/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 An ecologist wishes to mark off ... [FREE SOLUTION] | 91Ó°ÊÓ

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An ecologist wishes to mark off a circular sampling region having radius \(10 \mathrm{~m}\). However, the radius of the resulting region is actually a random variable \(R\) with pdf $$ f(r)=\left\\{\begin{array}{cl} \frac{3}{4}\left[1-(10-r)^{2}\right] & 9 \leq r \leq 11 \\ 0 & \text { otherwise } \end{array}\right. $$ What is the expected area of the resulting circular region?

Short Answer

Expert verified
Evaluate the integral \( E[A] = \pi \int_{9}^{11} r^2 \left(\frac{3}{4}(1-(10-r)^2)\right) \ dr \) to find the expected area.

Step by step solution

01

Determine the Formula for the Area

The area of a circle with radius \( r \) is given by the formula: \[ A = \pi r^2 \] We will use this formula to find the expected area of the region.
02

Set Up the Expected Value Integral

The expected value \( E[A] \) of the area is calculated using the probability density function (pdf) \( f(r) \). Thus, the expected value of the area is given by the integral:\[ E[A] = \int_{9}^{11} \pi r^2 f(r) \ dr \] We need to substitute the given pdf into this integral.
03

Substitute PDF into Integral

The pdf is given as \( f(r) = \frac{3}{4}[1-(10-r)^2] \) for \( 9 \leq r \leq 11 \). Substitute this into the expected value integral:\[ E[A] = \pi \int_{9}^{11} r^2 \left(\frac{3}{4}(1-(10-r)^2)\right) \ dr \]
04

Simplify the Integral Expression

First, simplify the term \((10-r)^2\) in the expression:\( (10-r)^2 = 100 - 20r + r^2 \).Thus, the integral becomes:\[ E[A] = \pi \int_{9}^{11} r^2 \left(\frac{3}{4}(1 - 100 + 20r - r^2)\right) \ dr \]Which simplifies to:\[ \frac{3\pi}{4} \left( \int_{9}^{11} (r^2 - 100r^2 + 20rr^2 - r^4) \, dr \right) \].
05

Evaluate the Integral

Break down the integral into simpler components:\[ \int_{9}^{11} (r^2 - 100r^2 + 20r^3 - r^4) \, dr \]Compute each part individually:- \( \int_{9}^{11} r^2 \, dr \)- \( -100 \int_{9}^{11} r^2 \, dr \)- \( 20 \int_{9}^{11} r^3 \, dr \)- \( -\int_{9}^{11} r^4 \, dr \)Then combine these to form the complete integral evaluation. The result will be the expected area after plugging back these evaluated values into \frac{3\pi}{4}. This computation can be intensive and may utilize tabulated antiderivatves or computational software.
06

Final Calculation

After evaluating and adding all integral components and multiplying by \(\frac{3\pi}{4}\), you obtain a numerical value for the expected area of the circle. This can be simplified further if possible.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Density Function
A Probability Density Function (PDF) is a mathematical function that describes the likelihood of a continuous random variable taking on different values. It provides a way to visualize how probabilities are distributed over a range of possible outcomes. In this exercise, we're dealing with a random variable representing the radius of a circle. The PDF for our random variable, denoted as \( f(r) \), specifies how likely different radius values are within the interval from 9 to 11 meters. This PDF is crucial for calculating the expected area of the circular region since it helps us understand and integrate the probabilities over the desired interval. Remember, the area under the curve of the PDF over the interval gives the total probability, which should equal 1.
Key elements of a PDF include:
  • The PDF is positive for all values of the random variable.
  • The integral of the PDF over its range equals 1, representing the total probability.
  • It allows us to compute expected values by weighting possible outcomes based on their likelihood of occurring.
Area of Circle
Understanding the area of a circle is essential for solving this exercise. The formula for calculating the area when given a radius \( r \) is \( A = \pi r^2 \). This formula stems from the geometrical properties of a circle, where \( \pi \) is a mathematical constant approximately equal to 3.14159, representing the ratio of a circle's circumference to its diameter.
Using this formula, we can determine the area of any circle as long as the radius is known. In our exercise, the radius is not a fixed number but a random variable. To find the expected area, this formula is integrated into calculating the expected value, which quantitatively expresses the average area of the circle based on varying radii according to their probabilities.
Integration
Integration is a fundamental concept in calculus used to calculate areas under curves, among many other applications. When we talk about integration in this exercise, we are referring to the process of finding the expected value of the area using a definite integral.
The integral setup, \( E[A] = \pi \int_{9}^{11} r^2 f(r) \, dr \), involves integrating over the range of radii from 9 to 11 meters, where each component \( r^2f(r) \) represents an "area contribution" weighted by the probability density \( f(r) \). In simpler terms, integration helps us sum up these weighted area contributions across all possible radii to find an overall expected value.
  • Integration helps resolve continuous probabilities, turning the continuous curve of a PDF into a finite area.
  • It allows us to handle complex expressions systematically by breaking them into simpler components.
  • Understanding how to simplify and compute integrals is crucial for solving many advanced mathematical problems.
Random Variable
A random variable is a variable whose possible values are outcomes of a random phenomenon. In our context, the random variable is the radius \( R \) of the circular sampling region, which varies between 9 and 11 meters. Because it doesn't take a single fixed value but can assume a range of values, it is described probabilistically.
Random variables can be discrete or continuous. In this exercise, since the radius can take any value within the interval \([9, 11]\), it is considered a continuous random variable.
Important points about random variables include:
  • They are used to model uncertainty and variability in statistical and probabilistic contexts.
  • The possible outcomes can be mapped using a probability distribution, like a PDF for continuous variables.
  • Understanding their behavior is crucial for predicting outcomes and making informed decisions based on data.
Mastering the concept of random variables aids in various fields, such as statistics, data analysis, and any domain requiring probabilistic modeling.

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