Chapter 11: Problem 56
$$ \cos A \cos (B-A)-\sin A \sin (B-A)=\cos B $$
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Chapter 11: Problem 56
$$ \cos A \cos (B-A)-\sin A \sin (B-A)=\cos B $$
These are the key concepts you need to understand to accurately answer the question.
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$$ \frac{\sin A}{1+\cos A}+\frac{1+\cos A}{\sin A}=2 \operatorname{cosec} A $$
$$ \sin 20^{\circ} \sin 40^{\circ} \sin 60^{\circ} \sin 80^{\circ}=\frac{3}{16} $$
$$ 2 \cos \frac{\pi}{13} \cos \frac{9 \pi}{13}+\cos \frac{3 \pi}{13}+\cos \frac{5 \pi}{13}=0 $$
$$ \sin 75^{\circ}-\sin 15^{\circ}=\cos 105^{\circ}+\cos 15^{\circ} $$
$$ \sqrt{\operatorname{cosec}^{2} A-1}=\cos A \operatorname{cosec} A $$
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