Chapter 11: Problem 134
$$ \frac{\sin ^{2} A-\sin ^{2} B}{\sin A \cos A-\sin B \cos B}=\tan (A+B) $$
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Chapter 11: Problem 134
$$ \frac{\sin ^{2} A-\sin ^{2} B}{\sin A \cos A-\sin B \cos B}=\tan (A+B) $$
These are the key concepts you need to understand to accurately answer the question.
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$$ \cos 2 \theta \cos \frac{\theta}{2}-\cos 3 \theta \cos \frac{9 \theta}{2}=\sin 5 \theta \sin \frac{5 \theta}{2} \text { . } $$
$$ (\sin A+\cos A)(1-\sin A \cos A)=\sin ^{3} A+\cos ^{3} A $$
$$ \frac{\sin (4 A-2 B)+\sin (4 B-2 A)}{\cos (4 A-2 B)+\cos (4 B-2 A)}=\tan (A+B) $$
$$ \cos \left(36^{\circ}-A\right) \cos \left(36^{\circ}+A\right)+\cos \left(54^{\circ}+A\right) \cos \left(54^{\circ}-A\right)=\cos 2 A $$
$$ \frac{1-\tan A}{1+\tan A}=\frac{\cot A-1}{\cot A+1} $$
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