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The number of individuals arriving at a post office to mail packages during a certain period is a Poisson random variable \(X\) with mean value 20 . Independently of the others, any particular customer will mail either \(1,2,3\), or 4 packages with probabilities \(.4, .3, .2\), and .1, respectively. Let \(Y\) denote the total number of packages mailed during this time period. a. Find \(E(Y \mid X=x)\) and \(V(Y \mid X=x)\). b. Use part (a) to find \(E(Y)\). c. Use part (a) to find \(V(Y)\).

Short Answer

Expert verified
a. \(E(Y \mid X=x) = 2x\), \(V(Y \mid X=x) = x\); b. \(E(Y) = 40\); c. \(V(Y) = 100\).

Step by step solution

01

Understand Conditional Expectation and Variance

First, recognize that we are given a conditional scenario where the number of individuals, described by the random variable \(X\), follows a Poisson distribution with a mean of 20. Each individual mails a certain number of packages \(Y\), which differ in probability. We need to use this information to find conditional expectations first: \(E(Y \mid X=x)\) and \(V(Y \mid X=x)\).
02

Calculate Expected Number of Packages per Person

For any one individual, expected number of packages mailed, \(E(Z)\), can be computed as follows: \[E(Z) = 1 \times 0.4 + 2 \times 0.3 + 3 \times 0.2 + 4 \times 0.1 = 0.4 + 0.6 + 0.6 + 0.4 = 2.0.\]
03

Find E(Y | X=x)

Given the expected number of packages per person, the conditional expectations for all individuals \(x\) follow as: \[E(Y \mid X=x) = x \cdot E(Z) = 2x.\]
04

Calculate Variance of Packages per Person

Next, compute the variance of packages for any one individual, \(V(Z)\). Since each outcome is associated with a probability, we use:\[V(Z) = (1^2 \cdot 0.4 + 2^2 \cdot 0.3 + 3^2 \cdot 0.2 + 4^2 \cdot 0.1) - (E(Z))^2 = (0.4 + 1.2 + 1.8 + 1.6) - 4 = 1.\]
05

Compute V(Y | X=x)

Given that variance adds up linearly for independent random variables, the conditional variance of the total number of packages mailed is:\[V(Y \mid X=x) = x \cdot V(Z) = x.\]
06

Find E(Y) Using Law of Total Expectation

Using the expected value found previously:\[E(Y) = E[E(Y \mid X)] = E[2X] = 2E(X) = 2 \times 20 = 40.\]
07

Find V(Y) Using Law of Total Variance

Use the law of total variance:\[V(Y) = E[V(Y \mid X)] + V[E(Y \mid X)].\]Given \(V(Y \mid X) = X\) and \(E(Y \mid X) = 2X\), calculate:\[E[V(Y \mid X)] = E(X) = 20,\]\[V[E(Y \mid X)] = V(2X) = 4V(X) = 4 \times 20 = 80.\]Thus, \[V(Y) = 20 + 80 = 100.\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conditional Expectation
Conditional expectation involves finding the expected value of a random variable given certain conditions or events. In this exercise, we focus on the scenario where the number of visitors at a post office, denoted as the random variable \(X\), is known. Each visitor sends a random number of packages \(Y\) following certain probabilities.

The goal is to find \(E(Y \mid X=x)\), the expected number of packages sent when exactly \(x\) people have visited. Since each person independently mails packages with a specific average (computed from their probabilities), we multiply the constant expected packages per person, \(E(Z) = 2\), by the number of people \(x\). This results in the formula: \(E(Y \mid X=x) = 2x\).

Conditional expectation allows us to predict the average outcome by simplifying it based on known variables.
Conditional Variance
Conditional variance helps measure how much the number of packages might deviate from their expected number when a known condition is present, such as a specific number of visitors. In this context, we need to determine \(V(Y \mid X=x)\), the variance of the number of packages mailed for a given number of people \(x\).

Just like with conditional expectation, we first compute the variance of packages sent by one individual \(V(Z) = 1\). Since each visitor's acts are independent, variations in package-sending behavior aggregate linearly. Therefore, by multiplying this variance by the number of visitors \(x\), we get \(V(Y \mid X=x) = x\).

Conditional variance helps us understand the potential fluctuations in a result even when a certain aspect is fixed.
Law of Total Expectation
The Law of Total Expectation is a powerful tool that allows us to calculate the overall expected value when multiple scenarios or partitions exist, as it aggregates expected values over all possible conditions. In our example, this law helps find the total expected number of packages mailed \(E(Y)\).

Using the conditional expectation derived earlier \(E(Y \mid X)\), we apply the law: \(E(Y) = E[E(Y \mid X)] = E[2X] = 2E(X)\). Since \(E(X) = 20\) for our Poisson-distributed visitors, \(E(Y) = 40\).

By dealing with sub-expectations within each condition and summing them up, this law reveals the complete expected outcome.
Law of Total Variance
The Law of Total Variance breaks down a variance problem considering both within-condition variance and between-condition variance. This law is essential when trying to find \(V(Y)\), the total variance of packages sent by all visitors.

According to this law:
  • 1. Calculate \(E[V(Y \mid X)]\), the expected conditional variance, which in our problem is simply \(E(X) = 20\).
  • 2. Determine \(V[E(Y \mid X)]\), which reflects the variance across the expectations for each condition. Here, since \(E(Y \mid X) = 2X\), it becomes \(4V(X) = 80\).

Combine these to acquire \(V(Y) = E[V(Y \mid X)] + V[E(Y \mid X)] = 20 + 80 = 100\).
This law ties together within-condition variation and cross-condition variance, offering a comprehensive variance assessment.

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