Chapter 11: Problem 11
$$ \frac{1-\tan A}{1+\tan A}=\frac{\cot A-1}{\cot A+1} $$
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Chapter 11: Problem 11
$$ \frac{1-\tan A}{1+\tan A}=\frac{\cot A-1}{\cot A+1} $$
These are the key concepts you need to understand to accurately answer the question.
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$$ \sin \frac{\pi}{10} \sin \frac{13 \pi}{10}=-\frac{1}{4} $$
$$ \frac{\cos 2 B+\cos 2 A}{\cos 2 B-\cos 2 A}=\cot (A+B) \cot (A-B) $$
$$ 2 \sec ^{2} A-\sec ^{4} A-2 \operatorname{cosec}^{2} A+\operatorname{cosec}^{4} A=\cot ^{4} A-\tan ^{4} A $$
$$ \frac{\sin A-\sin B}{\cos B-\cos A}=\cot \frac{A+B}{2} $$
$$ \sin ^{2}\left(\frac{\pi}{8}+\frac{A}{2}\right)-\sin ^{2}\left(\frac{\pi}{8}-\frac{A}{2}\right)=\frac{1}{\sqrt{2}} \sin A $$
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