Chapter 11: Problem 14
$$ \frac{\tan A}{1-\cot A}+\frac{\cot A}{1-\tan A}=\sec A \operatorname{cosec} A+1 $$
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Chapter 11: Problem 14
$$ \frac{\tan A}{1-\cot A}+\frac{\cot A}{1-\tan A}=\sec A \operatorname{cosec} A+1 $$
These are the key concepts you need to understand to accurately answer the question.
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$$ \left(\frac{1}{\sec ^{2} A-\cos ^{2} A}+\frac{1}{\operatorname{cosec}^{2} A-\sin ^{2} A}\right) \cos ^{2} A \sin ^{2} A=\frac{1-\cos ^{2} A \sin ^{2} A}{2+\cos ^{2} A \sin ^{2} A} $$
$$ \frac{\operatorname{cosec} A}{\cot A+\tan A}=\cos A $$
$$ \text { If } x=y \cos \frac{2 \pi}{3}=z \cos \frac{4 \pi}{3}, \text { then show that } x y+y z+z x=0 $$
$$ \frac{\cot A+\tan B}{\cot B+\tan A}=\cot A \tan B $$
$$ \frac{\sec A-\tan A}{\sec A+\tan A}=1-2 \sec A \tan A+2 \tan ^{2} A $$
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