac{1}{2n^2} + \cdots > \frac{1}{n} - \frac{1}{n+1}\]This shows \( g'(n) > 0 \), hence \( n \ln \left(1 + \frac{1}{n}\right) \) is increasing. Therefore, the sequence \( x_n \) is increasing.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Logarithmic Differentiation
Logarithmic differentiation is a clever method that helps simplify the differentiation of complex functions, particularly those involving products or powers of variables.
It is based on taking the natural logarithm of a function, which turns products into sums and exponents into multiplication, making differentiation more straightforward.
For example, if you have a function like \(f(n) = \left(1 + \frac{1}{n}\right)^n\), directly differentiating it can be tricky.
By logarithmically differentiating, you first take the natural log:
Such an approach is vital when working with sequences such as \(x_n = \left(1 + \frac{1}{n}\right)^n\), because it simplifies the steps needed to understand the behavior of the sequence.
In this context, if \(\ln f(n)\) is increasing, then \(f(n)\) itself is increasing, which is a crucial insight when proving properties like monotonicity.
It is based on taking the natural logarithm of a function, which turns products into sums and exponents into multiplication, making differentiation more straightforward.
For example, if you have a function like \(f(n) = \left(1 + \frac{1}{n}\right)^n\), directly differentiating it can be tricky.
By logarithmically differentiating, you first take the natural log:
- \(\ln f(n) = n \ln \left(1 + \frac{1}{n}\right)\)
Such an approach is vital when working with sequences such as \(x_n = \left(1 + \frac{1}{n}\right)^n\), because it simplifies the steps needed to understand the behavior of the sequence.
In this context, if \(\ln f(n)\) is increasing, then \(f(n)\) itself is increasing, which is a crucial insight when proving properties like monotonicity.
Sequence Convergence
Sequence convergence refers to the concept of whether a sequence approaches a specific value as its index grows larger.
A sequence is termed "convergent" if it approaches a particular limit.
In mathematical terms, for a sequence \( \{a_n\} \), it converges to a limit \( L \) if for every positive number \( \epsilon \), there exists an integer \( N \) such that for all \( n > N \), the terms of the sequence satisfy \( |a_n - L| < \epsilon \).
In the case of the sequence \( x_n = \left(1 + \frac{1}{n}\right)^n\), it is known to converge to the mathematical constant \( e \) (approximately 2.718).
This conclusion comes from both theoretical work related to the definition of \( e \) and practical numerical computations showing \( x_n \) getting increasingly closer to \( e \) as \( n \) increases.
The convergence is significant because it connects this seemingly simple sequence to one of the most important constants in mathematics.
A sequence is termed "convergent" if it approaches a particular limit.
In mathematical terms, for a sequence \( \{a_n\} \), it converges to a limit \( L \) if for every positive number \( \epsilon \), there exists an integer \( N \) such that for all \( n > N \), the terms of the sequence satisfy \( |a_n - L| < \epsilon \).
In the case of the sequence \( x_n = \left(1 + \frac{1}{n}\right)^n\), it is known to converge to the mathematical constant \( e \) (approximately 2.718).
This conclusion comes from both theoretical work related to the definition of \( e \) and practical numerical computations showing \( x_n \) getting increasingly closer to \( e \) as \( n \) increases.
The convergence is significant because it connects this seemingly simple sequence to one of the most important constants in mathematics.
Derivative Analysis
Derivative analysis is a technique used to understand how a function behaves as its input changes — essentially, it reveals the rate of change.
Calculating the derivative provides vital insights into whether a function is increasing or decreasing.
A positive derivative indicates an increasing function, while a negative derivative points to a decreasing one.
In this exercise, we applied derivative analysis to the function \( g(n) = n \ln \left(1 + \frac{1}{n}\right) \) to examine if it is monotone increasing.
The key step here was to find \( g'(n) \), the derivative of \(g(n)\) with respect to \( n\), which we simplified as:
This analysis illuminates the behavior of sequences and functions, offering a deeper comprehension beyond numerical computation alone.
Calculating the derivative provides vital insights into whether a function is increasing or decreasing.
A positive derivative indicates an increasing function, while a negative derivative points to a decreasing one.
In this exercise, we applied derivative analysis to the function \( g(n) = n \ln \left(1 + \frac{1}{n}\right) \) to examine if it is monotone increasing.
The key step here was to find \( g'(n) \), the derivative of \(g(n)\) with respect to \( n\), which we simplified as:
- \(g'(n) = \ln\left(1 + \frac{1}{n}\right) - \frac{1}{n+1}\)
This analysis illuminates the behavior of sequences and functions, offering a deeper comprehension beyond numerical computation alone.