/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 77 A rock specimen from a particula... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A rock specimen from a particular area is randomly selected and weighed two different times. Let \(W\) denote the actual weight and \(X_{1}\) and \(X_{2}\) the two measured weights. Then \(X_{1}=W+E_{1}\) and \(X_{2}=W+E_{2}\), where \(E_{1}\) and \(E_{2}\) are the two measurement errors. Suppose that the \(E_{i}\) 's are independent of each other and of \(W\) and that \(V\left(E_{1}\right)=V\left(E_{2}\right)=\sigma_{E}^{2} .\) a. Express \(\rho\), the correlation coefficient between the two measured weights \(X_{1}\) and \(X_{2}\), in terms of \(\sigma_{W}^{2}\), the variance of actual weight, and \(\sigma_{X}^{2}\), the variance of measured weight. b. Compute \(\rho\) when \(\sigma_{W}=1 \mathrm{~kg}\) and \(\sigma_{E}=.01 \mathrm{~kg}\).

Short Answer

Expert verified
a. \(\rho = \frac{\sigma_W^2}{\sigma_W^2 + \sigma_E^2}\). b. \(\rho \approx 0.9999\).

Step by step solution

01

Understand the formulas and parameters

We are dealing with two measured values, \(X_1\) and \(X_2\), for a rock's weight \(W\). The measurements include errors \(E_1\) and \(E_2\). The given variances are \(V(E_1) = \sigma_E^2\) and \(V(E_2) = \sigma_E^2\). We need to express the correlation \(\rho\) between \(X_1\) and \(X_2\).
02

Express covariance of \(X_1\) and \(X_2\)

Since \(X_1 = W + E_1\) and \(X_2 = W + E_2\), we have the covariance formula:\[\text{Cov}(X_1, X_2) = \text{Cov}(W + E_1, W + E_2) = \text{Cov}(W, W) + \text{Cov}(W, E_2) + \text{Cov}(E_1, W) + \text{Cov}(E_1, E_2)\]Given that \(E_1\) and \(E_2\) are independent of \(W\) and each other, it simplifies to:\[\text{Cov}(X_1, X_2) = \text{Var}(W) = \sigma_W^2\]
03

Calculate variances of measured weights

The variance of \(X_1\) and \(X_2\) is given by:\[V(X_1) = V(X_2) = V(W + E_i) = V(W) + V(E_i) = \sigma_W^2 + \sigma_E^2\]
04

Express correlation \(\rho\)

The correlation \(\rho\) is the covariance of \(X_1\) and \(X_2\) over the product of their standard deviations:\[\rho = \frac{\text{Cov}(X_1, X_2)}{\sqrt{V(X_1)} \sqrt{V(X_2)}}\]Substitute the values:\[\rho = \frac{\sigma_W^2}{\sqrt{(\sigma_W^2 + \sigma_E^2)(\sigma_W^2 + \sigma_E^2)}} = \frac{\sigma_W^2}{\sigma_W^2 + \sigma_E^2}\]
05

Compute \(\rho\) with given values

Using \(\sigma_W = 1\, \text{kg}\) and \(\sigma_E = 0.01\, \text{kg}\), substitute into the formula:\[\rho = \frac{1^2}{1^2 + 0.01^2} = \frac{1}{1.0001} \approx 0.9999\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistics
Statistics is a branch of mathematics dealing with data collection, organization, analysis, interpretation, and presentation. One of its core purposes is to help us understand relationships between data sets, which is precisely what the correlation coefficient does. In our context, we are looking at the measured weights of a rock and trying to find the correlation between these measurements.
- **Data Collection**: Before performing any statistical analysis, data must be gathered. Here, the weights of a rock are measured twice, generating two data points subject to possible errors.
- **Data Analysis**: Analysis involves applying statistical methods to describe, summarize, and draw inferences from data. For weights, understanding variance and correlation between measurements is essential for accuracy assessment.
Through statistics, we can model the errors and understand how accurate and reliable our measurements are in comparison to the actual value of the rock's weight.
Variance
Variance is a statistical measure that describes the spread of numbers in a data set. It represents how far data points are from the mean, or average. In terms of our exercise, variance helps us understand the error in each weight measurement.
- **Actual Weight Variance**: Denoted as \( \sigma_W^2 \), this is the variance of the true weight of the rock without any error. It is the measure of true dispersion.
- **Measurement Error Variance**: Given by \( \sigma_E^2 \), this measures the variability introduced by errors in each measurement process of the rock's weight.
  • Independent variances mean that errors are not affecting each other, remaining consistent across measurements.
Variance matters because it affects the correlation calculation between \( X_1 \) and \( X_2 \), allowing us to infer the overall error impact on our data set.
Covariance
Covariance is a statistical measure of how much two random variables change together. It is related to correlation but is not normalized. In our scenario, covariance helps to understand the relationship between the two measured weights, \( X_1 \) and \( X_2 \).
- **Formula Insight**: Covariance uses the expression \( \text{Cov}(X_1, X_2) = \text{Cov}(W, W) + \text{Cov}(W, E_2) + \text{Cov}(E_1, W) + \text{Cov}(E_1, E_2) \). Because the error terms \( E_1 \) and \( E_2 \) are independent, only \( \text{Var}(W) \) remains.
- **Interpreting Covariance**: A positive covariance indicates that variables tend to increase together. Since we model weight errors as independent, they do not contribute to the measured variables' mutual variation.
Understanding covariance helps us to determine the strength and direction of a linear relationship between two variables.
Measurement Errors
Measurement errors are discrepancies between the measured values and the true values. In our case, errors \( E_1 \) and \( E_2 \) in the measured rock weights can impact data analysis. Understanding these errors is critical to improving measurement accuracy and reliability.
- **Error Components**: Measurement errors can arise from various sources such as instrument calibration, environmental conditions or human error.
  • Variance \( \sigma_E^2 \) quantifies these errors statistically, allowing for easier adjustments in data analysis.
Independent errors ensure that flaws in one measurement do not affect the other, making it simpler to isolate the actual source of error.
Recognizing and analyzing measurement errors ensures that statistical results accurately reflect true values, laying the foundation for robust data-driven decisions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A company maintains three offices in a region, each staffed by two employees. Information concerning yearly salaries (1000's of dollars) is as follows: $$ \begin{array}{lcccccc} \text { Office } & 1 & 1 & 2 & 2 & 3 & 3 \\ \text { Employee } & 1 & 2 & 3 & 4 & 5 & 6 \\ \text { Salary } & 29.7 & 33.6 & 30.2 & 33.6 & 25.8 & 29.7 \end{array} $$ a. Suppose two of these employees are randomly selected from among the six (without replacement). Determine the sampling distribution of the sample mean salary \(\bar{X}\). b. Suppose one of the three offices is randomly selected. Let \(X_{1}\) and \(X_{2}\) denote the salaries of the two employees. Determine the sampling distribution of \(X\). c. How does \(E(X)\) from parts (a) and (b) compare to the population mean salary \(\mu\) ?

Let \(\mu\) denote the true \(\mathrm{pH}\) of a chemical compound. A sequence of \(n\) independent sample pH determinations will be made. Suppose each sample \(\mathrm{pH}\) is a random variable with expected value \(\mu\) and standard deviation .1. How many determinations are required if we wish the probability that the sample average is within \(.02\) of the true \(\mathrm{pH}\) to be at least \(.95\) ? What theorem justifies your probability calculation?

The tip percentage at a restaurant has a mean value of \(18 \%\) and a standard deviation of \(6 \%\). a. What is the approximate probability that the sample mean tip percentage for a random sample of 40 bills is between \(16 \%\) and \(19 \%\) ? b. If the sample size had been 15 rather than 40 , could the probability requested in part (a) be calculated from the given information?

The difference of two independent normal variables itself has a nomal distribution. Is it true that the difference between two independent chi- squared variables has a chi-squared distribution? Explain.

Let \(X\) have an \(F\) distribution with \(v_{1}\) numerator df and \(v_{2}\) denominator df. a. Determine the mean value of \(X\). b. Determine the variance of \(X\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.