Chapter 11: Problem 183
$$ \frac{1+\sin \theta-\cos \theta}{1+\sin \theta+\cos \theta}=\tan \frac{\theta}{2} $$
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Chapter 11: Problem 183
$$ \frac{1+\sin \theta-\cos \theta}{1+\sin \theta+\cos \theta}=\tan \frac{\theta}{2} $$
These are the key concepts you need to understand to accurately answer the question.
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$$ (\sin A+\cos A)(\cot A+\tan A)=\sec A+\operatorname{cosec} A $$
$$ \frac{\tan A}{1-\cot A}+\frac{\cot A}{1-\tan A}=\sec A \operatorname{cosec} A+1 $$
$$ \sin \left(45^{\circ}+A\right) \sin \left(45^{\circ}-A\right)=\frac{1}{2} \cos 2 A $$
$$ \sin ^{2}\left(\frac{\pi}{8}+\frac{A}{2}\right)-\sin ^{2}\left(\frac{\pi}{8}-\frac{A}{2}\right)=\frac{1}{\sqrt{2}} \sin A $$
$$ \sec ^{2} A \operatorname{cosec}^{2} A=\tan ^{2} A+\cot ^{2} A+2 $$
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