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A random sample of 5726 telephone numbers from a certain region taken in March 2002 yielded 1105 that were unlisted, and 1 year later a sample of 5384 yielded 980 unlisted numbers. a. Test at level .10 to see whether there is a difference in true proportions of unlisted numbers between the 2 years. b. If \(p_{1}=.20\) and \(p_{2}=.18\), what sample sizes \((m=n)\) would be necessary to detect such a difference with probability \(.90\) ?

Short Answer

Expert verified
a) Yes, there is a significant difference. b) Sample size must be 7200 for each group.

Step by step solution

01

Define the Hypotheses

For part a, we define the null hypothesis as there being no difference between the proportions of unlisted numbers in the two years: \(H_0: p_1 = p_2\).The alternative hypothesis is that there is a difference: \(H_a: p_1 eq p_2\).
02

Calculate Sample Proportions

Calculate the sample proportions for each year:Year 1: \(\hat{p}_1 = \frac{1105}{5726} \approx 0.1931\)Year 2: \(\hat{p}_2 = \frac{980}{5384} \approx 0.1820\)
03

Compute Combined Sample Proportion

The combined sample proportion is calculated using:\(\hat{p} = \frac{x_1 + x_2}{n_1 + n_2} = \frac{1105 + 980}{5726 + 5384} \approx 0.1877\)
04

Calculate the Test Statistic

The test statistic for the difference in proportions is given by the formula:\(z = \frac{\hat{p}_1 - \hat{p}_2}{\sqrt{\hat{p} (1 - \hat{p}) \left(\frac{1}{n_1} + \frac{1}{n_2}\right)}}\)Substitute the values: \(z \approx \frac{0.1931 - 0.1820}{\sqrt{0.1877 \times (1 - 0.1877) \times \left(\frac{1}{5726} + \frac{1}{5384}\right)}} \approx 1.93\)
05

Determine Critical Value and Decision

Using a significance level of \(\alpha = 0.10\), the critical z-value for a two-tailed test is approximately \(\pm 1.645\).Since \(|z| = 1.93\) is greater than 1.645, we reject the null hypothesis \(H_0\), suggesting a significant difference in the proportions.
06

Calculate Required Sample Size for Part b

For part b, to find the required sample size for detecting a difference between two proportions with a power of 0.90, use the formula:\(n = \left(\frac{z_{\alpha/2} + z_{\beta}}{p_1 - p_2}\right)^2 \times \left(p_1(1 - p_1) + p_2(1 - p_2)\right)\)where \(z_{\alpha/2} = 1.645\) for \(\alpha = 0.10\), and \(z_{\beta} = 1.282\) for power \(1 - \beta = 0.90\).Substitute values: \(n \approx \left(\frac{1.645 + 1.282}{0.20 - 0.18}\right)^2 \times \left(0.20(0.80) + 0.18(0.82)\right)\)After calculations, \(n \approx 7200\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Difference in Proportions Test
The Difference in Proportions Test is a statistical method used to determine if there is any significant difference between two sample proportions. In simple terms, it checks if two groups are different in terms of a particular characteristic. Imagine comparing the percentage of unlisted telephone numbers between two different years. This test can help you understand if the change you are observing is statistically significant or just due to random chance.

To perform this test, follow these basic steps:
  • Define your hypotheses. Generally, the null hypothesis (\(H_0\)) states that there is no difference between the two proportions. The alternative hypothesis (\(H_a\)) suggests that a difference does exist.
  • Calculate the sample proportions for each group. For example, how many unlisted numbers exist in each sample?
  • Combine the sample proportions to get an overall proportion. This helps in comparing the two groups effectively.
  • Calculate the test statistic. The formula for the test statistic \[ z = \frac{\hat{p}_1 - \hat{p}_2}{\sqrt{\hat{p} (1 - \hat{p}) \left(\frac{1}{n_1} + \frac{1}{n_2}\right)}} \]helps us to quantify the difference.
  • Compare this statistic to a critical value derived from a standard normal distribution. If the test statistic exceeds the critical value, you reject the null hypothesis.
The Difference in Proportions Test essentially tells you if the observed differences are due to a real change or just sampling variations.
Sample Size Calculation
Sample size calculation is crucial for any study aiming to detect a true difference or effect. It's akin to ensuring your sample size is large enough to yield reliable results without being unnecessarily large. When planning any statistical analysis, calculating the correct sample size is one of the first steps, especially in hypothesis testing.

For testing the difference between two proportions, you need an appropriate sample size to ensure the results are statistically significant. The formula for calculating the sample size required to detect a difference between two population proportions with a given level of significance and power is:\[n = \left(\frac{z_{\alpha/2} + z_{\beta}}{p_1 - p_2}\right)^2 \times \left(p_1(1 - p_1) + p_2(1 - p_2)\right)\]Here's what each component refers to:
  • \(z_{\alpha/2}\) is the z-value corresponding to your chosen level of significance. A typical value for a 10% significance level is 1.645.
  • \(z_{\beta}\) is the z-value based on the desired power of the test, often 0.90, leading to a value of 1.282.
  • \(p_1\) and \(p_2\) are the population proportions for each group. These represent the values you are comparing.
The calculation will give you the minimum sample size needed to detect a specified difference between groups with the desired confidence level and statistical power.
Statistical Power
Statistical Power is a concept that indicates the probability that a test will correctly reject a false null hypothesis. In layman's terms, it measures a test's ability to detect an effect or difference when one truly exists.

Power is influenced by several factors:
  • Sample Size: Larger samples generally increase power since they offer a better representation of the population, reducing variability.
  • Effect Size: The larger the effect or difference between groups, the easier it is to detect, and hence, the higher the power.
  • Significance Level: There is a trade-off between significance level and power. A more stringent alpha (\(\alpha\)) level (like 0.01 instead of 0.05) reduces power since you're being more cautious against Type I errors.
  • Variability: Less variability within your data means higher power, as the signal is clearer against the noise.
When designing a study, aiming for a statistical power of 0.80 or 0.90 is common practice. A test with 0.90 power means there is a 90% chance of detecting a true effect if there is one.

In summary, statistical power is about confidence in your test results—the higher, the better. It helps ensure your study results are trustworthy, leading to stronger conclusions.

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Most popular questions from this chapter

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