/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 76 a. Use the general formula for t... [FREE SOLUTION] | 91Ó°ÊÓ

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a. Use the general formula for the variance of a linear combination to write an expression for \(V(a X+Y)\). Then let \(a=\sigma_{Y} / \sigma_{X}\), and show that \(\rho \geq-1\). [Hint: Variance is always \(\geq 0\), and \(\left.\operatorname{Cov}(X, Y)=\sigma_{X} \cdot \sigma_{Y} \cdot \rho \cdot\right]\) b. By considering \(V(a X-Y)\), conclude that \(\rho \leq 1 .\) c. Use the fact that \(V(W)=0\) only if \(W\) is a constant to show that \(\rho=1\) only if \(Y=a X+b\).

Short Answer

Expert verified
Variance analysis shows \(-1 \leq \rho \leq 1\), and \(\rho = 1\) if \(Y = aX + b\).

Step by step solution

01

Variance of a Linear Combination

The formula for the variance of a linear combination, say \( aX + Y \), is given by:\[V(aX + Y) = a^2 V(X) + V(Y) + 2a \cdot \text{Cov}(X, Y)\]This uses the properties of variance and covariance: \(V(X)\) is the variance of \(X\), \(V(Y)\) is the variance of \(Y\), and \(\text{Cov}(X, Y)\) is the covariance of \(X\) and \(Y\).
02

Substitute and Simplify

Substitute \(a = \frac{\sigma_Y}{\sigma_X}\) into the formula:\[V\left(\frac{\sigma_Y}{\sigma_X}X + Y\right) = \left(\frac{\sigma_Y}{\sigma_X}\right)^2 \sigma_X^2 + \sigma_Y^2 + 2 \cdot \frac{\sigma_Y}{\sigma_X} \cdot \text{Cov}(X, Y)\]This simplifies to:\[\sigma_Y^2 + \sigma_Y^2 + 2 \cdot \sigma_Y \cdot \rho \cdot \sigma_Y\]\[= 2\sigma_Y^2(1 + \rho)\]
03

Use Positive Variance Property

Since variance is always non-negative, set the expression:\[2\sigma_Y^2(1 + \rho) \geq 0\]Since \(\sigma_Y^2\) is positive, it implies:\[1 + \rho \geq 0\]Thus, \(\rho \geq -1\).
04

Consider Variance of \(aX - Y\)

For \(V(aX - Y)\), use the variance formula:\[V(aX - Y) = a^2 V(X) + V(Y) - 2a \cdot \text{Cov}(X, Y)\]Substitute \(a = \frac{\sigma_Y}{\sigma_X}\), obtaining:\[\sigma_Y^2 + \sigma_Y^2 - 2 \cdot \sigma_Y \cdot \rho \cdot \sigma_Y = 2\sigma_Y^2(1 - \rho)\]Set \(V(aX - Y) \geq 0\), leading to:\[1 - \rho \geq 0\]Thus, \(\rho \leq 1\).
05

Condition for \(V(W) = 0\)

For \(V(aX - Y) = 0\), the expression becomes constant, i.e., no variance.This implies:\[\sigma_Y^2(1 - \rho) = 0\]If \(\rho = 1\), it means \(Y\) is perfectly linearly related to \(X\) as \(Y = aX + b\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Variance
Variance measures how much values in a set differ from the average value. It is an important statistical concept used to describe the spread or variability in a distribution.
Understanding variance helps in understanding how far individual numbers in a dataset are from the mean, illustrating whether values are closely bunched together or spread out.
When dealing with linear combinations of random variables, such as in the expression \(V(a X + Y)\), variance helps explain the total variability by considering the variances of individual components and their covariances.
  • The variance of \(aX + Y\) is calculated by the formula: \[V(aX + Y) = a^2 V(X) + V(Y) + 2a \cdot \text{Cov}(X, Y)\]
  • This formula considers the additive effects of variances and the interactive effect captured by covariance.
To solve the exercise, we use the properties of variance and substitute \(a = \frac{\sigma_Y}{\sigma_X}\), where \(\sigma_Y\) and \(\sigma_X\) are the standard deviations of \(Y\) and \(X\) respectively. This substitution illustrates how variance keeps its non-negative nature even when dealing with linear combinations.
Covariance
Covariance is a measure of how much two random variables change together. It's a helpful statistic when you want to determine the relationship between two variables.
If covariance is positive, it implies that as one variable increases, the other tends to increase as well. Conversely, a negative covariance indicates that as one variable increases, the other tends to decrease.
The covariance is crucial in understanding the behavior of the sum of variables, especially in the context of variance for linear combinations like \(aX + Y\). Covariance is used in the formula:
  • Covariance between two variables \(X\) and \(Y\) is calculated as: \[\text{Cov}(X, Y) = \sigma_X \cdot \sigma_Y \cdot \rho\]
  • Here, \(\rho\) represents the correlation coefficient, which standardizes covariance.
In the variance formula, covariance accounts for the interaction between \(X\) and \(Y\), affecting their combined variability. Understanding whether \(1 + \rho \geq 0\) helps set boundaries for \(\rho\), ensuring that there is a logical relationship between the fields of data.
Correlation Coefficient
The correlation coefficient, often denoted as \(\rho\), provides a bounded measure of the strength and direction of a linear relationship between two random variables.
This statistic lies between -1 and 1, where:
  • A \(\rho\) value of 1 indicates a perfect positive linear relationship.
  • A \(\rho\) value of -1 signifies a perfect negative linear relationship.
  • A \(\rho\) value around 0 means no linear relationship.
In the context of the exercise, demonstrating \(-1 \leq \rho \leq 1\) ensures that variance calculations remain consistent with statistical expectations.
When variance measures such as \(V(aX - Y)\) show inequality constraints (\(1 - \rho \geq 0\)), they help justify the logical limits for \(\rho\).The ultimate condition \(\rho = 1\) signifies \(Y\) precisely follows a linear equation \(Y = aX + b\), signifying a direct proportionality. Understanding these constraints on \(\rho\) allows you to predict relationships and dependencies between variables accurately.

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Most popular questions from this chapter

Let \(A\) denote the percentage of one constituent in a randomly selected rock specimen, and let \(B\) denote the percentage of a second constituent in that same specimen. Suppose \(D\) and \(E\) are measurement errors in determining the values of \(A\) and \(B\) so that measured values are \(X=A+D\) and \(Y=B+E\), respectively. Assume that measurement errors are independent of each other and of actual values. a. Show that $$ \begin{gathered} \operatorname{Corr}(X, Y)=\operatorname{Corr}(A, B) \cdot \sqrt{\operatorname{Corr}\left(X_{1}, X_{2}\right)} \\ \cdot \sqrt{\operatorname{Corr}\left(Y_{1}, Y_{2}\right)} \end{gathered} $$ where \(X_{1}\) and \(X_{2}\) are replicate measurements on the value of \(A\), and \(Y_{1}\) and \(Y_{2}\) are defined analogously with respect to \(B\). What effect does the presence of measurement error have on the correlation? b. What is the maximum value of \(\operatorname{Corr}(X, Y)\) when \(\operatorname{Corr}\left(X_{1}, X_{2}\right)=.8100, \operatorname{Corr}\left(Y_{1}, Y_{2}\right)=\) \(.9025 ?\) Is this disturbing?

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