/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 46 A study of the relationship betw... [FREE SOLUTION] | 91Ó°ÊÓ

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A study of the relationship between age and various visual functions (such as acuity and depth perception) reported the following observations on area of scleral lamina \(\left(\mathrm{mm}^{2}\right)\) from human optic nerve heads ("Morphometry of Nerve Fiber Bundle Pores in the Optic Nerve Head of the Human," Exper. Eye Res., 1988: 559-568): \(\begin{array}{lllllllll}2.75 & 2.62 & 2.74 & 3.85 & 2.34 & 2.74 & 3.93 & 4.21 & 3.88 \\ 4.33 & 3.46 & 4.52 & 2.43 & 3.65 & 2.78 & 3.56 & 3.01 & \end{array}\) a. Calculate \(\sum x_{i}\) and \(\sum x_{i}^{2}\). b. Use the values calculated in part (a) to compute the sample variance \(s^{2}\) and then the sample standard deviation \(s\).

Short Answer

Expert verified
\(\sum x_{i} = 56.8\); \(s^2 \approx 0.2319\); \(s \approx 0.4816\).

Step by step solution

01

List the Data

Let's first write down all the given data points of the area of scleral lamina: 2.75, 2.62, 2.74, 3.85, 2.34, 2.74, 3.93, 4.21, 3.88, 4.33, 3.46, 4.52, 2.43, 3.65, 2.78, 3.56, 3.01.
02

Compute the Sum of the Data ( \(\sum x_{i}\) )

Add all the data points together. \[ \sum x_{i} = 2.75 + 2.62 + 2.74 + 3.85 + 2.34 + 2.74 + 3.93 + 4.21 + 3.88 + 4.33 + 3.46 + 4.52 + 2.43 + 3.65 + 2.78 + 3.56 + 3.01 = 56.8 \]
03

Compute the Sum of the Squares of the Data ( \(\sum x_{i}^{2}\) )

Square each data point and then add them together. \[ \sum x_{i}^{2} = 2.75^2 + 2.62^2 + 2.74^2 + 3.85^2 + 2.34^2 + 2.74^2 + 3.93^2 + 4.21^2 + 3.88^2 + 4.33^2 + 3.46^2 + 4.52^2 + 2.43^2 + 3.65^2 + 2.78^2 + 3.56^2 + 3.01^2 = 193.4426 \]
04

Compute the Sample Variance ( \(s^{2}\) )

Use the formula for sample variance: \[ s^2 = \frac{\sum x_{i}^2 - \frac{(\sum x_{i})^2}{n}}{n-1} \]where \(n\) is the number of observations. Here, \(n = 17\). \[ s^2 = \frac{193.4426 - \frac{(56.8)^2}{17}}{17-1} \] \[ s^2 = \frac{193.4426 - \frac{3225.44}{17}}{16} \] \[ s^2 = \frac{193.4426 - 189.7317647}{16} \] \[ s^2 = \frac{3.7108353}{16} \] \(s^2 \approx 0.2319\)
05

Compute the Sample Standard Deviation ( \(s\) )

The sample standard deviation is the square root of the sample variance. \[ s = \sqrt{s^2} \]\[ s = \sqrt{0.2319} \]\[ s \approx 0.4816 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Standard Deviation
The Sample Standard Deviation is a measure of how spread out the numbers in a data set are. To compute it, you start by finding the sample variance, which measures the average squared deviation from the mean. Once you have the sample variance, you take the square root to get the sample standard deviation.

In the exercise, we first calculated the sample variance ( s^2 ), which was found to be approximately 0.2319 using the appropriate formula. This formula incorporates the sum of squares of the data as well as the square of the sum, divided by the sample size minus one. This adjustment (using n-1 instead of n) is crucial when dealing with sample data because it corrects for bias in the estimation of the population variance.

The final step to find the sample standard deviation is straightforward: calculate s as the square root of s^2 . For our data set, this resulted in a sample standard deviation of approximately 0.4816. This tells us, on average, how much each data point deviates from the mean of the data set.
Sum of Squares
The concept of Sum of Squares is central to understanding variance and standard deviation. It involves squaring each individual data point and then adding all these squared values together.

This process helps quantify the "spread" of numbers in a data set. By squaring differences, we focus on the magnitude of deviations (ignoring direction), ensuring that negative differences do not cancel out positive ones.

In the context of the exercise, we calculated the Sum of Squares as \( \sum x_{i}^{2} \), which was 193.4426. This value was derived by taking each data point, squaring it, and then summing all these squared results. This metric is foundational when calculating variance, as it helps to account for each observation's contribution to the overall variability of the data.
Descriptive Statistics
Descriptive Statistics provide a way to summarize or describe a set of data. They offer essential insights that help in understanding the data through various measures such as mean, median, variance, and standard deviation.

Among these, the mean provides the average value of the data set, offering a central tendency. However, to understand how data points differ from each other, measures like variance and standard deviation are essential. For instance, while the mean of our data set gives a quick overview, the standard deviation provides a clearer picture of each data point's variance from the mean.

Calculating these statistics for our dataset involved adding up the data points for the mean, calculating the Sum of Squares, and deriving the sample variance and standard deviation. These measures help us encapsulate the data's essence, making it easier to communicate and draw inferences from large sets of data. Descriptive statistics are crucial in fields ranging from research to business, allowing decision-makers to understand data patterns without delving into individual data points.

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Most popular questions from this chapter

The value of Young's modulus (GPa) was determined for cast plates consisting of certain intermetallic substrates, resulting in the following sample observations ("Strength and Modulus of a Molybdenum-Coated Ti-25Al-10Nb-3U-1Mo Intermetallic," J. Mater. Engrg. Perform., 1997: 46-50): \(116.4\) \(115.9\) \(114.6\) \(115.2\) \(115.8\) a. Calculate \(\bar{x}\) and the deviations from the mean. b. Use the deviations calculated in part (a) to obtain the sample variance and the sample standard deviation. c. Calculate \(s^{2}\) by using the computational formula for the numerator \(S_{x x}\). d. Subtract 100 from each observation to obtain a sample of transformed values. Now calculate the sample variance of these transformed values, and compare it to \(s^{2}\) for the original data. State the general principle.

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Fire load \(\left(\mathrm{MJ} / \mathrm{m}^{2}\right)\) is the heat energy that could be released per square meter of floor area by combustion of contents and the structure itself. The article "Fire Loads in Office Buildings" \((J .\) Struct. Engrg., 1997: \(365-368\) ) gave the following cumulative percentages (read from a graph) for fire loads in a sample of 388 rooms: \(\begin{array}{lccccc}\text { Value } & 0 & 150 & 300 & 450 & 600 \\ \text { Cumulative \% } & 0 & 19.3 & 37.6 & 62.7 & 77.5 \\ \text { Value } & 750 & 900 & 1050 & 1200 & 1350 \\ \text { Cumulative \% } & 87.2 & 93.8 & 95.7 & 98.6 & 99.1 \\ \text { Value } & 1500 & 1650 & 1800 & 1950 & \\ \text { Cumulative \% } & 99.5 & 99.6 & 99.8 & 100.0\end{array}\) a. Construct a relative frequency histogram and comment on interesting features. b. What proportion of fire loads are less than 600 ? At least 1200 ? c. What proportion of the loads are between 600 and 1200 ?

In a famous experiment carried out in 1882, Michelson and Newcomb obtained 66 observations on the time it took for light to travel between two locations in Washington, D.C. A few of the measurements (coded in a certain manner) were 31,23 , \(32,36,22,26,27\), and 31 . a. Why are these measurements not identical? b. Does this study involve sampling an existing population or a conceptual population?

The accompanying data set consists of observations on shear strength (lb) of ultrasonic spot welds made on a type of alclad sheet. Construct a relative frequency histogram based on ten equalwidth classes with boundaries \(4000,4200, \ldots .\) [The histogram will agree with the one in "Comparison of Properties of Joints Prepared by Ultrasonic Welding and Other Means" (J. Aircraft, 1983: 552-556).] Comment on its features. \(\begin{array}{lllllll}5434 & 4948 & 4521 & 4570 & 4990 & 5702 & 5241 \\ 5112 & 5015 & 4659 & 4806 & 4637 & 5670 & 4381 \\ 4820 & 5043 & 4886 & 4599 & 5288 & 5299 & 4848 \\ 5378 & 5260 & 5055 & 5828 & 5218 & 4859 & 4780 \\ 5027 & 5008 & 4609 & 4772 & 5133 & 5095 & 4618 \\ 4848 & 5089 & 5518 & 5333 & 5164 & 5342 & 5069 \\ 4755 & 4925 & 5001 & 4803 & 4951 & 5679 & 5256 \\ 5207 & 5621 & 4918 & 5138 & 4786 & 4500 & 5461 \\ 5049 & 4974 & 4592 & 4173 & 5296 & 4965 & 5170 \\ 4740 & 5173 & 4568 & 5653 & 5078 & 4900 & 4968 \\ 5248 & 5245 & 4723 & 5275 & 5419 & 5205 & 4452 \\ 5227 & 5555 & 5388 & 5498 & 4681 & 5076 & 4774 \\ 4931 & 4493 & 5309 & 5582 & 4308 & 4823 & 4417 \\ 5364 & 5640 & 5069 & 5188 & 5764 & 5273 & 5042 \\ 5189 & 4986 & & & & & \end{array}\)

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