/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 A surveyor wishes to lay out a s... [FREE SOLUTION] | 91Ó°ÊÓ

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A surveyor wishes to lay out a square region with each side having length \(L\). However, because of measurement error, he instead lays out a rect angle in which the north-south sides both have length \(X\) and the east-west sides both have length \(Y\). Suppose that \(X\) and \(Y\) are independent and that each is uniformly distributed on the interva \([L-A, L+A]\) (where \(0

Short Answer

Expert verified
The expected area is \(L^2\).

Step by step solution

01

Understand the Uniform Distribution

The variables \(X\) and \(Y\) represent the lengths of the north-south and east-west sides of the rectangle, respectively. Both \(X\) and \(Y\) are uniformly distributed on the interval \([L-A, L+A]\). This means that any value within this interval is equally likely for both \(X\) and \(Y\).
02

Set the Interval for Uniform Distribution

For a uniformly distributed variable across the interval \([L-A, L+A]\), the probability density function is constant. The length of this interval is \(2A\), so the probability density function is \(f(x) = \frac{1}{2A}\) for \(x \in [L-A, L+A]\). Similarly, the same is true for \(Y\).
03

Define the Expected Area

The expected area of the rectangle is the product of the expected values of \(X\) and \(Y\). That is, \(E[XY] = E[X] \times E[Y]\) since \(X\) and \(Y\) are independent.
04

Calculate the Expected Value for Uniform Variable

For a uniformly distributed variable \(Z\) on \([L-A, L+A]\), the expected value is the midpoint of the interval. Therefore, \(E[X] = E[Y] = \frac{(L-A) + (L+A)}{2} = L\).
05

Compute the Expected Area of the Rectangle

Now, since \(E[X] = L\) and \(E[Y] = L\), the expected area of the rectangle becomes: \[E[XY] = E[X] \times E[Y] = L \times L = L^2.\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Expected Value
The expected value, often referred to as the mean, is a fundamental concept in probability and statistics. It provides a measure of the central tendency of a random variable. In simpler terms, it's what we "expect" to happen on average over multiple trials. When dealing with a uniformly distributed random variable, calculating the expected value is straightforward.

For a uniform distribution over an interval \[a, b\], every outcome within the interval has an equal probability of occurring, and the expected value is the midpoint of the interval. Mathematically, this can be expressed as:
  • \( E[Z] = \frac{a + b}{2} \)
In our context, both \({X}\) and \({Y}\) are uniformly distributed over the interval \[L-A, L+A\]. Thus, the expected value for both variables \((E[X]\) and \({E[Y]})\) is \({L}\), because:
  • \( E[X] = E[Y] = \frac{(L-A) + (L+A)}{2} = L \)

These expected values play a crucial role in determining the expected area of the rectangle, as they help us understand the average length expected for each side.
Rectangle Area
The area of a rectangle is calculated by multiplying its length by its width. In mathematical terms, if one side (length) is represented by \({X}\) and the other (width) by \({Y}\), the area \({A}\) is computed as:
  • \( A = X \times Y \)
When these side lengths are random variables, the concept of expected area becomes important.

The expected area is given by the product of the expected values of the lengths of the sides. For independent variables, the rule simplifies to multiplying their individual expected values:
  • \( E[XY] = E[X] \times E[Y] \)
Since we know that \({E[X] = L}\) and \({E[Y] = L}\), the expected area is calculated as:
  • \( E[XY] = L \times L = L^2 \)
This represents the average area you can expect, even when the side lengths vary due to measurement errors.
Independent Variables
In probability and statistics, independence between random variables is a key concept. Two variables are said to be independent if the occurrence of one does not affect the probability of occurrence of the other. This concept is crucial when calculating combined probabilities or expected values, as it simplifies computations significantly.

When dealing with independent random variables \({X}\) and \({Y}\), especially in the context of expected values, the following property holds true:
  • \( E[XY] = E[X] \times E[Y] \)
This property is a direct result of independence and allows us to easily find the expected value of a product of two independent random variables.

In the problem at hand, \({X}\) and \({Y}\) are independent, which means the calculation of the expected area of the rectangle simplifies as follows:
  • Since \({E[X] = L}\) and \({E[Y] = L}\), the expected area is simply \({L^2}\).
Understanding independence helps us make these simplifications and accurately assess the expected outcomes in probabilistic situations.

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Most popular questions from this chapter

Show that if \(Y=a X+b(a \neq 0)\), then \(\operatorname{Corr}(X, Y)=\) \(+1\) or \(-1\). Under what conditions will \(\rho=+1\) ?

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Let \(X\) represent a measurement error. It is natural to assume that the pdf \(f(x)\) is symmetric about 0 , so that the density at a value \(-c\) is the same as the density at \(c\) (an error of a given magnitude is equally likely to be positive or negative). Consider a random sample of \(n\) measurements, where \(n=\) \(2 k+1\), so that \(Y_{k+1}\) is the sample median. What can be said about \(E\left(Y_{k+1}\right)\) ? If the \(X\) distribution is symmetric about some other value, so that value is the median of the distribution, what does this imply about \(E\left(Y_{k+1}\right)\) ? [Hints: For the first question, symmetry implies that \(1-F(x)=P(X>x)=P(X<-x)=F(-x) .\) For the second question, consider \(W=X-\tilde{\mu}\); what is the median of the distribution of \(W ?]\)

Consider a sample of size \(n=3\) from the standard normal distribution, and obtain the expected value of the largest order statistic. What does this say about the expected value of the largest order statistic in a sample of this size from any normal distribution? [Hint: With \(\phi(x)\) denoting the standard normal pdf, use the fact that \((d / d x) \phi(x)=-x \phi(x)\) along with integration by parts.]

According to the Mars Candy Company, the longrun percentages of various colors of M\&M milk chocolate candies are as follows: \(\begin{array}{llllll}\text { Blue: } & \text { Orange: } & \text { Green: } & \text { Yellow: } & \text { Red: } & \text { Brown: } \\ 24 \% & 20 \% & 16 \% & 14 \% & 13 \% & 13 \%\end{array}\) a. In a random sample of 12 candies, what is the probability that there are exactly two of each color? b. In a random sample of 6 candies, what is the probability that at least one color is not included? c. In a random sample of 10 candies, what is the probability that there are exactly 3 blue candies and exactly 2 orange candies? d. In a random sample of 10 candies, what is the probability that there are at most 3 orange candies? [Hint: Think of an orange candy as a success and any other color as a failure.] e. In a random sample of 10 candies, what is the probability that at least 7 are either blue, orange, or green?

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