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In studies of anticancer drugs it was found that if mice are injected with cancer cells, the survival time can be modeled with the exponential distribution. Without treatment the expected survival time was \(10 \mathrm{~h}\). What is the probability that a. A randomly selected mouse will survive at least \(8 \mathrm{~h}\) ? At most \(12 \mathrm{~h}\) ? Between 8 and \(12 \mathrm{~h}\) ? b. The survival time of a mouse exceeds the mean value by more than 2 standard deviations? More than 3 standard deviations?

Short Answer

Expert verified
Probabilities: At least 8h = 0.4493, at most 12h = 0.6988, between 8-12h = 0.1481; Exceeds mean by >2 SDs = 0.0498, >3 SDs = 0.0183.

Step by step solution

01

Understand the Exponential Distribution

The exponential distribution is often used to model the time until an event occurs, such as the survival time of mice in this problem. If a random variable \(X\) follows the exponential distribution with mean \(\mu = 10\), then the probability density function (pdf) is given by \(f(x) = \frac{1}{\mu} e^{-x/\mu}\) for \(x \geq 0\).
02

Calculate the Rate Parameter

The exponential distribution's rate parameter \(\lambda\) is the reciprocal of the mean \(\mu\). Thus, for this distribution, \(\lambda = \frac{1}{10}\).
03

Calculate Survival Probabilities (Part a)

For a randomly selected mouse to survive at least 8 hours, we need to calculate \(P(X \geq 8)\). The survival function for the exponential distribution is \(S(x) = e^{-x/\mu}\). So, \(P(X \geq 8) = e^{-8/10} \approx 0.4493\). To find the probability that a mouse survives at most 12 hours, we use \(P(X \leq 12) = 1 - P(X \geq 12) = 1 - e^{-12/10} \approx 0.6988\).For the probability between 8 and 12 hours, subtract the two results: \(P(8 \leq X \leq 12) = P(X \leq 12) - P(X \leq 8) = (1 - e^{-12/10}) - (1 - e^{-8/10}) \approx 0.6988 - 0.5507 = 0.1481\).
04

Standard Deviation of the Exponential Distribution

The standard deviation \(\sigma\) of an exponential distribution is equal to its mean \(\mu\). Therefore, \(\sigma = 10\).
05

Calculate Exceeding Probabilities (Part b)

To find the probability that survival time exceeds the mean by more than 2 standard deviations, we calculate \(P(X > 10 + 2 \times 10) = P(X > 30) = e^{-30/10} = e^{-3} \approx 0.0498\).To find the probability for more than 3 standard deviations, \(P(X > 10 + 3 \times 10) = P(X > 40) = e^{-40/10} = e^{-4} \approx 0.0183\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Anticancer Drug Studies
In anticancer drug studies, researchers aim to understand how long subjects, such as mice or humans, can survive after being administered cancer cells or treatment. These studies are crucial for developing effective drugs that can extend survival times and improve the quality of life. The survival time can be modeled using statistical distributions, which provides a systematic way to predict and analyze outcomes.

One common model used in these studies is the exponential distribution, as in the case of mice injected with cancer cells. This distribution is particularly suitable because it helps researchers understand the time until death, which is a significant interest in these studies.

Through this model, the effectiveness of anticancer therapies can be rigorously tested by comparing survival times under different conditions, such as with or without drug interventions. Statistical insights from these models allow scientists to make informed decisions about potential anticancer drug candidates and their likelihood of success in clinical settings.
Probability Calculation
Probability calculation is a critical component in analyzing the likelihood of certain outcomes using statistical models. The exponential distribution, defined by its probability density function (pdf) and survival function, facilitates these calculations.

In the context of the exponential distribution, the survival function, denoted as \(S(x)\), is calculated using the formula \(S(x) = e^{-x/\mu}\), where \(\mu\) is the mean survival time. This function is key to determining the probability of events, such as the survival of mice up to or beyond a certain duration.

For example, to compute the probability that a mouse survives at least 8 hours, one would evaluate \(S(8)\). To find the probability for a duration range, like surviving between 8 to 12 hours, subtract the probabilities calculated for \(12\) hours and \(8\) hours respectively. Such calculations allow researchers to quantify survival probabilities, helping them understand treatment efficacy and identify significant differences between experimental groups.
Survival Analysis
Survival analysis involves using statistical methods to analyze and interpret the duration until one or more events—such as death or relapse—occur. It is widely used in biomedical research, where the timing of such events is crucial for determining the efficacy of treatments like anticancer drugs.

The exponential distribution, due to its memoryless property, is a natural fit for survival analysis in cases where the event of interest occurs continuously over time, such as survival time in mice injected with cancer cells. This model allows researchers to evaluate the treatment impact, assess patient prognosis, and make data-driven decisions in clinical trials.

By utilizing survival analysis, researchers convert complex biological data into searchable and meaningful insights, making it possible to tailor treatments more effectively. The knowledge gained from these methods can guide the development of cancer therapies and improve understanding of disease progression.
Standard Deviation in Exponential Distribution
The standard deviation provides insight into the variability of data points relative to the mean, and it plays a significant role in interpreting the spread of data within an exponential distribution.

In the exponential distribution, the standard deviation (\(\sigma\)) is equal to the mean (\(\mu\)). This property makes it unique among statistical distributions because the spread or dispersion of the distribution is directly tied to its central value. For a mean survival time of 10 hours, the standard deviation also equals 10 hours.

This direct relationship simplifies the calculation of probabilities for extreme events, such as those exceeding certain multiples of the standard deviation from the mean. Researchers can easily determine, for instance, the probability of survival times falling outside typical ranges, thereby identifying anomalies or outliers that may indicate a successful or unsuccessful effect of an intervention. Understanding this concept is instrumental in predicting survival outcomes with greater confidence.

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