/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 32 The long run proportion of vehic... [FREE SOLUTION] | 91Ó°ÊÓ

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The long run proportion of vehicles that pass a certain emissions test is \(p\). Suppose that three vehicles are independently selected for testing. Let \(X_{i}=1\) if the \(i\) th vehicle passes the test and \(X_{i}=0\) otherwise \((i=1,2,3)\), and let \(X=X_{1}+\) \(X_{2}+X_{3}\). Use the definition of sufficiency to show that \(X\) is sufficient for \(p\) by obtaining the conditional distribution of the \(X_{i}\) 's given that \(X=x\) for each possible value \(x\). Then generalize by giving an analogous argument for the case of \(n\) vehicles.

Short Answer

Expert verified
The sum \(X\) of test results is sufficient for \(p\) because the conditional distribution given \(X=x\) is uniform and does not depend on \(p\). This holds generally for \(n\) vehicles.

Step by step solution

01

Understanding the Problem

To show that a statistic is sufficient for a parameter, we need to establish that the conditional distribution of data given the statistic is independent of the parameter. Here, we need to find the conditional distribution of \(X_1, X_2, X_3\) given \(X = x\) and show it doesn't depend on \(p\).
02

Set Up the Binomial Distribution

Each \(X_i\) is a Bernoulli random variable with parameter \(p\). The statistic \(X = X_1 + X_2 + X_3\) is the sum of three independent Bernoulli random variables, making it a Binomial random variable with parameters 3 and \(p\): \(X \sim \text{Binomial}(3, p)\).
03

Calculate Conditional Distribution

We need to find \(P(X_1 = x_1, X_2 = x_2, X_3 = x_3 \mid X = x)\), where \(x_1 + x_2 + x_3 = x\). Since all combinations yielding \(x\) are equally likely, the distribution is uniform. Thus, \(P(X_1 = x_1, X_2 = x_2, X_3 = x_3 \mid X = x) = \frac{1}{\binom{3}{x}}\), which doesn’t depend on \(p\).
04

Verify Sufficiency

Since the conditional distribution \(P(X_1 = x_1, X_2 = x_2, X_3 = x_3 \mid X = x)\) is free of \(p\), by the factorization theorem, \(X\) is sufficient for \(p\).
05

Generalize to n Vehicles

Extend the logic to \(n\) vehicles: \(X = X_1 + X_2 + \ldots + X_n\) becomes a Binomial random variable with parameters \(n\) and \(p\). The sample space for \(X = x\) consists of \(\binom{n}{x}\) combinations, making \(P(X_1=x_1, \ldots, X_n=x_n \mid X=x) = \frac{1}{\binom{n}{x}}\). The independence from \(p\) shows \(X\) is sufficient for any \(n\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conditional Distribution
In probability and statistics, understanding conditional distribution is crucial as it describes the probability of an event given that another event has occurred. For this particular problem, we're interested in the conditional distribution of the individual test results of each vehicle, given the total number of vehicles that passed the test.

In the context of our exercise, we define the conditional distribution as:
  • We consider three vehicles, each either passing (1) or failing (0) the emissions test.
  • Given that exactly \( x \) vehicles pass, we need to find the probability distribution of possible outcomes resulting in \( x \) total passes.
Given the total passes \( X = x \), the conditional distribution for the individual outcomes \( X_1, X_2, \) and \( X_3 \) becomes a crucial factor that indicates how the passes are distributed among the vehicles.

Since the conditional probability doesn't depend on \( p \), the outcomes are uniformly likely, shown by the probability \( P(X_1 = x_1, X_2 = x_2, X_3 = x_3 \mid X = x) = \frac{1}{\binom{3}{x}} \). This uniformity in distribution, regardless of the value of \( p \), shows that the total number of passes is a sufficient statistic for \( p \).
Binomial Distribution
The binomial distribution is a probability distribution that summarizes the likelihood that a value will take one of two independent states across a number of trials. In this exercise, each vehicle's test is a trial, and its outcome is a success (passing) or a failure (failing).

The sum \( X = X_1 + X_2 + X_3 \) represents a binomial random variable because it is the result of adding up independent Bernoulli random variables (each with the same probability \( p \) of passing). For 3 vehicles, \( X \) follows a binomial distribution with parameters 3 (the number of trials) and \( p \) (the probability of success in each trial). Formally, it is expressed as:

\[ X \sim \text{Binomial}(3, p) \]

This distribution tells us the probabilities of getting 0, 1, 2, or all 3 vehicles passing the test. It plays a crucial role in determining the sufficiency of the statistic \( X \) because, by summing up results from independent tests, we're effectively compressing all information about \( p \) into a single statistic.
Bernoulli Random Variable
A Bernoulli random variable is a specific type of random variable that has only two possible outcomes, usually labeled as 1 (success) and 0 (failure). In our vehicle emission test scenario, each vehicle's result can either pass or fail, making it a Bernoulli random variable.

Every \( X_i \) in the original problem (where \( i = 1, 2, 3 \)) is a Bernoulli random variable with a probability \( p \) of passing the test. The probability mass function is given by:

\[ P(X_i = x_i) = p^{x_i}(1-p)^{1-x_i} \]

where \( x_i \) is either 0 or 1. This concise representation highlights the binary nature of outcomes for each test.
  • Understanding individual outcomes helps in identifying how these variables can be added together to form a Binomial distribution.
  • The behavior of the Bernoulli variables (their likelihood of success and independence) plays a central role in assessing the sufficiency of the sum \( X = X_1 + X_2 + X_3 \). When combined, they transition into a binomial model which aids in testing the sufficiency for the parameter \( p \).

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