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When the sample standard deviation \(S\) is based on a random sample from a normal population distribution, it can be shown that $$ E(S)=\sqrt{2 /(n-1)} \Gamma(n / 2) \sigma / \Gamma[(n-1) / 2] $$ Use this to obtain an unbiased estimator for \(\sigma\) of the form \(c S\). What is \(c\) when \(n=20\) ?

Short Answer

Expert verified
The value of \( c \) is approximately \( 4.97749 \) when \( n = 20 \).

Step by step solution

01

Understand the Problem Statement

We are given an equation for the expected value of the sample standard deviation \( S \), the goal is to find an unbiased estimator for \( \sigma \) of the form \( cS \). We need to adjust \( c \) such that the expected value of \( cS \) equals \( \sigma \). Specifically, we need to calculate the value of \( c \) for \( n=20 \).
02

Set up the Equation for the Unbiased Estimator

An unbiased estimator for \( \sigma \) means \( E(cS) = \sigma \). Therefore, we can set up the equation: \[ c \cdot E(S) = \sigma \].Substitute the formula for \( E(S) \):\[ c \cdot \left( \sqrt{\frac{2}{n-1}} \frac{\Gamma(n/2)}{\Gamma((n-1)/2)} \right) \sigma = \sigma \].
03

Solve for \( c \)

To isolate \( c \), divide both sides by the expression of \( E(S) \):\[ c = \frac{1}{\sqrt{\frac{2}{n-1}} \frac{\Gamma(n/2)}{\Gamma((n-1)/2)}} \].Then substitute \( n = 20 \) into the equation:\[ c = \frac{1}{\sqrt{\frac{2}{19}} \frac{\Gamma(10)}{\Gamma(9.5)}}. \]
04

Calculate \( c \) for \( n = 20 \)

Using the properties of the Gamma function, calculate:\[ \Gamma(10) = 9! = 362880 \]\[ \Gamma(9.5) = \frac{7 \sqrt{\pi}}{48} \approx 530.788 \] (using a calculator for precise values)Substitute:\[ c = \frac{1}{\sqrt{\frac{2}{19}} \frac{362880}{530.788}} \].Calculate:\[ \sqrt{\frac{2}{19}} \approx 0.3244428 \] \[ \frac{362880}{530.788} \approx 683.424 \]Thus:\[ c \approx \frac{1}{0.3244428 \times 683.424} \approx 4.97749 \].
05

Provide Final Answer

The value of \( c \) which makes \( cS \) an unbiased estimator for \( \sigma \) when \( n = 20 \) is approximately \( 4.97749 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Standard Deviation
The sample standard deviation, often represented as \( S \), is a measure of the amount of variation or dispersion in a set of values. Essentially, it quantifies how much the numbers in a data set deviate from the mean (average) of the data. This is crucial in statistics when you want to understand the spread of your data.
Calculating the sample standard deviation involves a few steps:
  • Find the mean of the data set.
  • Subtract the mean from each data point and square the result.
  • Calculate the average of these squared differences.
  • Finally, take the square root of that average.
Since the sample standard deviation is derived from a sample of the entire population, it is a point estimate and can vary from sample to sample. It is important to know how it serves as an unbiased estimator to adjust for sampling fluctuations.
Gamma Function
The Gamma function is a complex function that extends the factorial function. For a positive integer \( n \), the Gamma function is defined as \( \Gamma(n) = (n-1)! \). However, the Gamma function also allows us to compute values at non-integer points, making it a continuous function over the real and complex numbers.
A notable property of the Gamma function is:
  • \( \Gamma(n+1) = n \times \Gamma(n) \)
This property is useful when deriving functions involving statistics and probability, as shown in solving the problem where \( \Gamma \) values are crucial in calculating constants like \( c \). In our problem, we used the Gamma function to adjust the expected value of \( S \) by understanding the ratio: \( \frac{\Gamma(n/2)}{\Gamma((n-1)/2)} \).
Expected Value
Expected value is a fundamental concept in probability and statistics, often referred to as the mean of a random variable in probability theory. In simple terms, it is the long-run average value of repetitions of the experiment it represents.
For the sample standard deviation \( S \), the expected value \( E(S) \) refers to its average result after many samples, considering the population standard deviation \( \sigma \). It provides insight into the accuracy of \( S \) as an estimate for \( \sigma \).
The formula given for \( E(S) \) in our problem is:\[E(S) = \sqrt{\frac{2}{n-1}} \frac{\Gamma(n/2)}{\Gamma((n-1)/2)} \sigma\]This expression is crucial because it dictates how \( S \) systematically differs from \( \sigma \), allowing adjustments to parameters like \( c \) to achieve an unbiased estimator.
Normalizer Constant
The normalizer constant, \( c \), plays a vital role in statistical estimation, particularly in transforming biased estimates into unbiased ones. In our context, we need \( cS \) to estimate \( \sigma \) without bias.
To find \( c \), we solve for:\[c = \frac{1}{\sqrt{\frac{2}{n-1}} \frac{\Gamma(n/2)}{\Gamma((n-1)/2)}}\]This relation ensures that when \( S \) is multiplied by \( c \), the expected value equals the true standard deviation, \( \sigma \). By substituting \( n = 20 \), we calculated a specific normalizer constant \( c \approx 4.97749 \). This transform balances out the innate bias of \( S \), giving us an accurate, unbiased estimate of \( \sigma \).
Adjusting with such a constant is crucial in honing estimates derived from sample statistics.

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