Chapter 11: Problem 9
$$ \frac{1}{\cot A+\tan A}=\sin A \cos A $$
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Chapter 11: Problem 9
$$ \frac{1}{\cot A+\tan A}=\sin A \cos A $$
These are the key concepts you need to understand to accurately answer the question.
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$$ \cos (A+B) \cos C-\cos (B+C) \cos A=\sin B \sin (C-A) $$
$$ \sin A \sin (A+2 B)-\sin B \sin (B+2 A)=\sin (A-B) \sin (A+B) . $$
$$ \frac{\sin (4 A-2 B)+\sin (4 B-2 A)}{\cos (4 A-2 B)+\cos (4 B-2 A)}=\tan (A+B) $$
$$ \sin ^{2}\left(\frac{\pi}{8}+\frac{A}{2}\right)-\sin ^{2}\left(\frac{\pi}{8}-\frac{A}{2}\right)=\frac{1}{\sqrt{2}} \sin A $$
$$ \cot ^{4} A+\cot ^{2} A=\operatorname{cosec}^{4} A-\operatorname{cosec}^{2} A $$
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