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Determine the \(t\) critical value for a two-sided confidence interval in each of the following situations: a. Confidence level \(=95 \%\), df \(=10\) b. Confidence level \(=95 \%\), df \(=15\) c. Confidence level \(=99 \%\), df \(=15\) d. Confidence level \(=99 \%, n=5\) e. Confidence level \(=98 \%\), df \(=24\) f. Confidence level \(=99 \%, n=38\)

Short Answer

Expert verified
(a) 2.228, (b) 2.131, (c) 2.947, (d) 4.604, (e) 2.492, (f) 2.717.

Step by step solution

01

Understanding the t-distribution

The t-distribution is used in statistics to estimate population parameters when the sample size is small and/or the population variability is unknown. The critical value is determined by the confidence level and degrees of freedom (df), where df = n - 1 for a sample size of n.
02

Finding the t-critical value for (a)

For a 95% confidence level and 10 degrees of freedom, we look up the t-table or use a statistical calculator to find the t-critical value. The explanation requires a two-tailed test, hence we consider the two tails of 5% (2.5% each). The t-critical value is approximately 2.228.
03

Finding the t-critical value for (b)

For a 95% confidence level with 15 degrees of freedom, refer to the t-distribution table or use a statistical calculator. Again, for a two-tailed test, we allocate 2.5% in each tail. The t-critical value is around 2.131.
04

Finding the t-critical value for (c)

With a 99% confidence level and 15 degrees of freedom, use the t-table or a statistical tool to determine the critical value. Since 1% is in two tails, we use 0.5% in each tail. The t-critical value is approximately 2.947.
05

Finding the t-critical value for (d)

For a 99% confidence level and a sample size (n) of 5, the degrees of freedom are df = 5 - 1 = 4. Referring to a t-table or calculator, we set 0.5% in each tail for the two-tailed test. The t-critical value is approximately 4.604.
06

Finding the t-critical value for (e)

With a 98% confidence level and 24 degrees of freedom, consult the t-distribution table. Allocate 1% in each tail for the two-tailed test. The corresponding t-critical value is approximately 2.492.
07

Finding the t-critical value for (f)

For a 99% confidence level and a sample size of 38, we calculate the degrees of freedom as df = 38 - 1 = 37. Using a t-distribution table or calculator, with 0.5% in each tail, the t-critical value is approximately 2.717.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Interval
A confidence interval gives us a range of values which is likely to contain the true population parameter. It is constructed from the sample data and a given confidence level, which indicates how sure we are about the interval containing the parameter. For instance, a 95% confidence interval suggests that if we were to take many samples and compute an interval from each one, we expect about 95% of those intervals to contain the true parameter.

The width of the confidence interval depends on several factors:
  • Sample size: Larger samples tend to give more precise estimates, leading to narrower intervals.
  • Variability in the data: More variability can increase the interval width.
  • Confidence level: Higher confidence levels (like 99% versus 95%) result in wider intervals because we are extending the range to be more confident that it includes the true parameter.
Understanding how to calculate and interpret a confidence interval is crucial for inferring information about a population based on sample data.
Degrees of Freedom
Degrees of freedom (df) are a concept used in various statistical analyses. They are important when calculating the critical values for t-distributions, influencing the accuracy of statistical estimates.

In simple terms, degrees of freedom refer to the number of values in a calculation that are free to vary. When estimating a parameter like the mean, if you have a sample size of n, your degrees of freedom is typically df = n - 1. This concept ensures that the statistical test accounts for the number of independent values in your data.

In the context of a t-distribution:
  • The smaller the sample size, the fewer the degrees of freedom, and the more variable (wider) the t-distribution becomes.
  • As the sample size increases, the t-distribution approaches a normal distribution.
  • Knowing the degrees of freedom allows us to find the correct t-critical value for constructing confidence intervals.
T-Critical Value
The t-critical value is a key component in hypothesis testing and constructing confidence intervals, particularly when dealing with small sample sizes or unknown population variances. It represents a cutoff point on the t-distribution.

To find a t-critical value, one must know:
  • The confidence level: This determines how much of the data falls within the tails of the distribution.
  • The degrees of freedom: Used to select the correct t-distribution.
For example, in a 95% confidence interval with a two-tailed test, you need to account for 2.5% in each tail, giving you a central region covering 95% of the distribution. By referencing t-distribution tables or using a calculator, the t-critical value can be found, which helps in determining the interval's size.

The t-critical value increases with higher confidence levels or needs to be adjusted through degrees of freedom, as seen with different sample sizes.
Two-Tailed Test
A two-tailed test is a statistical test used when we are interested in deviations in both directions from a specific parameter value. This means, in practical terms, we are checking whether the sample data is significantly higher or lower than the parameter.

In the context of hypothesis testing with a t-distribution:
  • A two-tailed test examines the extremes on both ends of the distribution.
  • It is common in confidence interval estimation, requiring the critical region (the tails) to be split into two parts.
  • For a given confidence level, the percentages in the tails must total to the balance leftover from one minus the confidence level.
    • For example, with a 95% confidence level, a two-tailed test would have 2.5% in each tail, totaling 5% beyond the confidence interval.

      Two-tailed tests are essential when you want to see if a parameter has changed, regardless of direction, making them versatile and widely applicable in various statistical analyses.

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Most popular questions from this chapter

A CI is desired for the true average stray-load loss \(\mu\) (watts) for a certain type of induction motor when the line current is held at 10 amps for a speed of \(1,500 \mathrm{rpm}\). Assume that stray-load loss is normally distributed with \(\sigma=3.0\). a. Compute a \(95 \%\) CI for \(\mu\) when \(n=25\) and \(\bar{x}=58.3 .\) b. Compute a \(95 \%\) CI for \(\mu\) when \(n=100\) and \(\pi=58.3\). c. Compute a \(99 \%\) CI for \(\mu\) when \(n=100\) and \(\pi=58.3\) d. Compute an \(82 \%\) CI for \(\mu\) when \(n=100\) and \(\bar{x}=58.3 .\) e. How large must \(n\) be if the width of the \(99 \%\) interval for \(\mu\) is to be \(1.0\) ?

A random sample of \(n=15\) heat pumps of a certain type yielded the following observations on lifetime (in years): \(\begin{array}{rrrrrrrr}2.0 & 1.3 & 6.0 & 1.9 & 5.1 & .4 & 1.0 & 5.3 \\ 15.7 & .7 & 4.8 & .9 & 12.2 & 5.3 & .6 & \end{array}\) a. Assume that the lifetime distribution is exponential and use an argument parallel to that of Example \(8.5\) to obtain a \(95 \%\) CI for expected (true average) lifetime. b. How should the interval of part (a) be altered to achieve a confidence level of \(99 \%\) ? c. What is a \(95 \%\) CI for the standard deviation of the lifetime distribution? [Hint: What is the standard deviation of an exponential random variable?]

Here is a sample of ACT scores (average of the Math, English, Social Science, and Natural Science scores) for students taking college freshman calculus: \(\begin{array}{lllllll}24.00 & 28.00 & 27.75 & 27.00 & 24.25 & 23.50 & 26.25 \\\ 24.00 & 25.00 & 30.00 & 23.25 & 26.25 & 21.50 & 26.00 \\ 28.00 & 24.50 & 22.50 & 28.25 & 21.25 & 19.75 & \end{array}\) a. Using an appropriate graph, see if it is plausible that the observations were selected from a normal distribution. b. Calculate a two-sided \(95 \%\) confidence interval for the population mean. c. The university ACT average for entering freshmen that year was about 21. Are the calculus students better than average, as measured by the ACT?

Each of the following is a confidence interval for \(\mu=\) true average (i.c., population mean) resonance frequency \((\mathrm{Hz})\) for all tennis rackets of a certain type: \((114.4,115.6) \quad(114.1,115.9)\) a. What is the value of the sample mean resonance frequency? b. Both intervals were calculated from the same sample data. The confidence level for one of these intervals is \(90 \%\) and for the other is \(99 \%\). Which of the intervals has the \(90 \%\) confidence level, and why?

Aphid infestation of fruit trees can be controlled either by spraying with pesticide or by inundation with ladybugs. In a particular area, four different groves of fruit trees are selected for experimentation. The first three groves are sprayed with pesticides 1,2 , and 3 , respectively, and the fourth is treated with ladybugs, with the following results on yield: \begin{tabular}{llll} \hline Treatment & \multicolumn{1}{l}{\(n_{i}\) (number of } & \({\bar{x}_{i}}\) (bushels/ \\ & trees) & tree) & \\ \hline 1 & 100 & \(10.5\) & \(1.5\) \\ 2 & 90 & \(10.0\) & \(1.3\) \\ 3 & 100 & \(10.1\) & \(1.8\) \\ 4 & 120 & \(10.7\) & \(1.6\) \\ \hline \end{tabular} Let \(\mu_{i}=\) the true average yield (bushels/tree) after receiving the \(i\) th treatment. Then $$ \theta=\frac{1}{3}\left(\mu_{1}+\mu_{2}+\mu_{3}\right)-\mu_{4} $$ measures the difference in true average yields between treatment with pesticides and treatment with ladybugs. When \(n_{1}, n_{2}, n_{3}\), and \(n_{4}\) are all large, the estimator \(\hat{\theta}\) obtained by replacing each \(\mu_{i}\) by \(\bar{X}_{i}\) is approximately normal. Use this to derive a large-sample \(100(1-\alpha) \%\) CI for \(\theta\), and compute the \(95 \%\) interval for the given data.

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