Chapter 1: Problem 25
Use Taylor's Theorem with \(n=2\) to prove that the inequality \(1+x
Short Answer
Expert verified
The inequality \(1+x<e^{x}\) is valid for all real numbers except \(x=0\).
Step by step solution
01
Understanding Taylor's Theorem
Taylor's Theorem states that any function that is sufficiently smooth around a point can be approximated by a polynomial up to any desired degree. For this exercise, we are using Taylor's theorem around 0 for the function \(e^x\) with \(n = 2\).
02
Writing the Taylor Series Expansion
The Taylor series expansion for \(e^x\) about \(x = 0\) (to the order \(n = 2\)) is \(e^x = 1 + x + \frac{x^2}{2} + R_2(x)\), where \(R_2(x)\) is the remainder term of order 2.
03
Analyzing the Remainder Term
The remainder term \(R_2(x)\) for Taylor's theorem is given by \(R_2(x) = \frac{e^c x^3}{3!}\) for some \(c\) between \(0\) and \(x\). Since \(e^c > 0\), \(R_2(x)\) is always positive for \(x eq 0\).
04
Proving the Inequality
From the Taylor expansion, since the remainder \(R_2(x)\) is always positive for \(x eq 0\), we have:\[ e^x = 1 + x + \frac{x^2}{2} + R_2(x) > 1 + x \] thereby proving the inequality \(1 + x < e^x\) holds for \(x eq 0\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Taylor series expansion
The Taylor series expansion is a powerful tool in calculus, allowing us to approximate functions with polynomials. For those unfamiliar, think of it as breaking a complex function down into an infinite sum of its derivatives evaluated at a single point. This method excels in making calculations around this point much easier.
Consider the exponential function, such as \(e^x\). At the core of this expansion is the concept that \(e^x\) can be expressed in terms of its derivatives at zero, leading to the expression:
Consider the exponential function, such as \(e^x\). At the core of this expansion is the concept that \(e^x\) can be expressed in terms of its derivatives at zero, leading to the expression:
- \(e^x \approx 1 + x + \frac{x^2}{2} + \ldots\)
Inequality proof
Proving inequalities using calculus involves leveraging the properties of functions and their derivatives. In our context, we used a Taylor series expansion to approximate \(e^x\) and show that \(1 + x < e^x\) for \(x eq 0\).
- This is accomplished by understanding the behavior of the remainder term \(R_2(x)\).
Exponential functions
Exponential functions, like \(e^x\), play a critical role in both mathematics and the sciences. One of their most remarkable properties is that the rate of change of \(e^x\) is always proportional to its current value—a concept that forms the backbone of exponential growth and decay processes.
These functions boast several fascinating properties; notably:
These functions boast several fascinating properties; notably:
- They grow faster than polynomial functions as \(x\) increases.
- Their derivatives are simply scaled versions of themselves, specifically, the derivative of \(e^x\) is \(e^x\) itself.