Chapter 12: Problem 16
Find \(|\mathbf{a}| .|-2 \mathbf{b}| .|\mathbf{a}-\mathbf{b}|, \mathbf{a}+\mathbf{b}\), and \(3 \mathbf{a}-2 \mathbf{b}\) $$ \mathbf{a}=-\mathbf{i}-\mathbf{j} . \quad \mathbf{b}=2 \mathbf{i}+2 \mathbf{j} $$
Short Answer
Expert verified
The required calculations yield: \(|\mathbf{a}| = \sqrt{2}, |-2\mathbf{b}| = 4\sqrt{2}, |\mathbf{a}-\mathbf{b}| = 3\sqrt{2}, \mathbf{a}+\mathbf{b} = \mathbf{i} + \mathbf{j}, 3\mathbf{a} - 2\mathbf{b} = \mathbf{i} + \mathbf{j}."
Step by step solution
01
Finding \(|\mathbf{a}|\)
Calculate the magnitude of \(\mathbf{a}\). Given \(\mathbf{a} = -\mathbf{i} - \mathbf{j}\), the formula to use is \(|\mathbf{a}| = \sqrt{(-1)^2 + (-1)^2}\). This simplifies to \(|\mathbf{a}| = \sqrt{2}\).
02
Finding \(|-2 \mathbf{b}|\)
Calculate \(-2 \mathbf{b}\) first. Since \(\mathbf{b} = 2 \mathbf{i} + 2 \mathbf{j}\), we have \(-2 \mathbf{b} = -4 \mathbf{i} - 4 \mathbf{j}\). Now calculate the magnitude as follows: \(|-2 \mathbf{b}| = \sqrt{(-4)^2 + (-4)^2} = \sqrt{32} = 4\sqrt{2}\).
03
Finding \(|\mathbf{a} - \mathbf{b}|\)
First, calculate \(\mathbf{a} - \mathbf{b}\). \(\mathbf{a} - \mathbf{b} = (-1 \mathbf{i} - 1 \mathbf{j}) - (2 \mathbf{i} + 2 \mathbf{j}) = -3 \mathbf{i} - 3 \mathbf{j}\). Then, find the magnitude: \(|\mathbf{a} - \mathbf{b}| = \sqrt{(-3)^2 + (-3)^2} = \sqrt{18} = 3\sqrt{2}\).
04
Calculating \(\mathbf{a} + \mathbf{b}\)
Add the vector \(\mathbf{a}\) and \(\mathbf{b}\). \(\mathbf{a} + \mathbf{b} = (-1 \mathbf{i} - 1 \mathbf{j}) + (2 \mathbf{i} + 2 \mathbf{j}) = (1 \mathbf{i} + 1 \mathbf{j}) = \mathbf{i} + \mathbf{j}\).
05
Calculating \(3 \mathbf{a} - 2 \mathbf{b}\)
First compute each term. \(3 \mathbf{a} = 3(- \mathbf{i} - \mathbf{j}) = -3 \mathbf{i} - 3 \mathbf{j}\). \(-2 \mathbf{b}\) was calculated in Step 2 as \(-4 \mathbf{i} - 4 \mathbf{j}\). Combine both vectors: \(3 \mathbf{a} - 2 \mathbf{b} = (-3 \mathbf{i} - 3 \mathbf{j}) - (-4 \mathbf{i} - 4 \mathbf{j}) = \mathbf{i} + \mathbf{j}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Magnitude of Vectors
The magnitude of a vector, essentially its length, can be understood as the distance from the origin to the point represented by the vector in a coordinate system. This is applicable in both two and three dimensions, but we'll focus on two-dimensional vectors here for simplicity. To find the magnitude, you use the formula:
- If you have a vector \(\mathbf{v} = a\mathbf{i} + b\mathbf{j}\), then its magnitude \(|\mathbf{v}|\) is calculated as \(|\mathbf{v}| = \sqrt{a^2 + b^2}\).
Vector Addition
Vector addition is a fundamental operation in vector arithmetic. Simply put, it involves adding together the corresponding components of the given vectors. Suppose you have two vectors, \(\mathbf{a} = a_1 \mathbf{i} + a_2 \mathbf{j}\) and \(\mathbf{b} = b_1 \mathbf{i} + b_2 \mathbf{j}\). The sum \(\mathbf{a} + \mathbf{b}\) is given by:
For instance, in our exercise, \(\mathbf{a} = -\mathbf{i} - \mathbf{j}\) and \(\mathbf{b} = 2\mathbf{i} + 2\mathbf{j}\). Adding them gives \(\mathbf{a} + \mathbf{b} = \mathbf{i} + \mathbf{j}\). This operation preserves the direction proportionally according to the individual components' directions.
- \(\mathbf{a} + \mathbf{b} = (a_1 + b_1) \mathbf{i} + (a_2 + b_2) \mathbf{j}\)
For instance, in our exercise, \(\mathbf{a} = -\mathbf{i} - \mathbf{j}\) and \(\mathbf{b} = 2\mathbf{i} + 2\mathbf{j}\). Adding them gives \(\mathbf{a} + \mathbf{b} = \mathbf{i} + \mathbf{j}\). This operation preserves the direction proportionally according to the individual components' directions.
Scalar Multiplication
Scalar multiplication involves multiplying a vector by a scalar (a constant real number). This operation scales the vector, changing its magnitude but not its direction. Suppose you have a vector \(\mathbf{v} = a\mathbf{i} + b\mathbf{j}\) and you multiply it by a scalar, say \(-2\). The result is:
- \(-2\mathbf{v} = -2(a\mathbf{i} + b\mathbf{j}) = (-2a)\mathbf{i} + (-2b)\mathbf{j}\)
Subtraction of Vectors
Subtracting vectors is quite like adding them, but with a slight twist. You subtract one vector from another by subtracting each corresponding component. Given two vectors \(\mathbf{a} = a_1 \mathbf{i} + a_2 \mathbf{j}\) and \(\mathbf{b} = b_1 \mathbf{i} + b_2 \mathbf{j}\), the difference \(\mathbf{a} - \mathbf{b}\) is calculated as:
In the provided exercise, \(\mathbf{a} - \mathbf{b}\) was evaluated as \(-3 \mathbf{i} - 3 \mathbf{j}\). This operation is essential for determining relative positions and movements in space. Just remember to handle each component carefully, ensuring the correct vector gets subtracted.
- \(\mathbf{a} - \mathbf{b} = (a_1 - b_1) \mathbf{i} + (a_2 - b_2) \mathbf{j}\)
In the provided exercise, \(\mathbf{a} - \mathbf{b}\) was evaluated as \(-3 \mathbf{i} - 3 \mathbf{j}\). This operation is essential for determining relative positions and movements in space. Just remember to handle each component carefully, ensuring the correct vector gets subtracted.