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The fraction of a bottle that is filled with a particular liquid is a continuous random variable \(X\) with pdf \(f(x ; \theta)=\theta x^{\theta-1}\) for \(00\) ). a. Obtain the method of moments estimator for \(\theta\). b. Is the estimator of (a) a sufficient statistic? If not, what is a sufficient statistic, and what is an estimator of \(\theta\) (not necessarily unbiased) based on a sufficient statistic?

Short Answer

Expert verified
Method of moments estimator: \( \hat{\theta} = \frac{\bar{x}}{1 - \bar{x}} \). It's not sufficient. Sufficient statistic is \( T = \sum \ln(X_i) \), estimator: \( \hat{\theta}_{MLE} = -\frac{n}{T} \).

Step by step solution

01

Identify the Moment to Use

To obtain the method of moments estimator for \( \theta \), we need to equate the theoretical moment to the sample moment. Here the first theoretical moment (mean) of the distribution can be used. Since \( X \sim \text{Beta}(\theta, 1) \) for \( 0 < x < 1 \), the mean of \( X \) is given by \( E(X) = \frac{\theta}{\theta+1} \).
02

Set the Theoretical Mean to Sample Mean

The method of moments equates the sample mean to the theoretical mean. Denote the sample mean as \( \bar{x} \), so we equate:\[ \bar{x} = \frac{\theta}{\theta+1} \]
03

Solve for Theta

To solve for \( \theta \), rearrange the equation from Step 2:\[ \bar{x} (\theta + 1) = \theta \]Simplifying gives:\[ \theta \bar{x} + \bar{x} = \theta \]\[ \theta \bar{x} - \theta = -\bar{x} \]\[ \theta (\bar{x} - 1) = -\bar{x} \]\[ \theta = \frac{\bar{x}}{1 - \bar{x}} \]
04

Check Sufficiency of the Estimator

The problem asks if this estimator is a sufficient statistic. A statistic is sufficient if it captures all the information about a parameter from the data. For the given distribution, the complete sufficient statistic for \( \theta \) is the sum of the logs of the observations, called \( T = \sum \ln(X_i) \).
05

Alternative Estimator Using Sufficient Statistic

Given \( T = \sum \ln(X_i) \) as a sufficient statistic, the likelihood function is: \[ L(\theta|X) \propto \theta^n \prod_{i=1}^{n} x_i^{\theta-1} = \theta^n (e^{T})^{\theta-1} \]The estimator for \( \theta \) based on this is:\[ \hat{\theta}_{MLE} = -\frac{n}{T} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sufficient Statistic
A sufficient statistic is a fundamental concept in statistics. It refers to a statistic that captures all necessary information from a sample about a parameter of interest. Imagine you have a dataset and want to make inferences about a population parameter, such as the mean or variance. A sufficient statistic allows you to summarize the data efficiently, without losing any information about the parameter. This concept is crucial when working with complex probability distributions.
For the given problem, the distribution of the continuous random variable reveals that the sum of the logarithms of observations, denoted as \( T = \sum \ln(X_i) \), is the sufficient statistic for \( \theta \).
  • It means, instead of using the whole dataset, \( T \) contains all the data necessary to estimate \( \theta \) optimally.
  • A sufficient statistic simplifies the process and is central to methods like Maximum Likelihood Estimation.
Understanding sufficient statistics can streamline statistical analysis and improve the efficiency of inferences and estimations.
Estimator
An estimator is a rule or formula used to calculate an estimate from observed data. It is the practical tool statisticians use to infer the characteristics of a larger population based on sample data. Estimators play a vital role in statistics because they provide ways to deduce unknown parameters.
In the context of the exercise, the method of moments estimator for \( \theta \) is derived by equating the sample mean \( \bar{x} \) to the theoretical mean \( \frac{\theta}{\theta+1} \).
  • This estimator is determined through a relationship that links sample data to theoretical parameters.
  • There are various methods to create estimators, each aiming to provide the most accurate reflection of the parameter being estimated.
The choice of an estimator can be critical in practice, as it affects the reliability and credibility of the conclusions drawn from data.
Maximum Likelihood Estimator
The Maximum Likelihood Estimator (MLE) is a powerful method for finding estimates of parameters by maximizing the likelihood function. This technique chooses the parameter values that make the observed data most probable. MLE is widely used in statistical modeling due to its desirable efficiency and asymptotic properties.
In the given exercise, we use the likelihood function \( L(\theta|X) \propto \theta^n \prod_{i=1}^{n} x_i^{\theta-1} = \theta^n (e^{T})^{\theta-1} \) to find the MLE for \( \theta \). The final estimator is derived as:
  • \( \hat{\theta}_{MLE} = -\frac{n}{T} \), where \( T = \sum \ln(X_i) \).
  • This form indicates a direct relationship between the observed data and the parameter estimate.
MLE is often chosen for its likelihood-based foundation, providing a maximum insight from the given data.
Continuous Random Variable
Continuous random variables depict scenarios where outcomes form a continuum and cannot be counted individually. Such variables are defined over an interval of real numbers, making them suitable for modeling a wide range of phenomena. These variables have a probability density function (pdf) that specifies the likelihood of falling within a particular range.
In the exercise, the fraction of a bottle filled with a liquid is modeled as a continuous random variable \(X\), with the probability density function:\[f(x ; \theta) = \theta x^{\theta-1}\text{ for }00.\]
  • The function describes how probabilities are distributed across different fill-fractions of the bottle.
  • The parameter \(\theta\) influences the shape of this distribution, affecting probabilities across the interval.
Understanding continuous random variables helps in modeling practical situations that cannot be discretely counted, adding depth to statistical analysis and interpretation.

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