Chapter 7: Problem 54
When the sample standard deviation \(S\) is based on a random sample from a normal population distribution, it can be shown that $$ E(S)=\sqrt{2 /(n-1)} \Gamma(n / 2) \sigma / \Gamma[(n-1) / 2] $$ Use this to obtain an unbiased estimator for \(\sigma\) of the form \(c S\). What is \(c\) when \(n=20\) ?
Short Answer
Step by step solution
Understand the Problem Statement
Set up the Equation for the Unbiased Estimator
Solve for \( c \)
Calculate \( c \) for \( n = 20 \)
Provide Final Answer
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sample Standard Deviation
Calculating the sample standard deviation involves a few steps:
- Find the mean of the data set.
- Subtract the mean from each data point and square the result.
- Calculate the average of these squared differences.
- Finally, take the square root of that average.
Gamma Function
A notable property of the Gamma function is:
- \( \Gamma(n+1) = n \times \Gamma(n) \)
Expected Value
For the sample standard deviation \( S \), the expected value \( E(S) \) refers to its average result after many samples, considering the population standard deviation \( \sigma \). It provides insight into the accuracy of \( S \) as an estimate for \( \sigma \).
The formula given for \( E(S) \) in our problem is:\[E(S) = \sqrt{\frac{2}{n-1}} \frac{\Gamma(n/2)}{\Gamma((n-1)/2)} \sigma\]This expression is crucial because it dictates how \( S \) systematically differs from \( \sigma \), allowing adjustments to parameters like \( c \) to achieve an unbiased estimator.
Normalizer Constant
To find \( c \), we solve for:\[c = \frac{1}{\sqrt{\frac{2}{n-1}} \frac{\Gamma(n/2)}{\Gamma((n-1)/2)}}\]This relation ensures that when \( S \) is multiplied by \( c \), the expected value equals the true standard deviation, \( \sigma \). By substituting \( n = 20 \), we calculated a specific normalizer constant \( c \approx 4.97749 \). This transform balances out the innate bias of \( S \), giving us an accurate, unbiased estimate of \( \sigma \).
Adjusting with such a constant is crucial in honing estimates derived from sample statistics.