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For customers purchasing a full set of tires at a particular tire store, consider the events \(A=\\{\) tires purchased were made in the United States ] \(B=\\{\) purchaser has tires balanced immediately \(\\}\) \(C=\) \\{purchaser requests front-end alignment \(\\}\) along with \(A^{\prime}, B^{\prime}\), and \(C^{\prime}\). Assume the following unconditional and conditional probabilities: $$ \begin{aligned} &P(A)=.75 \quad P(B \mid A)=.9 \quad P\left(B \mid A^{\prime}\right)=.8 \\ &P(C \mid A \cap B)=.8 \quad P\left(C \mid A \cap B^{\prime}\right)=.6 \\ &P\left(C \mid A^{\prime} \cap B\right)=.7 \quad P\left(C \mid A^{\prime} \cap B^{\prime}\right)=.3 \end{aligned} $$ a. Construct a tree diagram consisting of first-, second-, and third- generation branches and place an event label and appropriate probability next to each branch. b. Compute \(P(A \cap B \cap C)\). c. Compute \(P(B \cap C)\) d. Compute \(P(C)\). e. Compute \(P(A \mid B \cap C)\) the probability of a purchase of U.S. tires given that both balancing and an alignment were requested.

Short Answer

Expert verified
a tree, P(A ∩ B ∩ C)=0.54, P(B ∩ C)=0.68, P(C)=0.74, P(A | B ∩ C)≈0.7941.

Step by step solution

01

Draw First-Generation Branches

First-generation branches represent event \(A\) and its complement \(A'\). Assign probabilities based on the chance of the tires being made in the United States. Given \(P(A) = 0.75\), the probability of \(A'\) is \(P(A') = 0.25\).
02

Draw Second-Generation Branches

Second-generation branches come from each first-generation branch. These branches represent the events \(B\) and \(B'\). Assign conditional probabilities: \(P(B|A) = 0.9\) and \(P(B'|A) = 0.1\); \(P(B|A') = 0.8\) and \(P(B'|A') = 0.2\).
03

Draw Third-Generation Branches

Third-generation branches stem from each second-generation outcome. They represent \(C\) and \(C'\). Assign appropriate conditional probabilities for each branch: \(P(C|A \cap B) = 0.8\), \(P(C|A \cap B') = 0.6\), \(P(C|A' \cap B) = 0.7\), and \(P(C|A' \cap B') = 0.3\).
04

Compute Joint Probability P(A ∩ B ∩ C)

Use the chain rule to compute \(P(A \cap B \cap C)\), which factors as \(P(A) \times P(B|A) \times P(C|A \cap B) = 0.75 \times 0.9 \times 0.8 = 0.54\).
05

Compute Probability P(B ∩ C)

Calculate \(P(B \cap C)\) by summing the probabilities of all paths that include both \(B\) and \(C\): \[P(B \cap C) = P(A \cap B \cap C) + P(A' \cap B \cap C)\]\[= 0.75 \times 0.9 \times 0.8 + 0.25 \times 0.8 \times 0.7\]\[= 0.54 + 0.14 = 0.68\].
06

Compute Probability P(C)

Find \(P(C)\) by summing the probabilities of all branches ending in \(C\):\[P(C) = P(A \cap B \cap C) + P(A \cap B' \cap C) + P(A' \cap B \cap C) + P(A' \cap B' \cap C)\]\[= 0.54 + 0.75 \times 0.1 \times 0.6 + 0.14 + 0.25 \times 0.2 \times 0.3\]\[= 0.54 + 0.045 + 0.14 + 0.015 = 0.74\].
07

Compute Conditional Probability P(A | B ∩ C)

Use Bayes' theorem to find \(P(A | B \cap C)\):\[P(A|B \cap C) = \frac{P(A \cap B \cap C)}{P(B \cap C)} = \frac{0.54}{0.68} \approx 0.7941\].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conditional Probability
Conditional probability helps us understand the likelihood of an event occurring given that another event has already occurred. In simpler terms, it tells us how the probability of one event is affected by the occurrence of another trusted event. For instance, knowing that the tires are from a particular country might affect the likelihood that a customer asks for additional services like balancing or alignment.

The formula for conditional probability is expressed as: \[ P(B|A) = \frac{P(A \cap B)}{P(A)} \] This shows that the conditional probability, \( P(B|A) \), is the probability of both events \( A \) and \( B \) occurring, divided by the probability of event \( A \) alone.

In our exercise, we have probabilities like \( P(B|A) = 0.9 \), which means there is a 90% chance that a customer balances the tires given they were made in the U.S. The notation \( | \) symbolizes what's already known, like having U.S. tires (event \( A \)) affects the balancing activity (event \( B \)).

Understanding conditional probability is crucial for problems that involve chains of events. In tree diagrams, after every event, conditional probabilities are considered to calculate the branches' next stages. It helps build a comprehensive picture of compound multi-step events.
Joint Probability
Joint probability concerns itself with the likelihood of several events occurring together. It's represented by the intersection symbol \(\cap\), which implies "and" in this context. For example, finding the probability that events \( A \), \( B \), and \( C \) happen all together is exploring their joint probability: \( P(A \cap B \cap C) \).

In terms of our exercise's context, say you want to know the probability that the tires are U.S-made, and balancing and alignment services are all requested. Using the given probabilities, this joint probability is calculated using multiplication across the tree's branches:
\[ P(A \cap B \cap C) = P(A) \times P(B|A) \times P(C|A \cap B) = 0.75 \times 0.9 \times 0.8 = 0.54 \]
This means there's a 54% chance all those conditions are met when purchasing tires.** It's like following a path in a probability tree; the joint probability is a comprehensive view following one possibility from start to finish. Joint probabilities can sometimes require adding probabilities of different paths that satisfy the condition overall.
Bayes' Theorem
Bayes' Theorem is a critical concept for turning conditional probabilities on their heads. It allows calculation of the probability of an initial event given the final outcome. Think of it like retracing your steps after you've reached a destination, to estimate how likely your starting point was.

Bayes' Theorem formula is:\[ P(A|B) = \frac{P(B|A) \times P(A)}{P(B)} \] Here, \( P(A|B) \) tells us the probability that event \( A \) was true given we know event \( B \) happened. It uses the idea of updating our existing knowledge (\( P(A) \) and \( P(B|A) \)) to refine our belief about event \( A \).

Let's apply it to the question: What is the probability that the customer purchased U.S. tires given that they requested both balancing and alignment? Using Bayes':\[ P(A|B \cap C) = \frac{P(A \cap B \cap C)}{P(B \cap C)} = \frac{0.54}{0.68} \approx 0.7941 \]This result, approximately 79.41%, adjusts our expectation of initially having American tires considering later requests. Bayes’ Theorem is invaluable when dealing with complex conditional relationships and deriving insights from observed outcomes.

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Most popular questions from this chapter

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