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Let \(Y_{1}\) and \(Y_{2}\) have a bivariate normal distribution. a. Show that the marginal distribution of \(Y_{1}\) is normal with mean \(\mu_{1}\) and variance \(\sigma_{1}^{2}\) b. What is the marginal distribution of \(Y_{2} ?\)

Short Answer

Expert verified
The marginal distributions are \(Y_1 \sim N(\mu_1, \sigma_1^2)\) and \(Y_2 \sim N(\mu_2, \sigma_2^2)\).

Step by step solution

01

Clarifying the Problem

We are given that \(Y_1\) and \(Y_2\) are jointly distributed as a bivariate normal distribution. We need to identify the marginal distributions for both \(Y_1\) and \(Y_2\).
02

Understanding Bivariate Normal Distribution

A bivariate normal distribution for \(Y_{1}\) and \(Y_{2}\) is characterized by the mean vector \(\mu = (\mu_1, \mu_2)^T\) and covariance matrix \(abla\) which is a 2x2 matrix given by: \[abla = \begin{pmatrix} \sigma_1^2 & \rho\sigma_1\sigma_2 \ \rho\sigma_1\sigma_2 & \sigma_2^2 \end{pmatrix}\] where \(\rho\) is the correlation coefficient.
03

Identifying Marginal Distribution of Y1

The property of the bivariate normal distribution states that any linear combination or subset of a bivariate normal random vector is normally distributed. Therefore, the marginal distribution of \(Y_1\), which is a component of the bivariate normal distribution, will be normal with mean \(\mu_1\) and variance \(\sigma_1^2\).
04

Writing the Marginal Distribution for Y1

The marginal distribution of \(Y_{1}\) is: \(Y_{1} \sim N(\mu_{1}, \sigma_{1}^2)\). This confirms that \(Y_1\) follows a normal distribution with the given parameters.
05

Identifying Marginal Distribution of Y2

Similarly, by the same property of the bivariate normal distribution, the marginal distribution of \(Y_2\), another component of the joint distribution, will be normal with mean \(\mu_2\) and variance \(\sigma_2^2\).
06

Writing the Final Marginal Distribution for Y2

The marginal distribution of \(Y_{2}\) is: \(Y_{2} \sim N(\mu_{2}, \sigma_{2}^2)\). This shows that \(Y_2\) follows a normal distribution with the given parameters.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Marginal Distribution
In a bivariate normal distribution, we focus not on the joint characteristics of two variables together, but rather on the characteristics of one variable at a time. The term "marginal distribution" refers to the probability distribution of a single random variable within a multivariate context.
When you have a bivariate normal distribution of variables \(Y_1\) and \(Y_2\), the marginal distribution of each variable is a normal distribution. This is because the properties of the bivariate normal distribution ensure that any individual component, or subset, will also be normally distributed.
Hence, the marginal distribution of \(Y_1\) is given by \(Y_1 \sim N(\mu_1, \sigma_1^2)\). Similarly, for \(Y_2\), the marginal distribution will be \(Y_2 \sim N(\mu_2, \sigma_2^2)\). This means:
  • Each variable is normally distributed as if it was independent, thanks to the bivariate structure.
  • We simply extract the mean and variance of one variable from the joint features.
Understanding marginal distribution helps in simplifying analyses of multivariate distributions by examining each variable on its own.
Covariance Matrix
The covariance matrix is a crucial aspect of any multivariate distribution, especially in a bivariate normal distribution. It reflects how two variables co-vary, essentially displaying the relationships among variables and encapsulating variance and covariance values.
For a bivariate normal distribution containing \(Y_1\) and \(Y_2\), the covariance matrix is a 2x2 matrix given by: \[\Sigma = \begin{pmatrix} \sigma_1^2 & \rho\sigma_1\sigma_2 \ \rho\sigma_1\sigma_2 & \sigma_2^2 \end{pmatrix}\]Here's what each element in the matrix represents:
  • \(\sigma_1^2\) is the variance of \(Y_1\).
  • \(\sigma_2^2\) is the variance of \(Y_2\).
  • \(\rho\sigma_1\sigma_2\) is the covariance between \(Y_1\) and \(Y_2\).
Covariance describes how two variables change together. Here, \(\rho\) is the correlation coefficient, converting covariance to a standardized measure of dependence that ranges between -1 and 1. Covariance is fundamental as it is central to estimating the overall variance in any linear combinations of the variables.
Understanding the covariance matrix is key to grasping the interdependencies within multivariate distributions.
Correlation Coefficient
The correlation coefficient is a key statistic in assessing the relationship between two random variables. Often denoted as \(\rho\), this metric quantifies the degree to which the variables are related in a linear sense.
The correlation coefficient is especially significant in the context of a bivariate normal distribution. It not only helps in understanding how two variables \(Y_1\) and \(Y_2\) interact, but it achieves this by normalizing their covariance. Thus, whereas covariance might reflect the degree of variability interdependence based on the scale of the variables, the correlation coefficient confines this metric to a fixed range:
  • \(\rho = 1\) indicates a perfect positive linear relationship.
  • \(\rho = -1\) indicates a perfect negative linear relationship.
  • \(\rho = 0\) suggests no linear relationship.
For \(Y_1\) and \(Y_2\), the correlation coefficient is found within the covariance matrix and has the formula: \(\rho = \frac{\text{Cov}(Y_1, Y_2)}{\sigma_1\sigma_2}\).
With correlation coefficients, we can gain intuitive and standardized insights into how closely two variables follow the same trends within a distribution.

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Most popular questions from this chapter

The lengths of life \(Y\) for a type of fuse has an exponential distribution with a density function given by $$f(y)=\left\\{\begin{array}{ll} (1 / \beta) e^{-y / \beta}, & y \geq 0 \\ 0, & \text { elsewhere } \end{array}\right.$$ a. If two such fuses have independent life lengths \(Y_{1}\) and \(Y_{2}\), find their joint probability density function. b. One fuse from part (a) is in a primary system, and the other is in a backup system that comes into use only if the primary system fails. The total effective life length of the two fuses. therefore, is \(Y_{1}+Y_{2} .\) Find \(P\left(Y_{1}+Y_{2} \leq a\right),\) where \(a>0\)

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Two friends are to meet at the library. Each independently and randomly selects an arrival time within the same one-hour period. Each agrees to wait a maximum of ten minutes for the other to arrive. What is the probability that they will meet?

The length of life \(Y\) for fuses of a certain type is modeled by the exponential distribution, with $$f(y)=\left\\{\begin{array}{ll}(1 / 3) e^{-y / 3}, & y>0 \\\0, & \text { elsewhere }\end{array}\right.$$ (The measurements are in hundreds of hours.) a. If two such fuses have independent lengths of life \(Y_{1}\) and \(Y_{2}\), find the joint probability density function for \(Y_{1}\) and \(Y_{2}\). b. One fuse in part (a) is in a primary system, and the other is in a backup system that comes into use only if the primary system fails. The total effective length of life of the two fuses is then \(Y_{1}+Y_{2} .\) Find \(P\left(Y_{1}+Y_{2} \leq 1\right)\).

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