Chapter 11: Problem 3
$$ \frac{\sin A}{1+\cos A}+\frac{1+\cos A}{\sin A}=2 \operatorname{cosec} A $$
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Chapter 11: Problem 3
$$ \frac{\sin A}{1+\cos A}+\frac{1+\cos A}{\sin A}=2 \operatorname{cosec} A $$
These are the key concepts you need to understand to accurately answer the question.
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$$ \sin (n+1) A \sin (n-1) A+\cos (n+1) A \cos (n-1) A=\cos 2 A $$
$$ \cos 20^{\circ} \cos 100^{\circ}+\cos 100^{\circ} \cos 140^{\circ}-\cos 140^{\circ} \cos 200^{\circ}=-\frac{3}{4} $$
$$ (\sin A+\cos A)(1-\sin A \cos A)=\sin ^{3} A+\cos ^{3} A $$
$$ \frac{\sin 2 A+\sin 2 B}{\sin 2 A-\sin 2 B}=\frac{\tan (A+B)}{\tan (A-B)} $$
$$ \frac{\cos 2 B+\cos 2 A}{\cos 2 B-\cos 2 A}=\cot (A+B) \cot (A-B) $$
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