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A company that produces fine crystal knows from experience that \(10 \%\) of its goblets have cosmetic flaws and must be classified as "seconds." a. Among six randomly selected goblets, how likely is it that only one is a second? b. Among six randomly selected goblets, what is the probability that at least two are seconds? c. If goblets are examined one by one, what is the probability that at most five must be selected to find four that are not seconds?

Short Answer

Expert verified
a. 0.354294. b. 0.114265. c. 0.268992.

Step by step solution

01

Identify the Distribution

The scenario is a classic case of a binomial distribution where each goblet has two possible outcomes: it is either a 'second' (defective) or 'not a second' (non-defective). The probability of a goblet being a second is given as \( p = 0.1 \), and being not a second is \( q = 1 - p = 0.9 \).
02

Part a: Calculate probability of one second

We need to find the probability of exactly one goblet being a second using the binomial probability formula: \[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \] where \( n = 6 \), \( k = 1 \), \( p = 0.1 \).Calculate it:\[ P(X = 1) = \binom{6}{1} (0.1)^1 (0.9)^5 \ = 6 \times 0.1 \times 0.59049 = 0.354294 \].
03

Part b: Calculate at least two seconds

For this, we calculate the complementary probability of fewer than 2 seconds (0 or 1 second) and subtract from 1:\[ P(X \geq 2) = 1 - P(X < 2) = 1 - (P(X = 0) + P(X = 1)) \].First, calculate \( P(X = 0) \):\[ P(X = 0) = \binom{6}{0} (0.1)^0 (0.9)^6 = 0.531441 \].Then add \( P(X = 1) \):\[ P(X < 2) = 0.531441 + 0.354294 = 0.885735 \].Finally:\[ P(X \geq 2) = 1 - 0.885735 = 0.114265 \].
04

Part c: Calculate probability of at most five to find four non-seconds

We use the negative binomial distribution since we want a fixed number of non-seconds before reaching the defective one:For finding four non-seconds among up to 5 goblets, calculate:\[ P(Y = 4 \text{ non-seconds}) = \binom{4}{3} (0.9)^4 (0.1)^1 + \binom{5}{4} (0.9)^4 (0.1)^1 \].The first term calculates exactly 4 non-seconds in 4 goblets and the second term including the 5th,\[ 4 \times 0.6561 \times 0.1 + 5 \times 0.6561 \times 0.1 = 0.236196 \ + 0.032805 = 0.268992 \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Theory
Probability Theory is the mathematical framework for quantifying uncertainty. It helps us calculate how likely an event is to happen. In probability, every event has a chance between 0 and 1. Here 0 means the event will not happen, and 1 means it will certainly happen.

When we talk about probabilities, we often deal with situations involving random events. For example, in the case of the crystal goblets, each goblet can either have a cosmetic flaw or not. This forms a basic scenario where probability theory applies.

Key aspects of probability theory include:
  • **Experiments and Outcomes:** An experiment is any process that leads to an uncertain result, like selecting goblets. Each result of an experiment is called an outcome.
  • **Events:** An event is something we can describe that might happen, like finding goblets without flaws.
  • **Probability Assignments:** Each event gets assigned a probability, which makes us predict how often the event occurs if the experiment is repeated many times.
Understanding these basics helps in analyzing events in a structured way, like how we determine which goblets are defective more than once.
Negative Binomial Distribution
The Negative Binomial Distribution is perfect for scenarios where we hunt for a number of successful outcomes in a series of trials until a specific number of failures happens. In essence, it helps to understand when we're repeating a task until something occurs a certain number of times, often a failure.

In our goblet explanation, the goblets are considered trials. We keep checking them until we find a certain number that are non-defective. This is why the negative binomial distribution is useful. It tells us the likelihood of finding a few non-flawed goblets before encountering flawed ones.

The formula for the negative binomial distribution is
\[ P(Y = k) = \binom{n-1}{k-1} p^k (1-p)^{n-k} \]
where:
  • **k** is the number of successful goblet checks,
  • **n** is the total checks needed to achieve those successes,
  • **p** is the probability of success on each check.
Using this distribution, we calculated the probability of finding four good goblets in the given trials. Understanding how negative binomial distribution works clarifies why we use it in real-world scenarios like this.
Combinatorics
Combinatorics is the branch of mathematics that deals with counting combinations and permutations. It answers questions like how many ways we can arrange subjects, choose groups, or select items. This is a backbone concept in probability theory since defining an event's probability often requires counting outcomes.

In our goblet problem, we used combinatorial math to calculate different probabilities. Combinatorics helped us find the probabilities for both the binomial and negative binomial distributions. Here’s why it matters:
  • **Combinations:** This part of combinatorics is used when the order of items doesn't matter, like when choosing how many goblets are non-defective.
  • **Permutations:** This is used when the order does matter, though it wasn't directly needed for our exercise.
  • **Binomial Coefficient:** It's represented as \( \binom{n}{k} \). This notation helps find the number of ways to choose \(k\) successes (like flawed goblets) out of \(n\) trials (total goblets), and it's vital for calculating binomial probabilities.
Understanding the basics of combinatorics makes solving probability problems easier and fosters deeper insight into the mechanics of probability theory.

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