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Let \(Y_{1}\) and \(Y_{2}\) have a bivariate normal distribution. Show that the conditional distribution of \(Y_{1}\) given that \(Y_{2}=y_{2}\) is a normal distribution with mean \(\mu_{1}+\rho \frac{\sigma_{1}}{\sigma_{2}}\left(y_{2}-\mu_{2}\right)\) and variance \(\sigma_{1}^{2}\left(1-\rho^{2}\right)\)

Short Answer

Expert verified
The conditional distribution is normal with mean \(\mu_1 + \rho \frac{\sigma_1}{\sigma_2} (y_2 - \mu_2)\) and variance \(\sigma_1^2(1 - \rho^2)\).

Step by step solution

01

Understanding Bivariate Normal Distribution

The bivariate normal distribution involves two random variables, \(Y_1\) and \(Y_2\). These variables are characterized by their means, \(\mu_1\) and \(\mu_2\), variances, \(\sigma_1^2\) and \(\sigma_2^2\), and correlation, \(\rho\). The correlation measures the linear relationship between \(Y_1\) and \(Y_2\).
02

Define the Conditional Distribution

The goal is to find the conditional distribution of \(Y_1\) given \(Y_2 = y_2\). The theory of conditional distributions for normal variables indicates that it will also follow a normal distribution, conditioned by the given value \(y_2\).
03

Conditional Mean Formula

The conditional mean of \(Y_1\) given \(Y_2 = y_2\) is given by the formula:\[\mu_{1|2} = \mu_1 + \rho \frac{\sigma_1}{\sigma_2} (y_2 - \mu_2)\]This formula accounts for the shift in the mean of \(Y_1\) caused by the information that \(Y_2\) takes a particular value \(y_2\).
04

Conditional Variance Formula

The conditional variance of \(Y_1\) given \(Y_2 = y_2\) is:\[\sigma_{1|2}^2 = \sigma_1^2 (1 - \rho^2)\]This expression demonstrates that the variance of the conditional distribution depends only on \(\sigma_1^2\) and \(\rho\), not \(y_2\).
05

Conclusion

Putting it together, the conditional distribution of \(Y_1\) given \(Y_2 = y_2\) is normal with mean \(\mu_{1|2}\) and variance \(\sigma_{1|2}^2\), which confirms the exercise requirements.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conditional Distribution
In statistics, a conditional distribution is the probability distribution of a random variable given that a certain condition holds. Here, we are examining the conditional distribution of the random variable \( Y_1 \) given that \( Y_2 = y_2 \). In essence, it refers to how the values of \( Y_1 \) are distributed when \( Y_2 \) is fixed at a specific value.When dealing with a bivariate normal distribution, like with \( Y_1 \) and \( Y_2 \), the conditional distribution of one variable given the other is also normal. This is a fascinating property because normality is retained even under conditioning. The conditional mean of \( Y_1 \), given that \( Y_2 = y_2 \), shifts by a factor involving the correlation \( \rho \) between the variables and the variances \( \sigma_1^2 \) and \( \sigma_2^2 \). Additionally, the conditional variance does not depend on \( y_2 \), showcasing stability of variance irrespective of the specific value \( Y_2 \) can take.
Normal Distribution
The normal distribution, commonly known as the Gaussian distribution, is one of the most fundamental concepts in statistics. It is characterized by its bell-shaped curve, which is symmetric around the mean, \( \mu \).Normal distributions have two main parameters: the mean \( \mu \), which determines the center of the distribution, and the variance \( \sigma^2 \), which measures the spread of the distribution.
  • Mean (\( \mu \)): Specifies where the peak of the distribution occurs.
  • Variance (\( \sigma^2 \)): Illustrates how much the data points deviate from the mean on average.
In many natural phenomena, data tends to form a pattern that closely resembles a normal distribution. An important property here is that for normally distributed variables, any linear combination is also normally distributed. This property is crucial when dealing with multivariate normal distributions and their conditioning, as shown with \( Y_1 \) and \( Y_2 \).
Correlation
Correlation is a statistical measure that expresses the extent to which two variables fluctuate together. In the context of the bivariate normal distribution, the correlation coefficient \( \rho \) measures the strength and direction of a linear relationship between \( Y_1 \) and \( Y_2 \).
  • \( \rho = 1 \): Perfect positive linear correlation
  • \( \rho = 0 \): No linear correlation
  • \( \rho = -1 \): Perfect negative linear correlation
A correlation of \( \rho \,\) between \( Y_1 \) and \( Y_2 \) does not imply causation; it merely indicates a relationship where changes in one variable are associated with changes in the other. This relationship greatly influences the conditional mean of \( Y_1 \) given \( Y_2 \), incorporating the term involving \( \rho \) in its calculation. This demonstrates the influence of \( Y_2 \)'s deviation from its mean on \( Y_1 \)'s expected value.
Random Variables
Random variables are a foundational concept in probability and statistics. They are quantities whose possible values are numerical outcomes of a random phenomenon.A random variable can be discrete, taking on a specific set of values, or continuous, where it can take on any value within a range. In our case, \( Y_1 \) and \( Y_2 \) are continuous random variables associated with the bivariate normal distribution.Continuous random variables, like \( Y_1 \) and \( Y_2 \), have properties characterized by probability density functions (PDFs). For normal distributions, the PDF is the well-known bell curve, determined by mean and variance parameters.Understanding random variables is crucial when exploring bivariate distributions, where each variable is examined both individually and jointly to understand complex relationships and dependencies, including conditional distributions.

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Most popular questions from this chapter

Suppose that we are to observe two independent random samples: \(Y_{1}, Y_{2}, \ldots, Y_{n}\) denoting a random sample from a normal distribution with mean \(\mu_{1}\) and variance \(\sigma_{1}^{2} ;\) and \(X_{1}, X_{2}, \ldots, X_{m}\) denoting a random sample from another normal distribution with mean \(\mu_{2}\) and variance \(\sigma_{2}^{2} .\) An approximation for \(\mu_{1}-\mu_{2}\) is given by \(\bar{Y}-\bar{X}\), the difference between the sample means. Find \(E(\bar{Y}-\bar{X})\) and \(V(\bar{Y}-\bar{X})\)

Suppose that the random variables \(Y_{1}\) and \(Y_{2}\) have joint probability density function, \(f\left(y_{1}, y_{2}\right)\) given by (see Exercises 5.14 and 5.32 ) $$f\left(y_{1}, y_{2}\right)=\left\\{\begin{array}{ll}6 y_{1}^{2} y_{2}, & 0 \leq y_{1} \leq y_{2}, y_{1}+y_{2} \leq 2 \\\0, & \text { elsewhere }\end{array}\right.$$ Show that \(Y_{1}\) and \(Y_{2}\) are dependent random variables.

The weights of a population of mice fed on a certain diet since birth are assumed to be normally distributed with \(\mu=100\) and \(\sigma=20\) (measurement in grams). Suppose that a random sample of \(n=4\) mice is taken from this population. Find the probability that a. exactly two weigh between 80 and 100 grams and exactly one weighs more than 100 grams. b. all four mice weigh more than 100 grams.

In Exercise 5.65 , we considered random variables \(Y_{1}\) and \(Y_{2}\) that, for \(-1 \leq \alpha \leq 1\), have joint density $$f\left(y_{1}, y_{2}\right)=\left\\{\begin{array}{ll} {\left[1-\alpha\left\\{\left(1-2 e^{-y_{1}}\right)\left(1-2 e^{-y_{2}}\right)\right\\}\right] e^{-y_{1}-y_{2}},} & 0 \leq y_{1}, 0 \leq y_{2} \\ 0, & \text { elsewhere } \end{array}\right.$$and established that the marginal distributions of \(Y_{1}\) and \(Y_{2}\) are both exponential with mean \(1 .\) Find a. \(E\left(Y_{1}\right)\) and \(E\left(Y_{2}\right)\) $$\text { b. } V\left(Y_{1}\right) \text { and } V\left(Y_{2}\right)$$ d. \(E\left(Y_{1} Y_{1}\right)\) $$\text { d. } E\left(Y_{1} Y_{1}\right)$$ e. \(V\left(Y_{1}-Y_{2}\right) .\) Within what limits would you expect \(Y_{1}-Y_{2}\) to fall?

Suppose that the probability that a head appears when a coin is tossed is \(p\) and the probability that a tail occurs is \(q=1-p .\) Person A tosses the coin until the first head appears and stops. Person B does likewise. The results obtained by persons \(A\) and \(B\) are assumed to be independent. What is the probability that \(A\) and \(B\) stop on exactly the same number toss?

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