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Chapter 3: Problem 11

Write an equation to represent the situation and solve. Over a 10 -day period the low temperature for International Falls, Minnesota, was recorded as \(-18^{\circ} \mathrm{F}\) on 3 days, \(-15^{\circ} \mathrm{F}\) on 2 days, \(-10^{\circ} \mathrm{F}\) on 2 days, and $-8^{\circ} \mathrm{F},-5^{\circ} \mathrm{F},\( and \)-3^{\circ} \mathrm{F}$ on the remaining 3 days. What was the average low temperature over the 10 -day period?

Short Answer

Expert verified
Answer: The average low temperature during this period was -12掳F.

Step by step solution

01

Write an equation for the average low temperature

To find the average low temperature, we will sum up the given temperatures and divide by the total number of days. We can represent the average (A) by the equation: A = (total of low temperatures) / (number of days)
02

Find the total of low temperatures for the given days

Let's sum up the temperatures for each day: Total = (-18 * 3) + (-15 * 2) + (-10 * 2) + (-8) + (-5) + (-3) Here, we multiply the temperature by the number of days it occurred and then add all the products. Solve for the total: Total = (-54) + (-30) + (-20) + (-8) + (-5) + (-3) Total = -120
03

Calculate the average low temperature

Now that we have the total of low temperatures, we can find the average by dividing it by the total number of days (10). A = (-120) / (10) A = -12 So, the average low temperature over the 10-day period was \(\boxed{-12^{\circ} \mathrm{F}}\).

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