/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 127 Let \(X=\) the time it takes a r... [FREE SOLUTION] | 91Ó°ÊÓ

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Let \(X=\) the time it takes a read/write head to locate a desired record on a computer disk memory device once the head has been positioned over the correct track. If the disks rotate once every \(25 \mathrm{~ms}\), a reasonable assumption is that \(X\) is uniformly distributed on the interval \([0,25]\). a. Compute \(P(10 \leq X \leq 20)\). b. Compute \(P(X \geq 10)\). c. Obtain the cdf \(F(X)\).

Short Answer

Expert verified
a. 0.4, b. 0.6, c. \(F(x) = \frac{x}{25}\) for \(0 \leq x \leq 25\).

Step by step solution

01

Understand Problem

We are given a uniform distribution problem. The random variable \(X\) is uniformly distributed on the interval \([0, 25]\). This means every value within this interval is equally likely.
02

Define Uniform Distribution

A uniform distribution on the interval \([a, b]\) has a probability density function (pdf) of \(f(x) = \frac{1}{b-a}\) for \(a \leq x \leq b\). Here, \(a=0\) and \(b=25\). Thus \(f(x) = \frac{1}{25}\).
03

Compute P(10 ≤ X ≤ 20)

To compute \(P(10 \leq X \leq 20)\), we need to find the area under the pdf from \(x=10\) to \(x=20\). \[P(10 \leq X \leq 20) = \int_{10}^{20} \frac{1}{25} \, dx = \frac{1}{25} \times (20-10) = \frac{10}{25} = 0.4.\]
04

Compute P(X ≥ 10)

For \(P(X \geq 10)\), calculate the area under the pdf from \(x=10\) to \(x=25\). \[P(X \geq 10) = \int_{10}^{25} \frac{1}{25} \, dx = \frac{1}{25} \times (25-10) = \frac{15}{25} = 0.6.\]
05

Find Cumulative Distribution Function (CDF)

The cumulative distribution function \(F(x)\) for a uniform distribution on \([0,25]\) is given by \(F(x) = \frac{x-a}{b-a}\) for \(a \leq x \leq b\). Therefore, since \(a=0\) and \(b=25\), \(F(x) = \frac{x}{25}\) for \(0 \leq x \leq 25\). For \(x < 0\), \(F(x) = 0\), and for \(x > 25\), \(F(x) = 1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Density Function
A Probability Density Function (PDF) is a core concept in the study of continuous random variables, especially in distributions like the uniform distribution. It represents the likelihood of any outcome within a given range and is used to define probabilities over continuous intervals.
In the case of a uniform distribution on the interval \(a, b\), every value within this range is equally likely. Hence, the PDF for a uniform distribution between \(a\) and \(b\) is given by:
  • \( f(x) = \frac{1}{b-a} \) for \( a \leq x \leq b \)
  • \( f(x) = 0 \) for \(x < a\) or \(x > b\)
This means that any outcome between \(0\) and \(25\) for our given problem is equally probable and has the same density value of \(\frac{1}{25}\).
In practice, PDFs do not give probabilities for specific points but rather for intervals, making them crucial for calculating probabilities for continuous random variables.
Cumulative Distribution Function
The Cumulative Distribution Function (CDF) is another critical concept that relates closely to the PDF. While the PDF tells us about densities, the CDF provides the probability that a random variable \(X\) is less than or equal to a particular value \(x\).
For a uniform distribution, the CDF smoothly accumulates these probabilities over the interval. It is given by:
  • \( F(x) = \frac{x-a}{b-a} \) for \( a \leq x \leq b \)
  • \( F(x) = 0 \) for \(x < a\)
  • \( F(x) = 1 \) for \(x > b\)
In the example of our exercise, with \(a = 0\) and \(b = 25\), the CDF becomes \(F(x) = \frac{x}{25}\) for \(0 \leq x \leq 25\). This means if you wanted to find the probability of \(X\) being less than or equal to a particular time, you read the CDF value directly at that time. Understanding the CDF helps in predicting cumulative probabilities and understanding the distribution's behavior over the given interval.
Integration of Probability
Integration is a fundamental mathematical tool that helps us find probabilities for continuous distributions by determining the area under the curve of the Probability Density Function (PDF). In the context of our exercise on uniform distribution, we use integration to compute specific probabilities.
To find the probability that \(X\) falls within some range \([c, d]\), we calculate the integral of the PDF across that interval:
  • \( P(c \leq X \leq d) = \int_{c}^{d} f(x) \, dx \)
For the step-by-step solution given, this meant:
  • For \(P(10 \leq X \leq 20)\), solving \( \int_{10}^{20} \frac{1}{25} \, dx \) results in \(0.4\).
  • For \(P(X \geq 10)\), integrating \( \int_{10}^{25} \frac{1}{25} \, dx \) gives \(0.6\).
These integrals provide a practical means of calculating continuous probabilities, bridging between abstract mathematical concepts and real-world applications.

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Most popular questions from this chapter

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