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Use Taylor's Theorem with \(n=2\) to prove that the inequality \(1+x

Short Answer

Expert verified
The inequality \(1+x<e^{x}\) is valid for all real numbers except \(x=0\).

Step by step solution

01

Understanding Taylor's Theorem

Taylor's Theorem states that any function that is sufficiently smooth around a point can be approximated by a polynomial up to any desired degree. For this exercise, we are using Taylor's theorem around 0 for the function \(e^x\) with \(n = 2\).
02

Writing the Taylor Series Expansion

The Taylor series expansion for \(e^x\) about \(x = 0\) (to the order \(n = 2\)) is \(e^x = 1 + x + \frac{x^2}{2} + R_2(x)\), where \(R_2(x)\) is the remainder term of order 2.
03

Analyzing the Remainder Term

The remainder term \(R_2(x)\) for Taylor's theorem is given by \(R_2(x) = \frac{e^c x^3}{3!}\) for some \(c\) between \(0\) and \(x\). Since \(e^c > 0\), \(R_2(x)\) is always positive for \(x eq 0\).
04

Proving the Inequality

From the Taylor expansion, since the remainder \(R_2(x)\) is always positive for \(x eq 0\), we have:\[ e^x = 1 + x + \frac{x^2}{2} + R_2(x) > 1 + x \] thereby proving the inequality \(1 + x < e^x\) holds for \(x eq 0\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Taylor series expansion
The Taylor series expansion is a powerful tool in calculus, allowing us to approximate functions with polynomials. For those unfamiliar, think of it as breaking a complex function down into an infinite sum of its derivatives evaluated at a single point. This method excels in making calculations around this point much easier.
Consider the exponential function, such as \(e^x\). At the core of this expansion is the concept that \(e^x\) can be expressed in terms of its derivatives at zero, leading to the expression:
  • \(e^x \approx 1 + x + \frac{x^2}{2} + \ldots\)
For this exercise, we focus on the terms up to \(x^2\) and include a remainder term to account for the rest of the function's behavior. The idea is to create a polynomial that sufficiently approximates \(e^x\) right around \(x = 0\), known as a Taylor polynomial. This expansion proves invaluable for analysis, as it simplifies how we look at functions like \(e^x\) by visualizing them as sums of simpler terms.
Inequality proof
Proving inequalities using calculus involves leveraging the properties of functions and their derivatives. In our context, we used a Taylor series expansion to approximate \(e^x\) and show that \(1 + x < e^x\) for \(x eq 0\).
  • This is accomplished by understanding the behavior of the remainder term \(R_2(x)\).
The remainder term in a Taylor series acts as our error margin—how far off our approximation is from the actual function. Remarkably, for the function \(e^x\), this term is always positive for \(x \, eq \, 0\). Specifically, \(R_2(x) = \frac{e^c x^3}{3!}\), where \(c\) is a value between \(0\) and \(x\). This implies that our polynomial \(1 + x + \frac{x^2}{2}\) always underestimates \(e^x\), making the original expression \(1 + x < e^x\) true. This approach of using a positive remainder to prove the inequality is an elegant demonstration of how calculus can solidify our understanding of function behaviors.
Exponential functions
Exponential functions, like \(e^x\), play a critical role in both mathematics and the sciences. One of their most remarkable properties is that the rate of change of \(e^x\) is always proportional to its current value—a concept that forms the backbone of exponential growth and decay processes.
These functions boast several fascinating properties; notably:
  • They grow faster than polynomial functions as \(x\) increases.
  • Their derivatives are simply scaled versions of themselves, specifically, the derivative of \(e^x\) is \(e^x\) itself.
In proving inequalities like \(1+x< e^x\), we focus on harnessing these properties through tools such as Taylor series. The faithful work of such functions in calculus underpins the elegant reliability of exponential functions in unpredictable real-world phenomena, from population dynamics to financial models. Through Taylor's theorem and its remainder term, we gain insight into how exponential functions consistently exceed simple linear growth \(1+x\). Thus, understanding exponential functions is not just about recognizing their formula, but also about appreciating their swift rise and infinite potential.

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