Chapter 11: Problem 18
$$ \cot ^{4} A+\cot ^{2} A=\operatorname{cosec}^{4} A-\operatorname{cosec}^{2} A $$
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Chapter 11: Problem 18
$$ \cot ^{4} A+\cot ^{2} A=\operatorname{cosec}^{4} A-\operatorname{cosec}^{2} A $$
These are the key concepts you need to understand to accurately answer the question.
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$$ \tan ^{2} A-\sin ^{2} A=\sin ^{4} A \sec ^{2} A $$
$$ \frac{\sin A-\sin B}{\cos B-\cos A}=\cot \frac{A+B}{2} $$
$$ \frac{\sin (4 A-2 B)+\sin (4 B-2 A)}{\cos (4 A-2 B)+\cos (4 B-2 A)}=\tan (A+B) $$
$$ \sin 6^{\circ} \sin 42^{\circ} \sin 66^{\circ} \sin 78^{\circ}=\frac{1}{16} $$
$$ \frac{1}{\cos e c A-\cot A}-\frac{1}{\sin A}=\frac{1}{\sin A}-\frac{1}{\operatorname{cosec} A+\cot A} $$
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